Q. 9.96 - An Introduction to General, Organic, and Biological Chemistry

Question

An $80$-proof brandy is a $40.\% (v/v)$ ethanol solution. The "proof" is twice the percent concentration of alcohol in the beverage. How many milliliters of alcohol are present in $750 mL$ of brandy? $(9.4)$

Step-by-Step Solution

Answer

As an outcome, $750 mL$ of whiskey comprises $300. mL$ of ethyl alcohol.

Step 1: Introduction.

An acetic solution is a solvent primarily up of water and ethanol. Sweetener ingredients can ferment into drunken energy mixtures.

Step 1: Given data.

Using the volume percent phrase.

$Volume percent (\%v/v)=\frac{volume of solute}{volume of solution}\times 100\% ......\left(1\right)$

Step 3: Explanation.

We offer cognac with an ethyl alcohol by volume of $40.0\% (v/v)$. Now we need to figure out just how much alcohol is in $750 mL$ of whiskey.

In $100 ml$ of brandy, $40.0 mL$ of ethyl alcohol represents $40.0\% (v/v)$. As a result, measure the number of alcohol in $750 mL$ of champagne.

$\frac{40.0 mL of ethyl alcohol}{100 \cancel{mL of brandly}}\times 750 \cancel{mL of brandly}=300. mL of ethyl alcohol$

As a result, $750 mL$ of brandy includes $300. mL$ of ethyl alcohol.