Q. 311 - Intermediate Algebra

Question

Divide each polynomial by the binomial. 

$\left(2n^3-10n+28\right)÷\left(n+3\right)$

Step-by-Step Solution

Answer

The solution is $\left(2n^2-6n+8+\frac{4}{n+3}\right)$.

Step 1. Given information

Polynomial: $2n^3-10n+28$

Binomial: $n+3$

Step 2. Calculation

Using long division - 

          $2n^2-6n+8+\frac{4}{n+3}$

$n+3 \overline{)2n^3-10n+28 }$

          $2n^3+6n^2$

            $\overline{ -6n^2-10n+28 }$

                $-6n^2-18n$

                  $\overline{ 8n+28}$

                                $8n+24$

                                 $\overline{ 4}$