Q. 9.95 - An Introduction to General, Organic, and Biological Chemistry

Question

How many milliliters of a $12\%(v/v)$ propyl alcohol solution would you need to obtain $4.5mL$of propyl alcohol?$(9.4)$

Step-by-Step Solution

Answer

As an outcome, $38 mL$ of $12(v/v)$ liquid is forced to hold $4.5mL$ of solute.

Step 1: Given information

The volume of solute absorbed in a 100 mL af mixture is the volume percent v/v. The formula for calculating volume percent is:

$volume percent(v/v)=\frac{volume solute }{volume of solution }\times 100$

$12\%(v/v)$ propyl alcohal indicates $12mL$ propyl alcohal in a solution of $100mL$.

The volume percent converts to a conversion factor of$\frac{12mL propyl alcohol}{100mL solution}$.

Step 2: Explanation.

Find the volume of a $12\%(v/v)$ solution having $4.5mL$ of propyl alcohol.

The volume of the solution is,

$=\cancel{4.5\mathrm{mL}\text{ propylatcohol }}\times \frac{100\mathrm{mL}\text{ solution }}{\cancel{12\mathrm{mLpropytatcohol} }}$

$=38mL solution.$

As a result, $38 mL$ of $12(v/v)$ solution is required to hold $4.5mL$ of solute.