Q. 310 - Intermediate Algebra

Question

Divide each polynomial by the binomial. 

$\left(3b^3+b^2+4\right)÷\left(b+1\right)$

Step-by-Step Solution

Answer

The solution is $\left(3b^2-2b+2+\frac{2}{b+1}\right)$.

Step 1. Given information

Polynomial: $3b^3+b^2+4$

Binomial: $b+1$

Step 2. Calculation

Using long division - 

         $3b^2-2b+2+\frac{2}{b+1}$

$b+1 \overline{)3b^3+b^2+4 }$

          $3b^3+3b^2$

          $\overline{ -2b^2+4 }$

                $-2b^2-2b$

                  $\overline{ 2b+4 }$

                             $2b+2$

                             $\overline{ 2 }$