Chapter 11

Calculus for Biology and Medicine · 116 exercises

Problem 21

A very simple two-compartment model for gap dynamics in a forest assumes that gaps are created by disturbances (wind, fire, etc.) and that gaps revert to forest as trees grow in the gaps. We denote by \(x_{1}(t)\) the area occupied by gaps and by \(x_{2}(t)\) the area occupied by adult trees. We assume that the dynamics are given by $$ \begin{array}{l} \frac{d x_{1}}{d t}=-0.2 x_{1}+0.1 x_{2} \\ \frac{d x_{2}}{d t}=0.2 x_{1}-0.1 x_{2} \end{array} $$ (a) Find the corresponding compartment diagram. (b) Show that \(x_{1}(t)+x_{2}(t)\) is a constant. Denote the constant by \(A\) and give its meaning. [Hint: Show that \(\frac{d}{d t}\left(x_{1}+x_{2}\right)=0 .\) ] (c) Let \(x_{1}(0)+x_{2}(0)=20\). Use your answer in (b) to explain why this equation implies that \(x_{1}(t)+x_{2}(t)=20\) for all \(t>0\). (d) Use your result in (c) to replace \(x_{2}\) in (11.44) by \(20-x_{1}\), and show that doing so reduces the system \((11.44)\) and \((11.45)\) to $$ \frac{d x_{1}}{d t}=2-0.3 x_{1} $$ with \(x_{1}(t)+x_{2}(t)=20\) for all \(t \geq 0\). (e) Solve the system (11.44) and (11.45), and determine what fraction of the forest is occupied by adult trees at time \(t\) when \(x_{1}(0)=2\) and \(x_{2}(0)=18\). What happens as \(t \rightarrow \infty\) ?

6 step solution

Problem 22

Solve the given initial-value problem. $$ \left[\begin{array}{c} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{rr} -1 & 0 \\ 1 & -2 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ $$ \text { with } x_{1}(0)=-1 \text { and } x_{2}(0)=-2 \text { . } $$

6 step solution

Problem 23

Solve the given initial-value problem. $$ \left[\begin{array}{c} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{cc} 4 & -7 \\ 2 & -5 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ $$ \text { with } x_{1}(0)=13 \text { and } x_{2}(0)=3 \text { . } $$

7 step solution

Problem 23

Let $$ \begin{array}{l} \frac{d x_{1}}{d t}=x_{1}\left(2-x_{1}\right)-x_{1} x_{2} \\ \frac{d x_{2}}{d t}=x_{1} x_{2}-x_{2} \end{array} $$ (a) Graph the zero isoclines. (b) Show that \((1,1)\) is an equilibrium. Use the graphical approach to determine its stability. 24\. Let $$ \begin{array}{l} \frac{d x_{1}}{d t}=x_{1}\left(2-x_{1}^{2}\right)-x_{1} x_{2} \\ \frac{d x_{2}}{d t}=x_{1} x_{2}-x_{2} \end{array} $$ (a) Graph the zero isoclines. (b) Show that \((1,1)\) is an equilibrium. Use the graphical approach to determine its stability.

6 step solution

Problem 23

23\. Solve $$ \frac{d^{2} x}{d t^{2}}=-4 x $$ with \(x(0)=0\) and \(\frac{d x(0)}{d t}=6\).

6 step solution

Problem 24

Solve the given initial-value problem. $$ \left[\begin{array}{l} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{ll} -3 & 4 \\ -1 & 2 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ $$ \text { with } x_{1}(0)=1 \text { and } x_{2}(0)=2 \text { . } $$

6 step solution

Problem 24

Solve $$ \frac{d^{2} x}{d t^{2}}=-9 x $$ with \(x(0)=0\) and \(\frac{d x(0)}{d t}=12\).

7 step solution

Problem 25

Solve the given initial-value problem. $$ \left[\begin{array}{c} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{rr} 4 & 7 \\ 1 & -2 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ $$ \text { with } x_{1}(0)=-3 \text { and } x_{2}(0)=1 \text { . } $$

6 step solution

Problem 25

\- Iranstorm the second-order dutferentral equation $$ \frac{d^{2} x}{d t^{2}}=3 x $$ into a system of first-order differential equations.

4 step solution

Problem 26

Solve the given initial-value problem. $$ \left[\begin{array}{c} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{ll} 2 & 6 \\ 1 & 3 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ $$ \text { with } x_{1}(0)=-3 \text { and } x_{2}(0)=1 \text { . } $$

7 step solution

Problem 26

Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}=-\frac{1}{2} x $$ into a system of first-order differential equations.

3 step solution

Problem 27

We discuss the case of repeated eigenvalues. $$ \left[\begin{array}{l} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ (a) Show that $$ A=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right] $$ has the repeated eigenvalues \(\lambda_{1}=\lambda_{2}=1\). (b) Show that \(\left[\begin{array}{l}1 \\ 0\end{array}\right]\) and \(\left[\begin{array}{l}0 \\ 1\end{array}\right]\) are eigenvectors of \(A\) and that any vector \(\left[\begin{array}{l}c_{1} \\ c_{2}\end{array}\right]\) can be written as $$ \left[\begin{array}{l} c_{1} \\ c_{2} \end{array}\right]=c_{1}\left[\begin{array}{l} 1 \\ 0 \end{array}\right]+c_{2}\left[\begin{array}{l} 0 \\ 1 \end{array}\right] $$ (c) Show that $$ \mathbf{x}(t)=c_{1} e^{t}\left[\begin{array}{l} 1 \\ 0 \end{array}\right]+c_{2} e^{t}\left[\begin{array}{l} 0 \\ 1 \end{array}\right] $$ is a solution of \((11.34)\) that satisfies the initial condition \(x_{1}(0)=c_{1}\) and \(x_{2}(0)=c_{2}\).

5 step solution

Problem 27

Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}+\frac{d x}{d t}=x $$ into a system of first-order differential equations.

5 step solution

Problem 28

We discuss the case of repeated eigenvalues. $$ \left[\begin{array}{l} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{ll} 1 & 2 \\ 0 & 1 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$ (a) Show that $$ A=\left[\begin{array}{ll} 1 & 2 \\ 0 & 1 \end{array}\right] $$ has the repeated eigenvalues \(\lambda_{1}=\lambda_{2}=1\). (b) Show that every eigenvector of \(A\) is of the form $$ c_{1}\left[\begin{array}{l} 1 \\ 0 \end{array}\right] $$ where \(c_{1}\) is a real number different from \(0 .\) (c) Show that $$ \mathbf{x}_{1}(t)=e^{t}\left[\begin{array}{l} 1 \\ 0 \end{array}\right] $$ is a solution of \((11.35)\).

3 step solution

Problem 28

Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}-2 \frac{d x}{d t}=3 x $$ into a system of first-order differential equations.

4 step solution

Problem 29

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} 2 & -1 \\ 0 & 3 \end{array}\right] $$

3 step solution

Problem 30

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} -1 & 0 \\ 0 & -4 \end{array}\right] $$

4 step solution

Problem 31

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} -2 & 2 \\ 2 & 1 \end{array}\right] $$

2 step solution

Problem 32

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} -5 & -2 \\ 6 & 3 \end{array}\right] $$

3 step solution

Problem 33

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{ll} -4 & 2 \\ -5 & 3 \end{array}\right] $$

4 step solution

Problem 34

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point.$$ A=\left[\begin{array}{rr} -2 & 4 \\ 2 & -5 \end{array}\right] $$

3 step solution

Problem 35

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} 6 & -4 \\ -3 & 5 \end{array}\right] $$

3 step solution

Problem 36

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} -1 & 3 \\ 2 & -5 \end{array}\right] $$

4 step solution

Problem 37

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point.3 $$ A=\left[\begin{array}{rr} -3 & -1 \\ 1 & -6 \end{array}\right] $$

5 step solution

Problem 37

Consider communities composed of two species. The abundance of species 1 at time \(t\) is given by \(N_{1}(t)\), the abundance of species 2 at time \(t\) by \(N_{2}(t) .\) Their dynamics are described by $$ \begin{array}{l} \frac{d N_{1}}{d t}=f_{1}\left(N_{1}, N_{2}\right) \\ \frac{d N_{2}}{d t}=f_{2}\left(N_{1}, N_{2}\right) \end{array} $$ Assume that when both species are at low abundances their abundances increase and that \(f_{1}\) and \(f_{2}\) change sign when crossing their zero isoclines. In each problem, determine the sign structure of the community matrix at the nontrivial equilibrium (indicated by a dot) on the basis of the graph of the zero isoclines. Determine the stability of the equilibria if possible.

4 step solution

Problem 38

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} -3 & 1 \\ 1 & -2 \end{array}\right] $$

4 step solution

Problem 39

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} 0 & -2 \\ -1 & 3 \end{array}\right] $$

5 step solution

Problem 40

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{ll} 0 & 2 \\ 3 & 7 \end{array}\right] $$

3 step solution

Problem 41

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{rr} -2 & -3 \\ 1 & 3 \end{array}\right] $$

3 step solution

Problem 41

Assume that the diagonal elements \(a_{i i}\) of the community matrix of a species assemblage in equilibrium are negative. Explain why this assumption implies that species \(i\) exhibits selfregulation.

4 step solution

Problem 42

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of A will be real, distinct, and nonzero. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a sink, a source, or a saddle point. $$ A=\left[\begin{array}{ll} 4 & -1 \\ 5 & -1 \end{array}\right] $$

3 step solution

Problem 42

Consider a community composed of two species. Assume that both species inhibit themselves. Explain why mutualistic and competitive interactions lead to qualitatively similar predictions about the stability of the corresponding equilibria. That is, show that if \(A=\left[a_{i j}\right]\) is the community matrix at equilibrium for the case of mutualism, and if \(B=\left[b_{i j}\right]\) is the community matrix at equilibrium for the case of competition, then the following holds: If \(\left|a_{i j}\right|=\left|b_{i j}\right|\) for \(1 \leq i, j \leq 2\), then either both equilibria are Iocally stable or both are unstable

5 step solution

Problem 43

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{rr} 2 & -1 \\ 3 & 0 \end{array}\right] $$

7 step solution

Problem 43

The classical Lotka-Volterra model of predation is given by $$ \begin{array}{l} \frac{d N}{d t}=a N-b N P \\ \frac{d P}{d t}=c N P-d P \end{array} $$ where \(N=N(t)\) is the prey density at time \(t\) and \(P=P(t)\) is the predator density at time \(t .\) The constants \(a, b, c\), and \(d\) are all positive. (a) Find the nontrivial equilibrium \((\hat{N}, \hat{P})\) with \(\hat{N}>0\) and \(\hat{P}>0\). (b) Find the community matrix corresponding to the nontrivial equilibrium. (c) Explain each entry of the community matrix found in (b) in terms of how individuals in this community affect each other.

8 step solution

Problem 44

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{rr} -1 & -5 \\ 4 & -3 \end{array}\right] $$

8 step solution

Problem 44

The modified Lotka-Volterra model of predation is given by $$ \begin{array}{l} \frac{d N}{d t}=a N\left(1-\frac{N}{K}\right)-b N P \\ \frac{d P}{d t}=c N P-d P \end{array} $$ where \(N=N(t)\) is the prey density at time \(t\) and \(P=P(t)\) is the predator density at time \(t\). The constants \(a, b, c, d\), and \(K\) are positive. Assume that \(d / c0\) and \(\hat{P}>0\). (b) Find the community matrix corresponding to the nontrivial equilibrium. (c) Explain each entry of the community matrix found in (b) in terms of how individuals in this community affect each other.

6 step solution

Problem 45

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{rr} -2 & 4 \\ -3 & -2 \end{array}\right] $$

4 step solution

Problem 45

Use a graphing calculator to study the following example of the Fitzhugh- Nagumo model: $$ \begin{array}{l} \frac{d V}{d t}=-V(V-0.3)(V-1)-w \\ \frac{d w}{d t}=0.01(V-0.4 w) \end{array} $$ Sketch the graph of the solution curve in the \(V-w\) plane when (i) \((V(0), w(0))=(0.4,0)\) and (ii) \((V(0), w(0))=(0.2,0)\).

5 step solution

Problem 46

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{ll} 1 & 3 \\ -2 & 1 \end{array}\right] $$

5 step solution

Problem 46

Use a graphing calculator to study the following example of the Fitzhugh- Nagumo model: $$ \begin{array}{l} \frac{d V}{d t}=-V(V-0.6)(V-1)-w \\ \frac{d w}{d t}=0.03(V-0.6 w) \end{array} $$ Sketch the graph of the solution curve in the \(V-w\) plane when (i) \((V(0), w(0))=(0.8,0)\) and (ii) \((V(0), w(0))=(0.4,0)\).

6 step solution

Problem 48

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{ll} 2 & -3 \\ 2 & -1 \end{array}\right] $$

4 step solution

Problem 49

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{rr} 4 & 5 \\ -3 & -3 \end{array}\right] $$

3 step solution

Problem 49

Use the mass action law to translate each chemical reaction into a system of differential equations. \(\mathrm{A}+\mathrm{B} \stackrel{k}{\longrightarrow} \mathrm{C}\)

5 step solution

Problem 50

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{ll} -1 & 1 \\ -3 & 1 \end{array}\right] $$

4 step solution

Problem 51

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{ll} -1 & 1 \\ -3 & 1 \end{array}\right] $$

3 step solution

Problem 51

Use the mass action law to translate each chemical reaction into a system of differential equations. \(\mathrm{E}+\mathrm{S} \stackrel{k_{1}}{\longrightarrow} \mathrm{ES} \stackrel{k_{2}}{\longrightarrow} \mathrm{E}+\mathrm{P}\)

4 step solution

Problem 52

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{rr} 3 & -2 \\ 1 & 3 \end{array}\right] $$

4 step solution

Problem 52

Use the mass action law to translate each chemical reaction into a system of differential equations. \(\mathrm{A}+\mathrm{B} \stackrel{k}{\longrightarrow} \mathrm{A}+\mathrm{C}\)

5 step solution

Problem 53

We consider differential equations of the form $$ \frac{d \mathbf{x}}{d t}=A \mathbf{x}(t) $$ where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] $$ The eigenvalues of \(A\) will be complex conjugates. Analyze the stability of the equilibrium \((0,0)\), and classify the equilibrium according to whether it is a stable spiral, an unstable spiral, or a center. $$ A=\left[\begin{array}{rr} 0 & -1 \\ 1 & 0 \end{array}\right] $$

5 step solution

Problem 53

Show that the following system of differential equations has a conserved quantity, and find it: $$ \begin{array}{l} \frac{d x}{d t}=2 x-3 y \\ \frac{d y}{d t}=3 y-2 x \end{array} $$

7 step solution

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