Q. 7.21 - An Introduction to General, Organic, and Biological Chemistry

Question

 Calculate the mass, in grams, for each of the following:

 a.$1.50$ moles of $Na$ 

b. $2.80$ moles of $Ca$

c.$0.125$ mole of$C{O}_2$ 

d. $0.0485$mole of $N{a}_{2}C{O}_3$

e. $7.14 x {10}^2$moles of $PC{I}_3$

Step-by-Step Solution

Answer

  The mass in gram for each of following is :

a. $1.50$ moles of $Na$ is $34.5$ g

b. $2.80$ moles of  $Ca$is $117$ g

c. $0.125$ mole of $C{O}_2$ is $5.50$g 

d. $0.0485$ mole of  $N{a}_{2}C{O}_3$     is $5.141$g 

e. $7.14\times {10}^2$ moles of $PC{l}_3$ is$98053.6$ g

Part (a) Step 1: Given information

We have  to find  that how much is the the mass in grams  for  $1.50$ moles of $Na$ 

Part (a) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$ mole  is $22.9$g

Therefore mass of $1.5$ mole = $1.5 \cancel{moles}\times 22.9 \frac{g}{\cancel{moles}}=34.5$g

Part (b) Step 1: Given information

We have  to find  that how much is the the mass in grams  for $2.80$  moles of $Ca$

Part (b) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$mole  is $40.078$g

Therefore mass of $2.8$moles is $2.80 \cancel{moles}\times 40.078 \frac{g}{\cancel{moles}}=117$g

Part (c) Step 1: Given information

We have  to find  that how much is the the mass in grams  for $0.125$ mole of $C{O}_2$ 

Part (c) Step 2: Explanation

Here $1$ mole is atomic mass of substance expressed in grams .

mass of $1$mole  is $44.01$ u

Therefore mass of $0.125$moles is   $44.01 \frac{g}{\cancel{moles}}\times 0.125 \cancel{moles}=5.50$ g

Part (d) Step 1: Given information

We have  to find  that how much is the the mass in grams  for $0.0485$ mole of  $N{a}_{2}C{O}_3$

Part (d) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$ mole is $106$g/moles

therefore mass of $0.0485$ moles is $106 \frac{g}{\cancel{moles}}\times 0.0485 \cancel{moles}=5.141$ g

Part (e) Step 1: Given information

We have  to find  that how much is the the mass in grams  for $7.14\times {10}^2$ moles of $PC{l}_3$

Part (e) Step 2: Explanation

Here $1$mole is atomic mass of substance expressed in grams .

mass of $1$ mole is $137.33$ g/mol

137.33 Therefore mass of $7.14 \times {10}^2$ moles is $7.14\times 10\cancel{{}^2 moles}\times 137.33 \frac{g}{\cancel{moles}}=98053.62$g