Calculate the number of moles in each of the following: a. 82.0 g of Ag b . localid="1653462860909" 0.288 g of C c. localid="1653462869919" 15.0g of ammonia, NH3d. localid="1653462880276" 7.25 g of CH4 e. localid="1653462890852" 245 g of Fe2O3;

Q. 7.25 - An Introduction to General, Organic, and Biological Chemistry

Q. 7.25

Question

Calculate the number of moles in each of the following:

a. $82.0$ g of $A g$

b . $0.288$ g of $C$

c. $15.0$ g of ammonia, $N H_{3}$

d. $7.25$ g of $C H_{4}$

e. $245$ g of $F e_{2} O_{3}$ ;

Step-by-Step Solution

Verified

Answer

The number of moles in each of the following :

a. $0.766$ moles

b. $0.024$ moles

c. $0.882$ moles

d. $0.45$ moles

e. $1.53$ moles

1Part (a) Step 1: Given information

We need to find number of moles in $82$ g of $A g$ .

2Part (a) Step 2: Explanation

Here, we need to calculate number of moles , we will use the formula for number of moles;

We are given with the gram molecular weight , and we know the molar mass for this element , so we get ;

Number of moles=gram molecular weight/molar mass

So, number of moles= $\frac{82 g}{107.8 g / m o l e s} = 0.766$ moles

3Part (b) Step 1: Given information

We need to find number of moles of $0.288$ g of $C$ .

4Part (b) Step 2: Explanation

Here, we need to calculate number of moles , we will use the formula for number of moles;

We are given with the gram molecular weight , and we know the molar mass for this element , so we get ;

Number of moles=gram molecular weight/molar mass

number of moles= $\frac{0.288 g}{12 g / m o l e s} = 0.024$ moles

5Part (c) Step 1: Given information

We need to find number of moles of $15.0$ g of ammonia.

6Part (c) Step 2: Explanation

Here, we need to calculate number of moles , we will use the formula for number of moles;

We are given with the gram molecular weight , and we know the molar mass for this element , so we get ;

Number of moles=gram molecular weight/molar mass

number of moles = $\frac{15 g}{17 g / m o l e s} = 0.882$ moles

7Part (d) Step 1: Given information

We need to find number of moles of $7.25$ g of $C H_{4}$ .

8Part (d) Step 2: Explanation

We are given with the gram molecular weight , and we know the molar mass for this element , so we get ;

Here, we need to calculate number of moles , we will use the formula for number of moles

Number of moles=gram molecular weight/molar mass

number of moles = $\frac{7.25 g}{16 g / m o l e s} = 0.45$ moles

9Part (e) Step 1: Given information

We need to find number of moles of $245$ g of $F e_{2} O_{3}$ .

10Part (e) Step 2: Explanation

We are given with the gram molecular weight , and we know the molar mass for this element , so we get ;

Here, we need to calculate number of moles , we will use the formula for number of moles

Number of moles=gram molecular weight/molar mass

number of moles = $\frac{245 g}{159.69 g / m o l e s} = 1.53$ moles

Q. 7.3

Q. 7.32

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