Chapter 8
Calculus for Biology and Medicine · 177 exercises
Problem 35
By breaking down each equation into two parts that you can sketch, determine how many equilib\mathrm{\\{} r i a ~ e a c h ~ d i f f e r e n t i a l ~ e q u a t i o n ~ h a s , ~ a n d ~ c l a s s i f y ~ t h e m ~ a s ~ s t a b l e ~ or unstable. You do not need to determine the location of the equilibria. $$ \frac{d N}{d t}=N^{2}-N+1 \quad N>0 $$
5 step solution
Problem 35
We showed in Section \(8.3 .4\) that if \(b
7 step solution
Problem 35
$$ \text { In Problems } 35-38, \text { solve each differential equation. } $$ $$ \frac{d y}{d x}=y(1+y) $$
6 step solution
Problem 36
By breaking down each equation into two parts that you can sketch, determine how many equilib\mathrm{\\{} r i a ~ e a c h ~ d i f f e r e n t i a l ~ e q u a t i o n ~ h a s , ~ a n d ~ c l a s s i f y ~ t h e m ~ a s ~ s t a b l e ~ or unstable. You do not need to determine the location of the equilibria. $$ \frac{d N}{d t}=1-N-N^{3} $$
7 step solution
Problem 36
$$ \text { In Problems } , \text { solve each differential equation. } $$$$ \frac{d y}{d x}=(1+y)^{2} $$
6 step solution
Problem 37
$$ \text { In Problems } , \text { solve each differential equation. } $$ $$ \frac{d y}{d x}=(1+y)^{3} $$
6 step solution
Problem 38
By breaking down each equation into two parts that you can sketch, determine how many equilib\mathrm{\\{} r i a ~ e a c h ~ d i f f e r e n t i a l ~ e q u a t i o n ~ h a s , ~ a n d ~ c l a s s i f y ~ t h e m ~ a s ~ s t a b l e ~ or unstable. You do not need to determine the location of the equilibria. $$ \frac{d y}{d x}=y^{4}+y^{3}-1 $$
5 step solution
Problem 38
We will analyze the population dynamics that are predicted by (8.69), for different values of b and \(c\). Suppose \(b=c\), then \(\frac{d x}{d t}=\frac{k n b}{2} x(1-x)^{2}\). Assuming \(k=1\), \(n=1\), and \(b=1\), sketch the vector field plot for \(x\).
4 step solution
Problem 38
$$ \text { In Problems } , \text { solve each differential equation. } $$ $$ \frac{d y}{d x}=\left(1-y^{2}\right) $$
5 step solution
Problem 39
In Problems 39-48 you should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use \(a\) graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d y}{d t}=e^{y}-(1-y) $$
5 step solution
Problem 40
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d y}{d t}=y-h $$
5 step solution
Problem 41
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d y}{d x}=y^{2}-h $$
5 step solution
Problem 41
To model the spread of a disease in a population of size \(N\) we derived a differential equation model: $$ \frac{d I}{d t}=(k b-c) I-\frac{k b}{N} I^{2} $$ where \(I(t)\) is the number of infected individuals at time \(t\), and \(k, b\), and \(c\) are all positive coefficients. Assuming that I ( \(t\) ) is modeled by Equation \((8.70)\), you should locate the equilibria of the model, and find which of these equilibria are stable. Draw a vector field plot for each problem. \(k=1, b=1, c=0.5, N=50 .\)
3 step solution
Problem 41
Suppose that the size of a population at time \(t\) is denoted by \(N(t)\) and that \(N(t)\) satisfies the logistic equation $$ \frac{d N}{d t}=0.34 N\left(1-\frac{N}{200}\right) \quad \text { with } N(0)=50 $$ Solve this differential equation, and determine the size of the population in the long run; that is, find \(\lim _{t \rightarrow \infty} N(t)\).
5 step solution
Problem 42
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d y}{d x}=(y-1)(y+3)-h $$
5 step solution
Problem 42
Assume that a population, whose size is denoted by \(N(t)\), grows according to the logistic equation. Find the limiting growth rate for small \(N\) (i.e., find the constant \(r\) ) if the carrying capacity is \(100, N(0)=10\), and \(N(1)=30\)
6 step solution
Problem 43
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d y}{d x}=(y-2)(y+4)+h $$
5 step solution
Problem 43
. Let \(N(t)\) denote the size of a population at time \(t .\) Assume that the population grows according to the logistic equation. Assume also that the limiting growth rate for small \(N\) is 5 and that the carrying capacity is \(50 .\) (a) Find a differential equation that describes the growth of this population. (b) Without solving the differential equation in (a), sketch solution curves of \(N(t)\) as a function of \(t\) when (i) \(N(0)=10\), (ii) \(N(0)=40\), and (iii) \(N(0)=50\).
5 step solution
Problem 44
Logistic growth is described by the differential equation $$ \frac{d N}{d t}=r N\left(1-\frac{N}{K}\right) $$ We showed in Example 6 that the solution of this differential equation with initial condition \(N(0)=N_{0}\) is given by $$ N(t)=\frac{K}{1+\left(\frac{K}{N_{0}}-1\right) e^{-r t}} $$ (a) Show that $$ r=\frac{1}{t} \ln \left(\frac{K-N_{0}}{N_{0}}\right)+\frac{1}{t} \ln \left(\frac{N(t)}{K-N(t)}\right) $$ by solving \((8.29)\) for \(r\). (b) Equation \((8.30)\) can be used to estimate \(r\). Suppose we are studying a population that grows according to the logistic equation and find that \(N(0)=10, N(5)=22, N(100)=30\), and \(N(200)=30 .\) Estimate \(r .(\) Hint \(:\) First estimate \(K\) from the behavior of the solution for large \(t .\) )
7 step solution
Problem 45
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d x}{d t}=x^{2}-h x $$
4 step solution
Problem 45
In this question we will interpret the recovery rate, \(c\), that appears in the model. Assume that a population of infected individuals is quarantined (that is, they are unable to transmit the disease to others, or to catch it again once they recover). (a) Explain why under these assumptions we expect: $$ \frac{d I}{d t}=-c I $$ (b) Assuming \(I(0)=I_{0}\), find \(I(t)\) by solving \((8.71)\). (c) How long will it take for the number of infected individuals to decrease from \(I_{0}\) to \(I_{0} / 2 ?\) (d) Assume that it takes 7 days for the number of infected individuals to decrease from 50 to \(25 .\) Calculate the recovery rate \(c\) for this disease.
4 step solution
Problem 45
Population genetics is the study of how the frequency of particular traits changes within a population over time. We are studying a gene that comes in two alleles (i.e., variants) \(A\) and \(a\). The \(A\) allele makes individuals reproduce a little faster than the \(a\) allele. So we expect the \(A\) alleles to take over the population with time. Suppose that a proportion \(p\) of all individuals within the population carry the \(A\) allele (with the remaining proportion, \(1-p\), carrying the \(a\) allele). If the \(A\) allele boosts reproduction rate by an amount \(s\) it can be shown under some assumptions that the proportion of \(A\) -allele individuals obeys a differential equation $$ \frac{d p}{d t}=\frac{1}{2} s p(1-p) $$ (a) Use separation of variables and partial fractions to find the solution of \((8.31)\), assuming \(p(0)=p_{0}\). (b) Show that if \(p_{0} \neq 0\), then \(\lim _{t \rightarrow \infty} p(t)=1\). Explain why this behavior makes sense biologically. (c) Suppose \(p_{0}=0.1\) and \(s=0.01\); how long will take until \(p(t)=0.5 ?\)
7 step solution
Problem 46
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d x}{d t}=x^{3}-h x $$
6 step solution
Problem 46
In Problems 46-54, solve each differential equation with the given initial condition. $$ \frac{d y}{d x}=2 \frac{y}{x}, \text { with } y(1)=1 $$
4 step solution
Problem 47
You should treat \(h\) as a constant. For what values of \(h\) (if any) does each equation have equilibria? Use a graphical argument to show which of the equilibria (if any) are stable. $$ \frac{d x}{d t}=x\left(x^{2}-1\right)-h $$
6 step solution
Problem 47
Handwashing One way to control the spread of a disease is to run public health programs that educate people on how to limit their exposure to the disease. For example, frequent handwashing can prevent people from picking up a virus after touching surfaces that it may live on. (a) Explain why in our model such efforts to control the disease would affect the value of the parameter \(k\), but would not affect \(b\) or \(c\). (b) Suppose that for a particular disease \(c=0.3 /\) day, and \(b=\) \(10 /\) day. What value must \(k\) remain below to prevent the disease from hecomino endemic?
4 step solution
Problem 47
In Problems, solve each differential equation with the given initial condition. $$ \frac{d y}{d x}=\frac{x+1}{y}, \text { with } y(0)=2 $$
7 step solution
Problem 48
In Problems, solve each differential equation with the given initial condition. $$ \frac{d y}{d x}=\frac{x y}{x+1}, \text { with } y(0)=1 . $$
6 step solution
Problem 49
For Problems \(49-56\) determine whether the equilibrium at \(x=0\) is stable, unstable, or semi-stable. $$ \frac{d x}{d t}=x^{3} $$
4 step solution
Problem 49
In Problems, solve each differential equation with the given initial condition. $$ \frac{d y}{d x}=(y+1) e^{-x}, \text { with } y(0)=2 $$
5 step solution
Problem 50
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=-x^{5} $$
3 step solution
Problem 50
In Problems, solve each differential equation with the given initial condition. $$ \frac{d y}{d x}=\frac{y^{2}}{x}, \text { with } y(1)=1 . $$
5 step solution
Problem 51
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=x^{4} $$
6 step solution
Problem 51
In Problems, solve each differential equation with the given initial condition. $$ \frac{d y}{d x}=\frac{y+1}{x-1}, \text { with } y(2)=5 $$
6 step solution
Problem 52
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=x^{3}-x^{5} $$
3 step solution
Problem 52
In Problems, solve each differential equation with the given initial condition.$$ \frac{d u}{d t}=\frac{\sin t}{u+1}, \text { with } u(0)=3 $$
5 step solution
Problem 53
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=x^{3}+x^{4} $$
5 step solution
Problem 53
In Problems, solve each differential equation with the given initial condition.$$ \frac{d y}{d t}=\frac{t}{y}, \text { with } y(0)=1 . $$
6 step solution
Problem 54
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=x^{2}-x^{3} $$
4 step solution
Problem 54
In Problems, solve each differential equation with the given initial condition. $$ \frac{d x}{d y}=\frac{1}{2} \frac{x}{y}, \text { with } x(3)=2 . $$
5 step solution
Problem 55
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=\frac{x^{3}}{x-1} $$
3 step solution
Problem 55
In Problems 55-60 you will need to solve differential equations by separation of variables. In these problems it will not always be possible to solve explicitly for \(y\) in terms of \(t ;\) instead your solution may take the form of an implicit function relating the two variables. $$ \frac{d y}{d t}=\frac{y^{2}+y}{t-1} \text { where } y(0)=1 $$
5 step solution
Problem 56
Determine whether the equilibrium at \(x=0\) is stable, unstable, or semi- stable. $$ \frac{d x}{d t}=x^{3} e^{-x} $$
6 step solution
Problem 56
In Problems you will need to solve differential equations by separation of variables. In these problems it will not always be possible to solve explicitly for \(y\) in terms of \(t ;\) instead your solution may take the form of an implicit function relating the two variables. $$ \frac{d y}{d t}=\frac{y t}{\ln y} \text { where } y(1)=e $$
7 step solution
Problem 57
For Problems \(57-66\) draw the vector field plot of the differential equation. Then, using the given initial conditions, sketch the solutions (i.e., draw a graph showing the dependent variable as a function of the independent variable). \(\frac{d y}{d t}=3 y-2\) (a) \(y(0)=2\), (b) \(y(0)=0\).
6 step solution
Problem 57
In Problems you will need to solve differential equations by separation of variables. In these problems it will not always be possible to solve explicitly for \(y\) in terms of \(t ;\) instead your solution may take the form of an implicit function relating the two variables. $$ \frac{d y}{d t}=\frac{t+1}{y+y^{2}} \text { where } y(0)=1 $$
8 step solution
Problem 58
Draw the vector field plot of the differential equation. Then, using the given initial conditions, sketch the solutions (i.e., draw a graph showing the dependent variable as a function of the independent variable). \(\frac{d y}{d t}=1-y\) (a) \(y(0)=2\), (b) \(y(0)=-1\).
6 step solution
Problem 58
In Problems you will need to solve differential equations by separation of variables. In these problems it will not always be possible to solve explicitly for \(y\) in terms of \(t ;\) instead your solution may take the form of an implicit function relating the two variables. $$ \frac{d y}{d t}=\frac{t^{2}+1}{\cos y+\sin y} \text { where } y(0)=0 $$
4 step solution
Problem 59
Draw the vector field plot of the differential equation. Then, using the given initial conditions, sketch the solutions (i.e., draw a graph showing the dependent variable as a function of the independent variable). \(\frac{d y}{d t}=y(1-y)\) (a) \(y(0)=0\), (b) \(y(0)=1 / 2\), (c) \(y(0)=1 / 4\), (d) \(y(0)=2\).
5 step solution
Problem 59
In Problems you will need to solve differential equations by separation of variables. In these problems it will not always be possible to solve explicitly for \(y\) in terms of \(t ;\) instead your solution may take the form of an implicit function relating the two variables. $$ \frac{d y}{d t}=\sqrt{\frac{t+1}{y+1}} \text { where } y(0)=1 $$
6 step solution