Q. 7.19 - An Introduction to General, Organic, and Biological Chemistry

Question

Calculate the molar mass for each of the following:

a. ${\mathrm{C}}_8{\mathrm{H}}_9{\mathrm{NO}}_2$, acetaminophen used in Tylenol

b. ${\mathrm{Ca}}_3{\left({\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{O}}_7\right)}_2$, calcium supplement

c. ${\mathrm{C}}_{17}{\mathrm{H}}_{18}{\mathrm{FN}}_3{\mathrm{O}}_3$, Cipro, used to treat a range of bacterial infections

Step-by-Step Solution

Answer

a. The molar mass of ${\mathrm{C}}_8{\mathrm{H}}_9{\mathrm{NO}}_2$ is $151.06 \mathrm{g}$

b. The molar mass of ${\mathrm{Ca}}_2{\left({\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{O}}_7\right)}_2$ is $498.22 \mathrm{g}$

c. The molar mass of ${\mathrm{C}}_{17}{\mathrm{H}}_{18}{\mathrm{FN}}_3{\mathrm{O}}_3$ is $331.13 \mathrm{g}$

Part (a) Step 1 : Given information

We have to find the molar mass of ${\mathrm{C}}_8{\mathrm{H}}_9{\mathrm{NO}}_2$

Part (a) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{C}$ atom = $12.01 \mathrm{g}$

Molar mass of one $\mathrm{H}$ atom = $1.00 \mathrm{g}$

Molar mass of one $\mathrm{N}$ atom = $14.00 \mathrm{g}$

Molar mass of one $\mathrm{O}$ atom = $15.99 \mathrm{g}$

So, the molar mass of ${\mathrm{C}}_8{\mathrm{H}}_9{\mathrm{NO}}_2$ = $8\left(12.01\right) + 9\left(1.00\right) + 14.00 + 2\left(15.99\right)$ = $151.06 \mathrm{g}$

Part (b) Step 1 : Given information

We have to find the molar mass of ${\mathrm{Ca}}_3{\left({\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{O}}_7\right)}_2$

Part (b) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{Ca}$ atom = $40.08 \mathrm{g}$

Molar mass of one $\mathrm{C}$ atom = $12.01 \mathrm{g}$

Molar mass of one $\mathrm{H}$ atom = $1.00 \mathrm{g}$

Molar mass of one $\mathrm{O}$ atom = $15.99 \mathrm{g}$

So, the molar mass of ${\mathrm{Ca}}_3{\left({\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{O}}_7\right)}_2$ = $3\left(40.08\right) + 12(12.01) + 10\left(1.00\right) + 14\left(15.99\right)$

                                                                    = $498.22 \mathrm{g}$

Part (c) Step 1 : Given information

We have to find the molar mass of ${\mathrm{C}}_{17}{\mathrm{H}}_{18}{\mathrm{FN}}_3{\mathrm{O}}_3$

Part (c) Step 2 : Simplification

We know that,

Molar mass of one $\mathrm{C}$ atom = $12.01 \mathrm{g}$

Molar mass of one $\mathrm{H}$ atom = $1.00 \mathrm{g}$

Molar mass of one $\mathrm{F}$ atom = $18.99 \mathrm{g}$$18.99g$

Molar mass of one $\mathrm{N}$ atom = $14.00 \mathrm{g}$

Molar mass of one $\mathrm{O}$ atom = $15.99 \mathrm{g}$

So. the molar mass of ${\mathrm{C}}_{17}{\mathrm{H}}_{18}{\mathrm{FN}}_3{\mathrm{O}}_3$ = $17\left(12.01\right) + 18\left(1.00\right) + 18.99 + 3\left(14.00\right) + 3\left(15.99\right)$

                                                                   = $331.13 \mathrm{g}$