Q. 9.103 - An Introduction to General, Organic, and Biological Chemistry

Question

How many liters of a $2.50{\mathrm{MKNO}}_3$ solution can be prepared from $60.0 \mathrm{g}$ of ${\mathrm{KNO}}_3$ ? 

Step-by-Step Solution

Answer

$0.237 L$of a $2.50{\mathrm{MKNO}}_3$ solution can be prepared from $60.0 g$ of ${\mathrm{KNO}}_3$.

Step 1: Given information

To calculate the how much liters of a $2.50{\mathrm{MKNO}}_3$ solution can be prepared from $60.0 g$ of ${\mathrm{KNO}}_3$.

Step 2: To calculate the moles of KNO 3 by using the following expression

Moles of ${\mathrm{KNO}}_3=\frac{\text{ mass of }{\mathrm{KNO}}_3}{\text{ molar mass of }{\mathrm{KNO}}_3}$

$=\frac{60 \mathrm{g}}{101.1 \mathrm{g}/\mathrm{mol}}$

$=0.593 \mathrm{mol}$.

Step 3: To calculate the volume required by using the following expression :

Volume of ${\mathrm{KNO}}_3=\frac{\text{ Moles of }{\mathrm{KNO}}_3}{\text{ Molarity of }{\mathrm{KNO}}_3}$

$=\frac{0.593 \mathrm{mol}}{2.50\mathrm{M}}$

$=0.237 \mathrm{L}$

Therefore, the required volume of ${\mathrm{KNO}}_3$ solution is $0.237 L$.