Chapter 3
43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Chemistry · 63 exercises
Problem 46
The element with the highest first ionization potential is (a) boron (b) carbon (c) nitrogen (d) oxygen
5 step solution
Problem 48
The \(1^{\text {st }}, 2^{\text {nd }}\), and the \(3^{\text {rd }}\) ionization enthalpies, \(I_{1}, I_{2}\), and \(I_{3}\), of four atoms with atomic numbers \(n, n+1, n+2\), and \(n+3\), where \(n<10\), are tabulated below. What is the value of \(n ?\) $$ \begin{array}{|c|c|c|c|} \hline {\begin{array}{c} \text { Atomic } \\ \text { number } \end{array}} & & {\text { Ionization Enthalpy }(\mathrm{kJ} / \mathrm{mol})} \\\ { 2 - 4 } & I_{1} & I_{,} & I_{3} \\ \hline n & 1681 & 3374 & 6050 \\ \hline n+1 & 2081 & 3952 & 6122 \\ \hline n+2 & 496 & 4562 & 6910 \\ \hline n+3 & 738 & 1451 & 7733 \\ \hline \end{array} $$
5 step solution
Problem 49
Among the following, the number of elements showing only one nonzero oxidation state is : \(\mathrm{O}, \mathrm{Cl}, \mathrm{F}, \mathrm{N}, \mathrm{P}, \mathrm{Sn}, \mathrm{Tl}, \mathrm{Na}, \mathrm{Ti}\)
10 step solution
Problem 50
On Mulliken scale, the average of ionization potential and electron affinity is known as ..............
4 step solution
Problem 51
The energy released when an electron is added to a neutral gaseous atom is called .......... of the atom.
3 step solution
Problem 52
True/ False The basic nature of the hydroxides of group 13 (Gr. III B) decreases progressively down the group.
4 step solution
Problem 53
The decreasing order of electron affinity of \(\mathrm{F}, \mathrm{Cl}\), Br \(\mathrm{isF}>\mathrm{Cl}>\mathrm{Br}\).
4 step solution
Problem 55
The option(s) with only amphoteric oxides is(are) (a) \(\mathrm{Cr}_{2} \mathrm{O}_{3}, \mathrm{BeO}, \mathrm{SnO}, \mathrm{SnO}_{2}\) (b) \(\mathrm{Cr}_{2} \mathrm{O}_{3}, \mathrm{CrO}, \mathrm{SnO}, \mathrm{PbO}\) (c) \(\mathrm{NO}, \mathrm{B}_{2} \mathrm{O}_{3}, \mathrm{PbO}, \mathrm{SnO}_{2}\) (d) \(\mathrm{ZnO}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{PbO}, \mathrm{PbO}_{2}\)
6 step solution
Problem 56
Ionic radii of (a) \(\mathrm{Ti}^{4+}<\mathrm{Mn}^{7+}\) (b) \({ }^{35} \mathrm{Cl}^{-}<{ }^{37} \mathrm{Cl}^{-}\) (c) \(\mathrm{K}^{+}>\mathrm{Cl}^{-}\) (d) \(\mathrm{P}^{3+}>\mathrm{P}^{5+}\)
5 step solution
Problem 57
Sodium sulphate is soluble in water whereas barium sulphate is sparingly soluble because : (a) the hydration energy of sodium sulphate is more than its lattice energy (b) the lattice energy of barium sulphate is more than its hydration energy (c) the lattice energy has no role to play in solubility (d) the hydration energy of sodium sulphate is less than its lattice energy.
4 step solution
Problem 58
Read the following statement and explanation and answer as per the options given below : ASSERTION : The first ionization energy of Be is greater than that of B. REASON : \(2 p\) orbital is lower in energy than \(2 s\)
5 step solution
Problem 59
Arrange the following in : (i) Arrange the following ions in order of their increasing radii: \(\mathrm{Li}^{+}\), \(\mathrm{Mg}^{2+}, \mathrm{K}^{+}, \mathrm{Al}^{3+}\) (ii) Increasing order of basic character : \(\mathrm{MgO}, \mathrm{SrO}, \mathrm{K}_{2} \mathrm{O}, \mathrm{NiO}, \mathrm{Cs}_{2} \mathrm{O}\) (iii) Increasing order of ionic size : \(\mathrm{N}^{3-}, \mathrm{Na}^{+}, \mathrm{F}^{-}, \mathrm{O}^{2-}, \mathrm{Mg}^{2+}\) (iv) Increasing size : \(\mathrm{Cl}^{-}, \mathrm{S}^{2-}, \mathrm{Ca}^{2+}, \mathrm{Ar}\) (v) Increasing first ionization potential: Mg, Al, Si, Na (vi) Increasing acidic property: \(\mathrm{ZnO}, \mathrm{Na}_{2} \mathrm{O}_{2}, \mathrm{P}_{2} \mathrm{O}_{5}, \mathrm{MgO}\) (vii) Decreasing ionic size : \(\mathrm{Mg}^{2+}, \mathrm{O}^{2-}, \mathrm{Na}^{+}, \mathrm{F}^{-}\)
7 step solution
Problem 60
The first ionization energy of carbon atom is greater than that of boron atom whereas, the reverse is true for the second ionization energy.
5 step solution