Q. 7.20 - An Introduction to General, Organic, and Biological Chemistry

Question

Calculate the molar mass for each of the following:

a. ${\mathrm{CaSO}}_4$, calcium sulfate, used to make casts to protect broken bones

b. ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$, Carboplatin, used in chemotherapy

c. ${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$, Propofol, used to induce anesthesia during surgery

Step-by-Step Solution

Answer

a. The molar mass of ${\mathrm{CaSO}}_4$ is $136.10 \mathrm{g}$

b. The molar mass of ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$ is $371.11 \mathrm{g}$

c. The molar mass of ${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$ is $178.11 \mathrm{g}$

Part (a) Step 1 : Given information

We have to find the molar mass of ${\mathrm{CaSO}}_4$

Part (a) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{Ca}$ atom = $40.08 \mathrm{g}$

Molar mass of one $\mathrm{S}$ atom = $32.06 \mathrm{g}$

Molar mass of one $\mathrm{O}$ atom = $15.99 \mathrm{g}$

So, the molar mass of ${\mathrm{CaSO}}_4$ = $40.08 + 32.06 + 4\left(15.99\right)$ = $136.10 \mathrm{g}$

Part (b) Step 1 : Given information

We have to find the molar mass of ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$

Part (b) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{C}$ atom = $12.01 \mathrm{g}$

Molar mass of one $\mathrm{H}$ atom = $1.00 \mathrm{g}$

Molar mass of one $\mathrm{N}$ atom = $14.00 \mathrm{g}$

Molar mass of one $\mathrm{O}$ atom = $15.99 \mathrm{g}$

Molar mass of one $\mathrm{Pt}$ atom = $195.09 \mathrm{g}$

So, the molar mass of ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{N}}_2{\mathrm{O}}_4\mathrm{Pt}$ = $6\left(12.01\right) + 12\left(1.00\right) + 2\left(14.00\right) + 4\left(15.99\right) + 195.09$ 

                                                                = $371.11 \mathrm{g}$

Part (c) Step 1 : Given information

We have to find the molar mass of ${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$

Part (c) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{C}$ atom = $12.01 \mathrm{g}$

Molar mass of one $\mathrm{H}$ atom = $1.00 \mathrm{g}$

Molar mass of one $\mathrm{O}$ atom = $15.99 \mathrm{g}$

So, the molar mass of ${\mathrm{C}}_{12}{\mathrm{H}}_{18}\mathrm{O}$ = $12\left(12.01\right) + 18\left(1.00\right) + 15.99$ = $178.11 \mathrm{g}$