Q. 7.32 - An Introduction to General, Organic, and Biological Chemistry

Question

a. Cyclopropane, ${\mathrm{C}}_3{\mathrm{H}}_6$, is an anesthetic given by inhalation. How many grams are in $0.25$ mole of cyclopropane?

b. The sedative Demerol hydrochloride has the formula $C_{15}{H}_{22}CIN{O}_2$. How many grams are in $0.025$ mole of Demerol hydrochloride?

Step-by-Step Solution

Answer

(a) The $10.5$ g are in $0.25$ mole of cyclopropane

(b) The $5.86$ g are in $0.025$ mole of Demerol hydrochloride

Part (a) Step 1: Given information

We need to find the mass in $0.25$ mole of cyclopropane

Part (a) Step 2: Simplify

We know that

A mole is equal to molar mass

And molar mass of cyclopropane is, $42 \mathrm{g}/\mathrm{mol}$

Therefore, the mass in $0.25$ mole of cyclopropane is, $42 \frac{\mathrm{g}}{\cancel{\mathrm{mol}}}\times 0.25 \cancel{\mathrm{mol}} =10.5 \mathrm{g}$

Part (b) Step 1: Given information

We need to find the mass in $0.025$ mole of Demerol hydrochloride  

Part (b) Step 2: Simplify

We know that

A mole is equal to molar mass

And molar mass of Demerol hydrochloride is, $234.3 \mathrm{g}/\mathrm{mol}$

Therefore, the mass in $0.025$ mole of Demerol hydrochloride  is, $234.3 \frac{\mathrm{g}}{\cancel{\mathrm{mol}}}\times 0.025 \cancel{\mathrm{mol}}=5.86 \mathrm{g}$