Q 6.32TI - Intermediate Algebra

Question

Factor completely using trial and error: $10y^2-37y+7$

Step-by-Step Solution

Answer

The factored form is $10y^2-37y+7$

Step 1: Given information

Given the polynomial $10y^2-37y+7$

Step 2: Calculate the factors of first term

The first term is $10y^2$ so the factors is $5y,2y$ so writing in parentheses, we get

$(5y )(2y )$

Step 3: Factors of the third term

The third term is $7$ so the factors is $1,7$ so the combination is $35,2$ so we have

$(5y-1)(2y-7)=10y^2-37y+7$