Q. 9.102 - An Introduction to General, Organic, and Biological Chemistry

Question

How many milliliters of a $1.50 M NaBr$ solution contain $75.0 g$ of $NaBr$

Step-by-Step Solution

Answer

$486 ml$ of $NaBr$ solution of $1.50 M NaBr$ solution contains $75.0 g$ of  $NaBr$

Step 1: Given information

To find how much milliliters of $1.50 M NaBr$ solution contains $75.0 g$of $NaBr$:

Step 2: Calculate the moles of N a B r by using the following expression :

Moles of $\mathrm{NaBr}=\frac{\text{ mass of }\mathrm{NaBr}}{\text{ molar mass of }\mathrm{NaBr}}$

$=\frac{75 \mathrm{g}}{102.89 \mathrm{g}/\mathrm{mol}}$

$=0.729 \mathrm{mol}$.

Step 3: Calculate the volume required by using the following expression :

Volume of $\mathrm{NaBr}=\frac{\text{ Moles of }\mathrm{NaBr}}{\text{ Molarity of }\mathrm{NaBr}}$

$=\frac{0.729 \mathrm{mol}}{1.50\mathrm{M}}$

$=0.486 \mathrm{L}\times \left(\frac{1000 \mathrm{mL}}{1 \mathrm{L}}\right)$

Therefore, the required volume of $NaBr$ solution is $486 ml$.