Chapter 8
A Complete Resource Book in Chemistry for JEE Main · 221 exercises
Problem 59
pKa values of three acids \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) are \(4.3,3.3\) and 5.5 respectively. Which of the following represents the correct order of acid strength? (a) \(\mathrm{A}>\mathrm{B}>\mathrm{C}\) (b) \(\mathrm{C}>\mathrm{A}>\mathrm{B}\) (c) \(\mathrm{B}>\mathrm{A}>\mathrm{C}\) (d) \(C>B>A\)
4 step solution
Problem 60
Which of the following on reaction with \(\mathrm{H}_{2} \mathrm{~S}\) does not produce metallic sulphide? (a) \(\mathrm{CdCl}_{2}\) (b) \(\mathrm{ZnCl}_{2}\) (c) \(\mathrm{CoCl}_{2}^{2}\) (d) \(\mathrm{CuCl}_{2}^{2}\)
4 step solution
Problem 62
Which of the following statement is correct? 1\. The \(\mathrm{pH}\) of \(1.0 \times 10^{-8} \mathrm{M}\) solution of \(\mathrm{HCl}\) is 8 2\. The conjugate base of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)is \(\mathrm{HPO}_{4}^{2-}\) 3\. Autoprotolysis constant of water increases with temperature 4\. When a solution of a weak monoprotic acid is titrated against a strong base at half neutralization point, \(\mathrm{pH}=(1 / 2) \mathrm{pKa}\). (a) 2,3 (b) \(1,2,3\) (c) 3,4 (d) \(2,3,4\)
5 step solution
Problem 63
The solubility of \(\mathrm{A}_{2} \mathrm{X}_{3}\) is \(\mathrm{y} \mathrm{mol} \mathrm{dm}^{-3}\). Its solubility product is (a) \(6 y^{4}\) (b) \(64 \mathrm{y}^{4}\) (c) \(36 \mathrm{y}^{5}\) (d) \(108 \mathrm{y}^{5}\)
5 step solution
Problem 64
If pKb for fluoride ion at \(25^{\circ} \mathrm{C}\) is \(10.83\), the ionization constant of hydrofluoric acid at this temperature is (a) \(1.74 \times 10^{-5}\) (b) \(3.52 \times 10^{-3}\) (c) \(6.75 \times 10^{-4}\) (d) \(5.38 \times 10^{-2}\)
4 step solution
Problem 65
The pKa pf HCN is \(9.30 .\) The \(\mathrm{pH}\) of a solution prepared by mixing \(2.5\) moles of \(\mathrm{KCN}\) and \(2.5\) moles of HCN in water and making up the total volume to \(500 \mathrm{ml}\) is (a) \(9.30\) (b) \(8.30\) (c) \(7.30\) (d) \(10.30\)
4 step solution
Problem 66
What is the decreasing order of strength of the bases? \(\mathrm{OH}^{-}, \mathrm{NH}_{2}^{-}, \mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}\)and \(\mathrm{CH}_{3}-\mathrm{CH}_{2}^{-2}\) (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}^{-},>\mathrm{NH}_{2}^{-}>\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}>\mathrm{OH}^{-}\) (b) \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}>\mathrm{CH}_{3}-\mathrm{CH}_{2}^{->} \mathrm{NH}_{2}^{->} \mathrm{OH}^{-}\) (c) \(\mathrm{OH}^{->} \mathrm{NH}_{2}^{->} \mathrm{H}-\mathrm{C} \equiv \mathrm{C}->\mathrm{CH}_{3}-\mathrm{CH}_{2}-\) (d) \(\mathrm{NH}_{2}^{-}>\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}>\mathrm{OH}^{->} \mathrm{CH}_{3}-\mathrm{CH}_{2}^{-}\)
4 step solution
Problem 67
The following equilibrium is established when hydrogen chloride is dissolved in acetic acid. \(\mathrm{HCl}+\mathrm{CH}_{3} \mathrm{COOH} \leftrightarrow \mathrm{Cl}^{-}+\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}\) The set that characterizes the conjugate acid base pair is (a) \(\left(\mathrm{HCl}, \mathrm{CH}_{3} \mathrm{COOH}\right)\) and \(\left(\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}, \mathrm{Cl}^{-}\right)\) (b) \(\left(\mathrm{HCl}, \mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}\right)\)and \(\left(\mathrm{HCl}, \mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}\right)\)and \(\left(\mathrm{CH}_{3} \mathrm{COOH}, \mathrm{Cl}^{-}\right)\) (c) \(\left(\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}, \mathrm{HCl}\right)\) and \(\left(\mathrm{Cl}^{-}, \mathrm{CH}_{3} \mathrm{COOH}\right)\) (d) \(\left(\mathrm{HCl}, \mathrm{Cl}^{-}\right)\)and \(\left(\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}, \mathrm{CH}_{3} \mathrm{COOH}\right)\)
4 step solution
Problem 68
The pKa of acetyl salicylic acid (aspirin) is \(3.5 .\) The \(\mathrm{pH}\) of gastric juice in human stomach is about \(2-3\) and \(\mathrm{pH}\) in the small intestine is about 8 . Aspirin will be (a) ionized in the small intestine and almost unionized in the stomach (b) unionized in the small intestine and in the stomach (c) completely ionized in the small intestine and in the stomach (d) ionized in the stomach and almost unionized in the small intestine.
4 step solution
Problem 69
An example of a reversible reaction is (a) \(\mathrm{KNO}_{3}(\mathrm{aq})+\mathrm{NaCl}(\mathrm{aq})=\mathrm{KCl}(\mathrm{aq})+\mathrm{NaNO}_{3}(\mathrm{aq})\) (b) \(2 \mathrm{Na}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(1)=2 \mathrm{NaOH}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{~g})\) (c) \(\mathrm{AgNO}_{3}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq})=\mathrm{AgCl}(\mathrm{s})+\mathrm{NaNO}_{3}\) (aq) (d) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{NaI}(\mathrm{aq})=\mathrm{PbI}_{2}(\mathrm{~s})+2 \mathrm{NaNO}_{3}(\mathrm{aq})\)
6 step solution
Problem 71
A certain buffer solution contains equal concentration of \(\mathrm{X}^{-}\)and \(\mathrm{HX}\). The \(\mathrm{Kp}\) for \(\mathrm{X}^{-}\)is \(10^{-10} .\) The \(\mathrm{pH}\) of the buffer is (a) 6 (b) 10 (c) 4 (d) 14
4 step solution
Problem 72
The precipitate of \(\mathrm{CaF}_{2}\left(\mathrm{Ksp}=1.7 \times 10^{-10}\right)\) is obtained when equal volumes of the following are mixed (a) \(10^{-2} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{MF}^{-}\) (b) \(10^{-3} \mathrm{M} \mathrm{Ca}^{2+}+10^{-5} \mathrm{MF}^{-}\) (c) \(10^{-4} \mathrm{M} \mathrm{Ca}^{2+}+10^{-4} \mathrm{MF}^{-}\) (d) \(10^{-5} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{MF}^{-}\)
5 step solution
Problem 73
The oxidation of \(\mathrm{SO}_{2}\) by \(\mathrm{O}_{2}\) to \(\mathrm{SO}_{3}\) is an exothermic reaction. They yield of \(\mathrm{SO}_{3}\) will be maximum if (a) temperature is reduced and pressure is increased (b) temperature is increased and pressure is kept constant (c) both temperature and pressure are reduced (d) both temperature and pressure are increased
4 step solution
Problem 74
Solution of \(0.1 \mathrm{~N} \mathrm{NH}_{4} \mathrm{OH}\) and \(0.1 \mathrm{~N} \mathrm{NH}_{4} \mathrm{Cl}\) has \(\mathrm{pH}\) 9.25, then find out \(\mathrm{pKb}\) of \(\mathrm{NH}_{4} \mathrm{OH}\) (a) \(9.25\) (b) \(4.75\) (c) \(3.75\) (d) \(8.25\)
3 step solution
Problem 75
Which has highest \(\mathrm{pH} ?\) (a) \(\mathrm{CH}_{3} \mathrm{COOK}\) (b) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (c) \(\mathrm{NH}_{4} \mathrm{Cl}\) (d) \(\mathrm{NaNO}_{3}\)
3 step solution
Problem 77
The hydrogen ion concentration of a \(10^{-8} \mathrm{M} \mathrm{HCl}\) aqueous solution at \(298 \mathrm{~K}\left(\mathrm{Kw}=10^{-14}\right)\) is (a) \(9.525 \times 10^{-8} \mathrm{M}\) (b) \(1.0 \times 10^{-8} \mathrm{M}\) (c) \(1.0 \times 10^{-6} \mathrm{M}\) (d) \(1.0525 \times 10^{-7} \mathrm{M}\)
5 step solution
Problem 78
Solubility of a \(\mathrm{M}_{2} \mathrm{~S}\) salt is \(3.5 \times 10^{-6}\) then find out solubility product. (a) \(1.7 \times 10^{-6}\) (b) \(1.7 \times 10^{-16}\) (c) \(1.7 \times 10^{-18}\) (d) \(1.7 \times 10^{-12}\)
5 step solution
Problem 79
Solubility of \(\mathrm{MX}_{2}\) type electrolyte is \(0.5 \times 10^{-4} \mathrm{~mol}\) \(\mathrm{L}^{-1}\). Then find out Ksp of electrolytes. (a) \(5 \times 10^{-12}\) (b) \(25 \times 10^{-10}\) (c) \(1 \times 10^{-13}\) (d) \(5 \times 10^{-13}\)
5 step solution
Problem 80
The solubility product of a sparingly soluble salt \(\mathrm{AX}_{2}\) is \(3.2 \times 10^{-11} .\) Its solubility (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) is (a) \(5.6 \times 10^{-6}\) (b) \(3.1 \times 10^{-4}\) (c) \(2 \times 10^{-4}\) (d) \(4 \times 10^{-4}\)
6 step solution
Problem 83
pKa value of four acids are given below. The strongest acid is (I) \(4.0\) (II) \(3.5\) (III) \(2.5\) (IV) 2 (a) I (b) II (c) III (d) IV
3 step solution
Problem 84
A solution has hydrogen ion concentration \(0.0005 \mathrm{M}\), its \(\mathrm{pOH}\) is (a) \(8.2798\) (b) \(10.6990\) (c) \(12.7854\) (d) \(13.3344\)
4 step solution
Problem 85
At \(25^{\circ} \mathrm{C}\) the \(\mathrm{pH}\) of solution containing \(0.10 \mathrm{M}\) sodium acetate and \(0.03 \mathrm{M}\) acetic acid is [pKa value of \(\left.\mathrm{CH}_{3} \mathrm{COOH}=4.57\right]\) (a) \(3.24\) (b) \(4.59\) (c) \(5.09\) (d) \(6.67\)
6 step solution
Problem 86
At \(80^{\circ} \mathrm{C}\), distilled water \(\left(\mathrm{H}_{3} \mathrm{O}^{+}\right)\)concentration is equal to \(1 \times 10^{-6}\) mol/litre. At the same temperature the value of \(\mathrm{Kw}\) is (a) \(1 \times 10^{-3}\) (b) \(1 \times 10^{-6}\) (c) \(1 \times 10^{-4}\) (d) \(1 \times 10^{-12}\)
5 step solution
Problem 87
When \(10 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) acetic acid \((\mathrm{pKa}=5.0)\) is titrated against \(10 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) ammonia solution \((\mathrm{pKb}=5.0\) ) the equivalence point occurs at \(\mathrm{pH}\) (a) \(5.0\) (b) \(6.0\) (c) \(9.0\) (d) \(7.0\)
5 step solution
Problem 89
The solubility of \(\mathrm{AgCl}\) in \(0.2 \mathrm{M} \mathrm{NaCl}\) is \([\mathrm{Ksp} \mathrm{AgCl}=\) \(\left.1.8 \times 10^{-10}\right]\) (a) \(1.8 \times 10^{-11} \mathrm{M}\) (b) \(9 \times 10^{-10} \mathrm{M}\) (c) \(6.5 \times 10^{-12} \mathrm{M}\) (d) \(5.6 \times 10^{-11} \mathrm{M}\)
5 step solution
Problem 90
Ionization constant of acetic acid is \(1.8 \times 10^{-5}\). The concentration of \(\mathrm{H}^{+}\)ions in \(0.1 \mathrm{M}\) solution is (a) \(1.8 \times 10^{-3} \mathrm{M}\) (b) \(1.8 \times 10^{-5} \mathrm{M}\) (c) \(1.3 \times 10^{-3} \mathrm{M}\) (d) \(1.34 \times 10^{-3} \mathrm{M}\)
3 step solution
Problem 91
The dissociation constant of a weak acid is \(4.9 \times 10^{-8}\), its percentage ionization at \(0.1 \mathrm{M}\) is (a) \(0.07 \%\) (b) \(0.007 \%\) (c) \(0.7 \%\) (d) \(0.0007 \%\)
7 step solution
Problem 92
The pKa of a weak acid is \(4.8\). What should be the ratio of \([\) acid \(] /[\mathrm{salt}]\), if a buffer of \(\mathrm{pH}=5.8\) is required? (a) \(0.1\) (b) 10 (c) 1 (d) 2
5 step solution
Problem 93
The \(\mathrm{pH}\) of a \(0.1 \mathrm{M}\) aqueous solution of a weak acid (HA) is \(3 .\) What is its degree of dissociation? (a) \(1 \%\) (b) \(10 \%\) (c) \(50 \%\) (d) \(25 \%\)
5 step solution
Problem 95
\(75 \mathrm{ml}\) of \(0.2 \mathrm{M} \mathrm{HCl}\) is mixed with \(25 \mathrm{ml}\) of \(\mathrm{M} \mathrm{HCl}\). To this solution, \(300 \mathrm{ml}\) of distilled water is added. What is the \(\mathrm{pH}\) of the resultant solution? (a) 1 (b) 2 (c) 4 (d) \(0.2\)
6 step solution
Problem 96
The dissociation constant of two acids \(\mathrm{HA}_{1}\) and \(\mathrm{HA}_{2}\) are \(3.0 \times 10^{-4}\) and \(1.8 \times 10^{-5}\) respectively. The relative strengths of the acids is (a) \(1: 16\) (b) \(1: 4\) (c) \(4: 1\) (d) \(16: 1\)
5 step solution
Problem 98
\(0.005 \mathrm{M}\) acid solution has \(5 \mathrm{pH}\). The percentage ionization of acid is (a) \(0.8 \%\) (b) \(0.6 \%\) (c) \(0.4 \%\) (d) \(0.2 \%\)
3 step solution
Problem 99
\(100 \mathrm{ml}\) of \(0.015 \mathrm{M} \mathrm{HCl}\) solution is mixed with 100 \(\mathrm{ml}\) of \(0.005 \mathrm{M} \mathrm{HCl}\). What is the \(\mathrm{pH}\) of the resultant solution? (a) \(2.5\) (b) \(1.5\) (c) 2 (d) 1
6 step solution
Problem 100
The solubility product of \(\mathrm{A}_{2} \mathrm{X}_{3}\) is \(1.08 \times 10^{-23} .\) Its solubility will be (a) \(1.0 \times 10^{-3} \mathrm{M}\) (b) \(1.0 \times 10^{-4} \mathrm{M}\) (c) \(1.0 \times 10^{-5} \mathrm{M}\) (d) \(1.0 \times 10^{-6} \mathrm{M}\)
7 step solution
Problem 101
\(\mathrm{M}(\mathrm{OH}) \mathrm{x}\) has \(\mathrm{Ksp}=4 \times 10^{-12}\) and solubility \(10^{-4} \mathrm{M}, \mathrm{x}\) is (a) 1 (b) 2 (c) 3 (d) 4
6 step solution
Problem 102
The \(\mathrm{pH}\) values of \(1 \mathrm{M}\) solutions of \(\mathrm{CH}_{3} \mathrm{COOH}\) (I), \(\mathrm{CH}_{3}, \mathrm{COONa}\) (II), \(\mathrm{CH}_{3} \mathrm{COONH}_{4}(\mathrm{III})\), and \(\mathrm{KOH}\) (IV) will be in the order (a) IV>III > II > I (b) \(I V>I I>I I I>I\) (c) \(\mathrm{I}>\mathrm{III}>\mathrm{II}>\mathrm{IV}\) (d) \(\mathrm{II}>\mathrm{I}>\mathrm{III}>\mathrm{IV}\)
3 step solution
Problem 103
For preparing a buffer solution of \(\mathrm{pH} 6\) by mixing sodium acetate and acetic acid, the ratio of the concentration of salt and acid should be \(\left(\mathrm{Ka}=10^{-5}\right)\) (a) \(1: 10\) (b) \(10: 1\) (c) \(100: 1\) (d) \(1: 100\)
5 step solution
Problem 106
The decreasing order of acidic nature of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (I), \(\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{II})\), and \(\mathrm{HClO}_{4}(\mathrm{III})\) is (a) \(\mathrm{I}>\mathrm{II}>\mathrm{III}\) (b) \(\mathrm{I}>\mathrm{III}>\mathrm{II}\) (c) \(\mathrm{III}>\mathrm{I}>\mathrm{II}\) (d) \(\mathrm{III}>\mathrm{II}>\mathrm{I}\)
5 step solution
Problem 107
The number of \(\mathrm{H}^{+}\)ions present in \(1 \mathrm{~cm}^{3}\) of a solution whose \(\mathrm{pH}\) is 10 is (a) \(10^{-10}\) (b) \(10^{-13}\) (c) \(6.02 \times 10^{10}\) (d) \(6.02 \times 10^{13}\)
4 step solution
Problem 108
The Ka value of formic acid and acetic acid are respectively \(1.77 \times 10^{-4}\) and \(1.75 \times 10^{-5}\). the ratio of the acid strength of \(0.1 \mathrm{~N}\) acids is (a) \(0.1\) (b) \(0.3\) (c) \(3.178\) (d) 100
5 step solution
Problem 109
If \(0.1 \mathrm{M}\) of a weak monobasic acid is taken and its percentage degree of ionization is \(1.34 \%\), then calculate its ionization constant (a) \(0.8 \times 10^{-5}\) (b) \(1.79 \times 10^{-5}\) (c) \(0.182 \times 19^{-5}\) (d) none of these
7 step solution
Problem 110
A weak monobasic acid is half neutralized by a strong base. If the \(\mathrm{pH}\) of the solution is \(5.4\), its pKa is (a) \(6.8\) (b) \(2.7\) (c) \(5.4\) (d) \(10.8\)
3 step solution
Problem 111
The solubility of \(\mathrm{AgCl}\) in moles per litre when its solubility product is \(1.56 \times 10^{-10}\) at \(25^{\circ} \mathrm{C}\) is (a) \(0.576 \times 10^{-8} \mathrm{~mol} /\) litre (b) \(1.056 \times 10^{-4} \mathrm{~mol} /\) litre (c) \(1.249 \times 10^{-5} \mathrm{~mol} /\) litre (d) \(1.478 \times 10^{-6} \mathrm{~mol} /\) litre
5 step solution
Problem 112
If the solubility of sodium hexafluoroaluminate is 'a' mol/litre, its solubility product is (a) \(\mathrm{a}^{8}\) (b) \(27 \mathrm{a}^{4}\) (c) \(180 \mathrm{a}^{3}\) (d) \(2916 \mathrm{a}^{8}\)
5 step solution
Problem 113
If the solubility of \(\mathrm{BaSO}_{4}\) (mol wt. 233) is \(2.33 \times 10^{-4}\) \(\mathrm{g} / 100 \mathrm{~mL}\) then the solubility product of \(\mathrm{BaSO}_{4}\) is (a) \(1 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1}\) (b) \(1 \times 10^{-10} \mathrm{~mol} \mathrm{~L}^{-1}\) (c) \(1 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}\) (d) \(1 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1}\)
6 step solution
Problem 114
The solubility product of calcium fluoride is \(3.2 \times\) \(10^{-11} \mathrm{M}^{3}\). Its solubility in saturated solution is (a) \(8 \times 10^{-12} \mathrm{M}\) (b) \(2 \times 10^{-4} \mathrm{M}\) (c) \(4 \times 10^{-12} \mathrm{M}\) (d) \(1 \times 10^{-4} \mathrm{M}\)
6 step solution
Problem 115
Equal volumes of the following \(\mathrm{Ca}^{2+}\) and \(\mathrm{F}^{-}\)solutions are mixed. In which of the solutions will precipitation occurs? \(\left[\mathrm{Ksp}\right.\) of \(\left.\mathrm{CaF}_{2}=1.7 \times 10^{-10}\right]\) 1\. \(10^{-2} \mathrm{M} \mathrm{Ca}^{2+}+10^{-5} \mathrm{M} \mathrm{F}^{-}\) 2\. \(10^{-3} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{M} \mathrm{F}^{-}\) 3\. \(10^{-4} \mathrm{M} \mathrm{Ca}^{2+}+10^{-2} \mathrm{M} \mathrm{F}^{-}\) 4\. \(10^{-2} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{M} \mathrm{F}^{-}\) Select the correct answer using the codes given below: (a) in 4 only (b) in 1 and 2 (c) in 3 and 4 (d) in 2,3 and 4
6 step solution
Problem 118
Consider of following acids: 1\. HCN 4\. HCOOH 3\. \(\mathrm{CH}_{3} \mathrm{COOH}\) 5\. \(\mathrm{Cl}-\mathrm{CH}_{2} \mathrm{COOH}\) Correct order of acid strength is (a) \(2>3>1>4\) (b) \(4>2>3>1\) (c) \(4>3>2>1\) (d) \(3>2>4>1\)
4 step solution
Problem 120
The \(\mathrm{pH}\) of solution made by mixing \(50 \mathrm{~mL}\) of \(0.01 \mathrm{M}\) barium hydroxide solution with \(50 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) is (a) \(3.0\) (b) \(6.0\) (c) \(12.0\) (d) \(15.0\)
5 step solution
Problem 121
Find the molar solubility of \(\mathrm{Fe}(\mathrm{OH})_{3}\) in a buffer solution that \(0.10 \mathrm{M}\) in \(\mathrm{NH}_{4} \mathrm{Cl}\) and \(0.10 \mathrm{M}\) in \(\mathrm{NH}_{3} .\) If \(\mathrm{K}_{\mathrm{b}}\) \(\left(\mathrm{NH}_{3}\right)=1.8 \times 10^{-5}\) and \(\mathrm{Ksp}\left[\mathrm{Fe}(\mathrm{OH})_{3}\right]=2.6 \times 10^{-39}\) (a) \(4.458 \times 10^{-25} \mathrm{M}\) (b) \(3.458 \times 10^{-25} \mathrm{M}\) (c) \(2.229 \times 10^{-24} \mathrm{M}\) (d) \(4.458 \times 10^{-22} \mathrm{M}\)
5 step solution