Chapter 8

A Complete Resource Book in Chemistry for JEE Main · 221 exercises

Problem 59

pKa values of three acids \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) are \(4.3,3.3\) and 5.5 respectively. Which of the following represents the correct order of acid strength? (a) \(\mathrm{A}>\mathrm{B}>\mathrm{C}\) (b) \(\mathrm{C}>\mathrm{A}>\mathrm{B}\) (c) \(\mathrm{B}>\mathrm{A}>\mathrm{C}\) (d) \(C>B>A\)

4 step solution

Problem 60

Which of the following on reaction with \(\mathrm{H}_{2} \mathrm{~S}\) does not produce metallic sulphide? (a) \(\mathrm{CdCl}_{2}\) (b) \(\mathrm{ZnCl}_{2}\) (c) \(\mathrm{CoCl}_{2}^{2}\) (d) \(\mathrm{CuCl}_{2}^{2}\)

4 step solution

Problem 62

Which of the following statement is correct? 1\. The \(\mathrm{pH}\) of \(1.0 \times 10^{-8} \mathrm{M}\) solution of \(\mathrm{HCl}\) is 8 2\. The conjugate base of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)is \(\mathrm{HPO}_{4}^{2-}\) 3\. Autoprotolysis constant of water increases with temperature 4\. When a solution of a weak monoprotic acid is titrated against a strong base at half neutralization point, \(\mathrm{pH}=(1 / 2) \mathrm{pKa}\). (a) 2,3 (b) \(1,2,3\) (c) 3,4 (d) \(2,3,4\)

5 step solution

Problem 63

The solubility of \(\mathrm{A}_{2} \mathrm{X}_{3}\) is \(\mathrm{y} \mathrm{mol} \mathrm{dm}^{-3}\). Its solubility product is (a) \(6 y^{4}\) (b) \(64 \mathrm{y}^{4}\) (c) \(36 \mathrm{y}^{5}\) (d) \(108 \mathrm{y}^{5}\)

5 step solution

Problem 64

If pKb for fluoride ion at \(25^{\circ} \mathrm{C}\) is \(10.83\), the ionization constant of hydrofluoric acid at this temperature is (a) \(1.74 \times 10^{-5}\) (b) \(3.52 \times 10^{-3}\) (c) \(6.75 \times 10^{-4}\) (d) \(5.38 \times 10^{-2}\)

4 step solution

Problem 65

The pKa pf HCN is \(9.30 .\) The \(\mathrm{pH}\) of a solution prepared by mixing \(2.5\) moles of \(\mathrm{KCN}\) and \(2.5\) moles of HCN in water and making up the total volume to \(500 \mathrm{ml}\) is (a) \(9.30\) (b) \(8.30\) (c) \(7.30\) (d) \(10.30\)

4 step solution

Problem 66

What is the decreasing order of strength of the bases? \(\mathrm{OH}^{-}, \mathrm{NH}_{2}^{-}, \mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}\)and \(\mathrm{CH}_{3}-\mathrm{CH}_{2}^{-2}\) (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}^{-},>\mathrm{NH}_{2}^{-}>\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}>\mathrm{OH}^{-}\) (b) \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}>\mathrm{CH}_{3}-\mathrm{CH}_{2}^{->} \mathrm{NH}_{2}^{->} \mathrm{OH}^{-}\) (c) \(\mathrm{OH}^{->} \mathrm{NH}_{2}^{->} \mathrm{H}-\mathrm{C} \equiv \mathrm{C}->\mathrm{CH}_{3}-\mathrm{CH}_{2}-\) (d) \(\mathrm{NH}_{2}^{-}>\mathrm{H}-\mathrm{C} \equiv \mathrm{C}^{-}>\mathrm{OH}^{->} \mathrm{CH}_{3}-\mathrm{CH}_{2}^{-}\)

4 step solution

Problem 67

The following equilibrium is established when hydrogen chloride is dissolved in acetic acid. \(\mathrm{HCl}+\mathrm{CH}_{3} \mathrm{COOH} \leftrightarrow \mathrm{Cl}^{-}+\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}\) The set that characterizes the conjugate acid base pair is (a) \(\left(\mathrm{HCl}, \mathrm{CH}_{3} \mathrm{COOH}\right)\) and \(\left(\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}, \mathrm{Cl}^{-}\right)\) (b) \(\left(\mathrm{HCl}, \mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}\right)\)and \(\left(\mathrm{HCl}, \mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}\right)\)and \(\left(\mathrm{CH}_{3} \mathrm{COOH}, \mathrm{Cl}^{-}\right)\) (c) \(\left(\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}, \mathrm{HCl}\right)\) and \(\left(\mathrm{Cl}^{-}, \mathrm{CH}_{3} \mathrm{COOH}\right)\) (d) \(\left(\mathrm{HCl}, \mathrm{Cl}^{-}\right)\)and \(\left(\mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}, \mathrm{CH}_{3} \mathrm{COOH}\right)\)

4 step solution

Problem 68

The pKa of acetyl salicylic acid (aspirin) is \(3.5 .\) The \(\mathrm{pH}\) of gastric juice in human stomach is about \(2-3\) and \(\mathrm{pH}\) in the small intestine is about 8 . Aspirin will be (a) ionized in the small intestine and almost unionized in the stomach (b) unionized in the small intestine and in the stomach (c) completely ionized in the small intestine and in the stomach (d) ionized in the stomach and almost unionized in the small intestine.

4 step solution

Problem 69

An example of a reversible reaction is (a) \(\mathrm{KNO}_{3}(\mathrm{aq})+\mathrm{NaCl}(\mathrm{aq})=\mathrm{KCl}(\mathrm{aq})+\mathrm{NaNO}_{3}(\mathrm{aq})\) (b) \(2 \mathrm{Na}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(1)=2 \mathrm{NaOH}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{~g})\) (c) \(\mathrm{AgNO}_{3}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq})=\mathrm{AgCl}(\mathrm{s})+\mathrm{NaNO}_{3}\) (aq) (d) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{NaI}(\mathrm{aq})=\mathrm{PbI}_{2}(\mathrm{~s})+2 \mathrm{NaNO}_{3}(\mathrm{aq})\)

6 step solution

Problem 71

A certain buffer solution contains equal concentration of \(\mathrm{X}^{-}\)and \(\mathrm{HX}\). The \(\mathrm{Kp}\) for \(\mathrm{X}^{-}\)is \(10^{-10} .\) The \(\mathrm{pH}\) of the buffer is (a) 6 (b) 10 (c) 4 (d) 14

4 step solution

Problem 72

The precipitate of \(\mathrm{CaF}_{2}\left(\mathrm{Ksp}=1.7 \times 10^{-10}\right)\) is obtained when equal volumes of the following are mixed (a) \(10^{-2} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{MF}^{-}\) (b) \(10^{-3} \mathrm{M} \mathrm{Ca}^{2+}+10^{-5} \mathrm{MF}^{-}\) (c) \(10^{-4} \mathrm{M} \mathrm{Ca}^{2+}+10^{-4} \mathrm{MF}^{-}\) (d) \(10^{-5} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{MF}^{-}\)

5 step solution

Problem 73

The oxidation of \(\mathrm{SO}_{2}\) by \(\mathrm{O}_{2}\) to \(\mathrm{SO}_{3}\) is an exothermic reaction. They yield of \(\mathrm{SO}_{3}\) will be maximum if (a) temperature is reduced and pressure is increased (b) temperature is increased and pressure is kept constant (c) both temperature and pressure are reduced (d) both temperature and pressure are increased

4 step solution

Problem 74

Solution of \(0.1 \mathrm{~N} \mathrm{NH}_{4} \mathrm{OH}\) and \(0.1 \mathrm{~N} \mathrm{NH}_{4} \mathrm{Cl}\) has \(\mathrm{pH}\) 9.25, then find out \(\mathrm{pKb}\) of \(\mathrm{NH}_{4} \mathrm{OH}\) (a) \(9.25\) (b) \(4.75\) (c) \(3.75\) (d) \(8.25\)

3 step solution

Problem 75

Which has highest \(\mathrm{pH} ?\) (a) \(\mathrm{CH}_{3} \mathrm{COOK}\) (b) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (c) \(\mathrm{NH}_{4} \mathrm{Cl}\) (d) \(\mathrm{NaNO}_{3}\)

3 step solution

Problem 77

The hydrogen ion concentration of a \(10^{-8} \mathrm{M} \mathrm{HCl}\) aqueous solution at \(298 \mathrm{~K}\left(\mathrm{Kw}=10^{-14}\right)\) is (a) \(9.525 \times 10^{-8} \mathrm{M}\) (b) \(1.0 \times 10^{-8} \mathrm{M}\) (c) \(1.0 \times 10^{-6} \mathrm{M}\) (d) \(1.0525 \times 10^{-7} \mathrm{M}\)

5 step solution

Problem 78

Solubility of a \(\mathrm{M}_{2} \mathrm{~S}\) salt is \(3.5 \times 10^{-6}\) then find out solubility product. (a) \(1.7 \times 10^{-6}\) (b) \(1.7 \times 10^{-16}\) (c) \(1.7 \times 10^{-18}\) (d) \(1.7 \times 10^{-12}\)

5 step solution

Problem 79

Solubility of \(\mathrm{MX}_{2}\) type electrolyte is \(0.5 \times 10^{-4} \mathrm{~mol}\) \(\mathrm{L}^{-1}\). Then find out Ksp of electrolytes. (a) \(5 \times 10^{-12}\) (b) \(25 \times 10^{-10}\) (c) \(1 \times 10^{-13}\) (d) \(5 \times 10^{-13}\)

5 step solution

Problem 80

The solubility product of a sparingly soluble salt \(\mathrm{AX}_{2}\) is \(3.2 \times 10^{-11} .\) Its solubility (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) is (a) \(5.6 \times 10^{-6}\) (b) \(3.1 \times 10^{-4}\) (c) \(2 \times 10^{-4}\) (d) \(4 \times 10^{-4}\)

6 step solution

Problem 83

pKa value of four acids are given below. The strongest acid is (I) \(4.0\) (II) \(3.5\) (III) \(2.5\) (IV) 2 (a) I (b) II (c) III (d) IV

3 step solution

Problem 84

A solution has hydrogen ion concentration \(0.0005 \mathrm{M}\), its \(\mathrm{pOH}\) is (a) \(8.2798\) (b) \(10.6990\) (c) \(12.7854\) (d) \(13.3344\)

4 step solution

Problem 85

At \(25^{\circ} \mathrm{C}\) the \(\mathrm{pH}\) of solution containing \(0.10 \mathrm{M}\) sodium acetate and \(0.03 \mathrm{M}\) acetic acid is [pKa value of \(\left.\mathrm{CH}_{3} \mathrm{COOH}=4.57\right]\) (a) \(3.24\) (b) \(4.59\) (c) \(5.09\) (d) \(6.67\)

6 step solution

Problem 86

At \(80^{\circ} \mathrm{C}\), distilled water \(\left(\mathrm{H}_{3} \mathrm{O}^{+}\right)\)concentration is equal to \(1 \times 10^{-6}\) mol/litre. At the same temperature the value of \(\mathrm{Kw}\) is (a) \(1 \times 10^{-3}\) (b) \(1 \times 10^{-6}\) (c) \(1 \times 10^{-4}\) (d) \(1 \times 10^{-12}\)

5 step solution

Problem 87

When \(10 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) acetic acid \((\mathrm{pKa}=5.0)\) is titrated against \(10 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) ammonia solution \((\mathrm{pKb}=5.0\) ) the equivalence point occurs at \(\mathrm{pH}\) (a) \(5.0\) (b) \(6.0\) (c) \(9.0\) (d) \(7.0\)

5 step solution

Problem 89

The solubility of \(\mathrm{AgCl}\) in \(0.2 \mathrm{M} \mathrm{NaCl}\) is \([\mathrm{Ksp} \mathrm{AgCl}=\) \(\left.1.8 \times 10^{-10}\right]\) (a) \(1.8 \times 10^{-11} \mathrm{M}\) (b) \(9 \times 10^{-10} \mathrm{M}\) (c) \(6.5 \times 10^{-12} \mathrm{M}\) (d) \(5.6 \times 10^{-11} \mathrm{M}\)

5 step solution

Problem 90

Ionization constant of acetic acid is \(1.8 \times 10^{-5}\). The concentration of \(\mathrm{H}^{+}\)ions in \(0.1 \mathrm{M}\) solution is (a) \(1.8 \times 10^{-3} \mathrm{M}\) (b) \(1.8 \times 10^{-5} \mathrm{M}\) (c) \(1.3 \times 10^{-3} \mathrm{M}\) (d) \(1.34 \times 10^{-3} \mathrm{M}\)

3 step solution

Problem 91

The dissociation constant of a weak acid is \(4.9 \times 10^{-8}\), its percentage ionization at \(0.1 \mathrm{M}\) is (a) \(0.07 \%\) (b) \(0.007 \%\) (c) \(0.7 \%\) (d) \(0.0007 \%\)

7 step solution

Problem 92

The pKa of a weak acid is \(4.8\). What should be the ratio of \([\) acid \(] /[\mathrm{salt}]\), if a buffer of \(\mathrm{pH}=5.8\) is required? (a) \(0.1\) (b) 10 (c) 1 (d) 2

5 step solution

Problem 93

The \(\mathrm{pH}\) of a \(0.1 \mathrm{M}\) aqueous solution of a weak acid (HA) is \(3 .\) What is its degree of dissociation? (a) \(1 \%\) (b) \(10 \%\) (c) \(50 \%\) (d) \(25 \%\)

5 step solution

Problem 95

\(75 \mathrm{ml}\) of \(0.2 \mathrm{M} \mathrm{HCl}\) is mixed with \(25 \mathrm{ml}\) of \(\mathrm{M} \mathrm{HCl}\). To this solution, \(300 \mathrm{ml}\) of distilled water is added. What is the \(\mathrm{pH}\) of the resultant solution? (a) 1 (b) 2 (c) 4 (d) \(0.2\)

6 step solution

Problem 96

The dissociation constant of two acids \(\mathrm{HA}_{1}\) and \(\mathrm{HA}_{2}\) are \(3.0 \times 10^{-4}\) and \(1.8 \times 10^{-5}\) respectively. The relative strengths of the acids is (a) \(1: 16\) (b) \(1: 4\) (c) \(4: 1\) (d) \(16: 1\)

5 step solution

Problem 98

\(0.005 \mathrm{M}\) acid solution has \(5 \mathrm{pH}\). The percentage ionization of acid is (a) \(0.8 \%\) (b) \(0.6 \%\) (c) \(0.4 \%\) (d) \(0.2 \%\)

3 step solution

Problem 99

\(100 \mathrm{ml}\) of \(0.015 \mathrm{M} \mathrm{HCl}\) solution is mixed with 100 \(\mathrm{ml}\) of \(0.005 \mathrm{M} \mathrm{HCl}\). What is the \(\mathrm{pH}\) of the resultant solution? (a) \(2.5\) (b) \(1.5\) (c) 2 (d) 1

6 step solution

Problem 100

The solubility product of \(\mathrm{A}_{2} \mathrm{X}_{3}\) is \(1.08 \times 10^{-23} .\) Its solubility will be (a) \(1.0 \times 10^{-3} \mathrm{M}\) (b) \(1.0 \times 10^{-4} \mathrm{M}\) (c) \(1.0 \times 10^{-5} \mathrm{M}\) (d) \(1.0 \times 10^{-6} \mathrm{M}\)

7 step solution

Problem 101

\(\mathrm{M}(\mathrm{OH}) \mathrm{x}\) has \(\mathrm{Ksp}=4 \times 10^{-12}\) and solubility \(10^{-4} \mathrm{M}, \mathrm{x}\) is (a) 1 (b) 2 (c) 3 (d) 4

6 step solution

Problem 102

The \(\mathrm{pH}\) values of \(1 \mathrm{M}\) solutions of \(\mathrm{CH}_{3} \mathrm{COOH}\) (I), \(\mathrm{CH}_{3}, \mathrm{COONa}\) (II), \(\mathrm{CH}_{3} \mathrm{COONH}_{4}(\mathrm{III})\), and \(\mathrm{KOH}\) (IV) will be in the order (a) IV>III > II > I (b) \(I V>I I>I I I>I\) (c) \(\mathrm{I}>\mathrm{III}>\mathrm{II}>\mathrm{IV}\) (d) \(\mathrm{II}>\mathrm{I}>\mathrm{III}>\mathrm{IV}\)

3 step solution

Problem 103

For preparing a buffer solution of \(\mathrm{pH} 6\) by mixing sodium acetate and acetic acid, the ratio of the concentration of salt and acid should be \(\left(\mathrm{Ka}=10^{-5}\right)\) (a) \(1: 10\) (b) \(10: 1\) (c) \(100: 1\) (d) \(1: 100\)

5 step solution

Problem 106

The decreasing order of acidic nature of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (I), \(\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{II})\), and \(\mathrm{HClO}_{4}(\mathrm{III})\) is (a) \(\mathrm{I}>\mathrm{II}>\mathrm{III}\) (b) \(\mathrm{I}>\mathrm{III}>\mathrm{II}\) (c) \(\mathrm{III}>\mathrm{I}>\mathrm{II}\) (d) \(\mathrm{III}>\mathrm{II}>\mathrm{I}\)

5 step solution

Problem 107

The number of \(\mathrm{H}^{+}\)ions present in \(1 \mathrm{~cm}^{3}\) of a solution whose \(\mathrm{pH}\) is 10 is (a) \(10^{-10}\) (b) \(10^{-13}\) (c) \(6.02 \times 10^{10}\) (d) \(6.02 \times 10^{13}\)

4 step solution

Problem 108

The Ka value of formic acid and acetic acid are respectively \(1.77 \times 10^{-4}\) and \(1.75 \times 10^{-5}\). the ratio of the acid strength of \(0.1 \mathrm{~N}\) acids is (a) \(0.1\) (b) \(0.3\) (c) \(3.178\) (d) 100

5 step solution

Problem 109

If \(0.1 \mathrm{M}\) of a weak monobasic acid is taken and its percentage degree of ionization is \(1.34 \%\), then calculate its ionization constant (a) \(0.8 \times 10^{-5}\) (b) \(1.79 \times 10^{-5}\) (c) \(0.182 \times 19^{-5}\) (d) none of these

7 step solution

Problem 110

A weak monobasic acid is half neutralized by a strong base. If the \(\mathrm{pH}\) of the solution is \(5.4\), its pKa is (a) \(6.8\) (b) \(2.7\) (c) \(5.4\) (d) \(10.8\)

3 step solution

Problem 111

The solubility of \(\mathrm{AgCl}\) in moles per litre when its solubility product is \(1.56 \times 10^{-10}\) at \(25^{\circ} \mathrm{C}\) is (a) \(0.576 \times 10^{-8} \mathrm{~mol} /\) litre (b) \(1.056 \times 10^{-4} \mathrm{~mol} /\) litre (c) \(1.249 \times 10^{-5} \mathrm{~mol} /\) litre (d) \(1.478 \times 10^{-6} \mathrm{~mol} /\) litre

5 step solution

Problem 112

If the solubility of sodium hexafluoroaluminate is 'a' mol/litre, its solubility product is (a) \(\mathrm{a}^{8}\) (b) \(27 \mathrm{a}^{4}\) (c) \(180 \mathrm{a}^{3}\) (d) \(2916 \mathrm{a}^{8}\)

5 step solution

Problem 113

If the solubility of \(\mathrm{BaSO}_{4}\) (mol wt. 233) is \(2.33 \times 10^{-4}\) \(\mathrm{g} / 100 \mathrm{~mL}\) then the solubility product of \(\mathrm{BaSO}_{4}\) is (a) \(1 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1}\) (b) \(1 \times 10^{-10} \mathrm{~mol} \mathrm{~L}^{-1}\) (c) \(1 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}\) (d) \(1 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1}\)

6 step solution

Problem 114

The solubility product of calcium fluoride is \(3.2 \times\) \(10^{-11} \mathrm{M}^{3}\). Its solubility in saturated solution is (a) \(8 \times 10^{-12} \mathrm{M}\) (b) \(2 \times 10^{-4} \mathrm{M}\) (c) \(4 \times 10^{-12} \mathrm{M}\) (d) \(1 \times 10^{-4} \mathrm{M}\)

6 step solution

Problem 115

Equal volumes of the following \(\mathrm{Ca}^{2+}\) and \(\mathrm{F}^{-}\)solutions are mixed. In which of the solutions will precipitation occurs? \(\left[\mathrm{Ksp}\right.\) of \(\left.\mathrm{CaF}_{2}=1.7 \times 10^{-10}\right]\) 1\. \(10^{-2} \mathrm{M} \mathrm{Ca}^{2+}+10^{-5} \mathrm{M} \mathrm{F}^{-}\) 2\. \(10^{-3} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{M} \mathrm{F}^{-}\) 3\. \(10^{-4} \mathrm{M} \mathrm{Ca}^{2+}+10^{-2} \mathrm{M} \mathrm{F}^{-}\) 4\. \(10^{-2} \mathrm{M} \mathrm{Ca}^{2+}+10^{-3} \mathrm{M} \mathrm{F}^{-}\) Select the correct answer using the codes given below: (a) in 4 only (b) in 1 and 2 (c) in 3 and 4 (d) in 2,3 and 4

6 step solution

Problem 118

Consider of following acids: 1\. HCN 4\. HCOOH 3\. \(\mathrm{CH}_{3} \mathrm{COOH}\) 5\. \(\mathrm{Cl}-\mathrm{CH}_{2} \mathrm{COOH}\) Correct order of acid strength is (a) \(2>3>1>4\) (b) \(4>2>3>1\) (c) \(4>3>2>1\) (d) \(3>2>4>1\)

4 step solution

Problem 120

The \(\mathrm{pH}\) of solution made by mixing \(50 \mathrm{~mL}\) of \(0.01 \mathrm{M}\) barium hydroxide solution with \(50 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) is (a) \(3.0\) (b) \(6.0\) (c) \(12.0\) (d) \(15.0\)

5 step solution

Problem 121

Find the molar solubility of \(\mathrm{Fe}(\mathrm{OH})_{3}\) in a buffer solution that \(0.10 \mathrm{M}\) in \(\mathrm{NH}_{4} \mathrm{Cl}\) and \(0.10 \mathrm{M}\) in \(\mathrm{NH}_{3} .\) If \(\mathrm{K}_{\mathrm{b}}\) \(\left(\mathrm{NH}_{3}\right)=1.8 \times 10^{-5}\) and \(\mathrm{Ksp}\left[\mathrm{Fe}(\mathrm{OH})_{3}\right]=2.6 \times 10^{-39}\) (a) \(4.458 \times 10^{-25} \mathrm{M}\) (b) \(3.458 \times 10^{-25} \mathrm{M}\) (c) \(2.229 \times 10^{-24} \mathrm{M}\) (d) \(4.458 \times 10^{-22} \mathrm{M}\)

5 step solution

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