Q. 7.33 - An Introduction to General, Organic, and Biological Chemistry

Question

Dinitrogen oxide (or nitrous oxide), ${\mathrm{N}}_2\mathrm{O}$, also known as laughing gas, is widely used as an anesthetic in dentistry. 

a. How many grams are in style="max-width: none; vertical-align: -4px;" $1.50$ moles of dinitrogen oxide? 

b. How many moles are in $34.0$ g of dinitrogen oxide?

Step-by-Step Solution

Answer

(a) The $66$ g is in $1.50$ mole of dinitrogen oxide

(b) The $0.772$ mole are in $34$ g of dinitrogen oxide

Part (a) Step 1: Given information

We need to find the mass in $1.50$ mole of dinitrogen oxide 

Part (a) Step 2: Simplify

We know that

A mole is equal to molar mass

And molar mass of dinitrogen oxide is, $44 \mathrm{g}/\mathrm{mol}$

Therefore, the mass in $1.50$ mole of dinitrogen oxide is, $44 \frac{\mathrm{g}}{\cancel{\mathrm{mol}}}\times 1.5 \cancel{\mathrm{mol}}=66 \mathrm{g}$

Part (b) Step 1: Given information

We need to find the no. of moles in $34$ g of dinitrogen oxide  

Part (b) Step 2: Simplify

We know that

A mole is equal to molar mass

And molar mass of dinitrogen oxide is, $44 \mathrm{g}/\mathrm{mol}$

Therefore, the no. of moles in $34$ g of dinitrogen oxide is, $\frac{34 \cancel{\mathrm{g}}}{44 {\displaystyle \raisebox{1ex}{$\cancel{\mathrm{g}}$}\!\left/ \!\raisebox{-1ex}{$\mathrm{mol}$}\right.}}=0.772 \mathrm{mol}$