Q. 9.104 - An Introduction to General, Organic, and Biological Chemistry

Question

How many liters of a $4.00M \mathrm{NaCl}$ solution will provide$25.0 \mathrm{g}$ of$\mathrm{NaCl}?$

Step-by-Step Solution

Answer

$0.107 ml$ of a $4.00M NaCl$solution provide $25.0 g$ of $NaCl$.

Step 1: Given information

To calculate how much liters of a $4.00\mathrm{MNaCl}$ solution will provide $25.0 \mathrm{g}$ of $NaCl$.

Step 2: To calculate the moles of N a C l   by using the following expression :

Moles of $\mathrm{NaCl}=\frac{\text{ mass of }\mathrm{NaCl}}{\text{ molar mass of }\mathrm{NaCl}}$

$=\frac{25 \mathrm{g}}{58.44 \mathrm{g}/\mathrm{mol}}$

$=0.428 \mathrm{mol}$

Step 3: To calculate the volume required by using the following expression :

Volume of $\mathrm{NaCl}=\frac{\text{ Moles of }\mathrm{NaCl}}{\text{ Molarity of }\mathrm{NaCl}}$

$=\frac{0.428 \mathrm{mol}}{4.00\mathrm{M}}$

$=0.107 \mathrm{L}$

Therefore, the required volume of $NaCl$ solution is $0.107 ml$.