Problem 106
Question
The decreasing order of acidic nature of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (I), \(\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{II})\), and \(\mathrm{HClO}_{4}(\mathrm{III})\) is (a) \(\mathrm{I}>\mathrm{II}>\mathrm{III}\) (b) \(\mathrm{I}>\mathrm{III}>\mathrm{II}\) (c) \(\mathrm{III}>\mathrm{I}>\mathrm{II}\) (d) \(\mathrm{III}>\mathrm{II}>\mathrm{I}\)
Step-by-Step Solution
Verified Answer
The order is (c) III > I > II.
1Step 1: Understand Acid Strength
The strength of an acid depends on its ability to donate protons and the stability of the conjugate base. Generally, the more oxygen atoms around the central atom, the stronger the acid, due to better distribution of negative charge in the conjugate base.
2Step 2: Analyze Perchloric Acid (HClO_{4})
Perchloric acid (HClO_{4}) is a very strong acid due to its ability to stabilize the conjugate base with multiple electronegative oxygen atoms. It completely dissociates in water, making it stronger than most other acids.
3Step 3: Analyze Sulfuric Acid (H_{2}SO_{4})
Sulfuric acid (H_{2}SO_{4}) is also a strong acid but not as strong as perchloric acid. It is a strong acid due to being able to donate two protons and the stability of its conjugate base, hydrogen sulfate (HSO_{4}^{-}).
4Step 4: Analyze Phosphoric Acid (H_{3}PO_{4})
Phosphoric acid (H_{3}PO_{4}) is a weaker acid compared to sulfuric and perchloric acids. It is a triprotic acid, but its conjugate bases (H_{2}PO_{4}^{-}, HPO_{4}^{2-}, and PO_{4}^{3-}) are less stable and less able to efficiently delocalize charge.
5Step 5: Rank Acids by Strength
Based on the analysis, perchloric acid (HClO_{4}) is the strongest, followed by sulfuric acid (H_{2}SO_{4}), and phosphoric acid (H_{3}PO_{4}) is the weakest. Thus, the decreasing order of acidic nature is: III > I > II.
Key Concepts
Perchloric AcidSulfuric AcidPhosphoric AcidConjugate Base Stability
Perchloric Acid
Perchloric acid, denoted as \( \text{HClO}_{4} \), is recognized as one of the strongest acids. Its remarkable strength is due to the complete dissociation of its hydrogen proton in solution, resulting in \( \text{ClO}_{4}^{-} \) ions. The high acidity is facilitated by the presence of multiple electronegative oxygen atoms. These oxygen atoms are strategically positioned around the chlorine central atom.
This strategic placement allows for an even distribution of negative charge when the acid loses a proton, hence stabilizing the conjugate base.
This strategic placement allows for an even distribution of negative charge when the acid loses a proton, hence stabilizing the conjugate base.
- Complete dissociation in water
- Stabilization through multiple oxygen atoms
- Strong proton donor
Sulfuric Acid
Sulfuric acid, \( \text{H}_{2}\text{SO}_{4} \), is a notable strong acid, although it is not as potent as perchloric acid. Known for its corrosive nature, sulfuric acid is diprotic, meaning it can donate two protons. Thus, it ionizes in two stages: Initially to form hydrogen sulfate ions \( \text{HSO}_{4}^{-} \), and further ionization results in \( \text{SO}_{4}^{2-} \).
- Two stages of ionization
- Formation and stability of hydrogen sulfate ions \( \text{HSO}_{4}^{-} \)
- Strong oxidative and dehydrating properties
Phosphoric Acid
Phosphoric acid, \( \text{H}_{3}\text{PO}_{4} \), is a weaker acid in comparison to both perchloric and sulfuric acids. This acid is triprotic, which means it can donate three protons sequentially. While it has multiple opportunities to release protons, each proton is less easily dissociated than those in sulfuric or perchloric acids.
- Three-step ionization process
- Sequential formation of \( \text{H}_{2}\text{PO}_{4}^{-}, \text{HPO}_{4}^{2-}, \text{PO}_{4}^{3-} \)
- Less stable conjugate bases
Conjugate Base Stability
The stability of the conjugate base is a key determinant in the strength of an acid. After an acid donates its proton, the remaining ion is known as the conjugate base. A stable conjugate base results in a stronger acid because it means charge is effectively distributed or delocalized.
- Effective charge distribution increases stability
- The presence of electronegative atoms improves charge delocalization
- More oxygen atoms often correlate with better conjugate base stability
Other exercises in this chapter
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