Q. 9.100 - An Introduction to General, Organic, and Biological Chemistry

Question

What is the molarity of a solution containing $15.6g of KCl$ in $274mL of KCl$solution? $(9.4)$

Step-by-Step Solution

Answer

The optimizer molarity is $0.77M KCl.$

Step 1: Given information

Given $15.6g KCl$ in a solution of $274mL=0.274.$

Molarity (moles/L) is required.

Compute molarity using the moles of $KCl$ and the quantity of the solution in litres.

$Molarity \left(M\right)=\frac{moles of solute }{liters of solution}$

$\mathrm{GKCl}\text{ Molar mass }=\frac{\text{ moles }KCl}{\text{ volume }\left(L\right)}=MKCl\text{ solution }$

Step 2: Explanation.

Factors,

$1 mole KCl = 74.6gKCl$

$\frac{1 mole KCl}{74.6gKCl} and \frac{74.6g KCl ssss}{1 mole KCl}$

Equation,

$moles KCl=15.6\cancel{gmL}\times \frac{1 mole KCl}{74.6\cancel{gmL}}=0.21 moles KCl$

Divide the molecules of KCl even by quantity in litres to get the molarity.

$Molarity=\frac{0.21moles KCl}{0.274L}=0.77M KCl$