Problem 59
Question
Arrange the following in : (i) Arrange the following ions in order of their increasing radii: \(\mathrm{Li}^{+}\), \(\mathrm{Mg}^{2+}, \mathrm{K}^{+}, \mathrm{Al}^{3+}\) (ii) Increasing order of basic character : \(\mathrm{MgO}, \mathrm{SrO}, \mathrm{K}_{2} \mathrm{O}, \mathrm{NiO}, \mathrm{Cs}_{2} \mathrm{O}\) (iii) Increasing order of ionic size : \(\mathrm{N}^{3-}, \mathrm{Na}^{+}, \mathrm{F}^{-}, \mathrm{O}^{2-}, \mathrm{Mg}^{2+}\) (iv) Increasing size : \(\mathrm{Cl}^{-}, \mathrm{S}^{2-}, \mathrm{Ca}^{2+}, \mathrm{Ar}\) (v) Increasing first ionization potential: Mg, Al, Si, Na (vi) Increasing acidic property: \(\mathrm{ZnO}, \mathrm{Na}_{2} \mathrm{O}_{2}, \mathrm{P}_{2} \mathrm{O}_{5}, \mathrm{MgO}\) (vii) Decreasing ionic size : \(\mathrm{Mg}^{2+}, \mathrm{O}^{2-}, \mathrm{Na}^{+}, \mathrm{F}^{-}\)
Step-by-Step Solution
VerifiedKey Concepts
Ionic Radii
In contrast, anions, such as \(\mathrm{F}^{-}\) or \(\mathrm{O}^{2-}\), gain electrons, increasing their size due to enhanced electron-electron repulsion and reduced effective nuclear charge. Generally, higher positive charge in cations results in a smaller radius, and higher negative charge in anions leads to a larger radius.
Therefore, in comparing ionic sizes, the order is affected by the ionic charges and the original atomic size, leading us to order ions such as \(\mathrm{Al}^{3+} < \mathrm{Mg}^{2+} < \mathrm{Li}^{+} < \mathrm{K}^{+}\) based on their decreasing size.
Basic Character
For example, in group 1, oxides like \(\mathrm{Cs}_{2} \mathrm{O}\) are more basic than \(\mathrm{Li}_{2} \mathrm{O}\), as cesium is lower in the group, making its oxide more ionic and basic. Similarly, \(\mathrm{SrO}\) is more basic than \(\mathrm{MgO}\). In a nutshell, more ionic oxides, that form ionic bonds readily, tend to be more basic, leading to the arrangement: \(\mathrm{NiO} < \mathrm{MgO} < \mathrm{SrO} < \mathrm{K}_{2} \mathrm{O} < \mathrm{Cs}_{2} \mathrm{O}\).
Ionic Size
For instance, \(\mathrm{N}^{3-}\) is the largest amongst common negative ions because it has the greatest number of excess electrons. Comparatively, cations like \(\mathrm{Mg}^{2+}\) are smaller since they lose electrons, reducing their ionic radius. The order of increasing ionic size. \(\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-} < \mathrm{N}^{3-}\), reflects this rule as more negatively charged and fully or partially filled inner shell configurations result in larger ionic sizes.
Ionization Potential
When comparing the elements like \(\mathrm{Na}, \mathrm{Mg}, \mathrm{Al},\) and \(\mathrm{Si}\), we notice that \(\mathrm{Si}\), being further to the right, has a higher ionization potential due to greater nuclear attraction on its valence electrons. Conversely, \(\mathrm{Na}\), at the start of the period, permits easier electron removal. The order of increasing ionization potential is: \(\mathrm{Na} < \mathrm{Mg} < \mathrm{Al} < \mathrm{Si}\).
Acidic Property
For example, \(\mathrm{P}_{2} \mathrm{O}_{5}\) is noted for its strong acidic properties, whereas \(\mathrm{Na}_{2} \mathrm{O}_{2}\) and \(\mathrm{MgO}\) are basic. As we progress from metallic oxides to nonmetallic oxides, the acidity of the oxides increases, since nonmetallic oxides react with water to form acids. With this reasoning, we can arrange the compounds by increasing acidity as follows: \[\mathrm{Na}_{2}\mathrm{O}_{2} < \mathrm{MgO} < \mathrm{ZnO} < \mathrm{P}_{2}\mathrm{O}_{5}\].