Q 6.28TI - Intermediate Algebra

Question

Factor completely, $6y^3+18y^2-60y$

Step-by-Step Solution

Answer

The factored form is $6y(y-2)(y+5)$

Step 1: Given information

Given polynomial $6y^3+18y^2-60y$

Step 2: Calculate the GCF and factor it

The GCF is $6y$ so factoring it, we get

$6y(y^2+3y-10)$

Step 3: Create the factor table for the trinomial

The table is 

Factors of $-10$	Sum of factors
$1,10$	$1+10=11$
$5,-2$	$5-2=3$

Step 4: Substitute the values to form the factored form

The factored form is $6y(y-2)(y+5)$