Q 6.30TI - Intermediate Algebra

Question

Factor completely using trial and error: $4b^2+5b+1$

Step-by-Step Solution

Answer

The factored form is $(4b+1)(b+1)$

Step 1: Given information

Given the polynomial $4b^2+5b+1$

Step 2: Write the factors of the first term

The first term is $4b^2$ the factors are $4b,1b$, putting in parentheses, we get

$(4b )(b )$

Step 3: Calculating the factors of the third term

The third term is $1$, the factors are $1$ so the combinations are $4,1$ so we have

$(4b+1)(b+1)=4b^2+5b+1$