Problem 96
Question
determine whether each statement makes sense or does not make sense, and explain your reasoning. Find the area of the donut-shaped region bounded by the graphs of \((x-2)^{2}+(y+3)^{2}=25 \quad\) and \((x-2)^{2}+(y+3)^{2}=36\)
Step-by-Step Solution
Verified Answer
The area of the donut-shaped region bounded by the two given circles is \(11\pi\).
1Step 1: Area formula
Recall the formula for the area of a circle: \(\pi r^{2}\), where \(r\) is the radius of the circle. This will be essential for finding the areas of the two given circles.
2Step 2: Find the radii
The equations of the circles are given in the format \((x-h)^{2}+(y-k)^{2}=r^{2}\), where \((h,k)\) is the center of the circle and \(r\) is the radius. From the equations, it can be inferred that the radii of the two circles are \(r_{1}=\sqrt{25}=5\) and \(r_{2}=\sqrt{36}=6\).
3Step 3: Find the areas of the circles
Using the area formula, find the area of both circles. The area of the first circle is \(\pi\cdot5^{2}=25\pi\) and the area of the second circle is \(\pi\cdot6^{2}=36\pi\).
4Step 4: Find the area of the donut-shaped region
Subtract the area of the smaller circle from the area of the larger circle to find the area of the donut-shaped region. Hence, the area is \(36\pi - 25\pi = 11\pi\).
Key Concepts
Circle equationsRadius of a circleArea of a circle
Circle equations
In mathematics, circles are defined by equations that describe every single point along the curve. A general equation for a circle is
In the given exercise, both circles have equations centered at
The circle's radius affects its size, resulting in a larger or smaller circle. Circle equations are foundational in understanding the shape and layout of circles in geometry.
- \((x-h)^2 + (y-k)^2 = r^2\)
- \(h\) and \(k\) represent the center coordinates of the circle.
- \(r\) is the radius.
In the given exercise, both circles have equations centered at
- \((x-2)^2 + (y+3)^2 = 25\) and
- \((x-2)^2 + (y+3)^2 = 36\).
The circle's radius affects its size, resulting in a larger or smaller circle. Circle equations are foundational in understanding the shape and layout of circles in geometry.
Radius of a circle
The radius is a key component in understanding circles. It is the distance from the center of the circle to any point on its circumference.
To find the radius in a circle equation, you can follow this simple rule: take the square root of the number on the right side of the equation.
For example, if we have the equation
Knowing the radius helps us calculate the area, which leads directly to understanding any donut-shaped region between two circles.
To find the radius in a circle equation, you can follow this simple rule: take the square root of the number on the right side of the equation.
For example, if we have the equation
- \((x-2)^2 + (y+3)^2 = 25\)
- \(\sqrt{25} = 5\)
- \((x-2)^2 + (y+3)^2 = 36\)
- \(\sqrt{36} = 6\)
Knowing the radius helps us calculate the area, which leads directly to understanding any donut-shaped region between two circles.
Area of a circle
The area of a circle shows how much space it occupies. The formula to find this area is straightforward:
So, if you have a radius, you can find the area by squaring it and multiplying the result by \(\pi\).
For instance, in our exercise, given the first circle:
This is found by subtracting the area of the smaller circle from the larger one:
- \(\pi r^2\)
So, if you have a radius, you can find the area by squaring it and multiplying the result by \(\pi\).
For instance, in our exercise, given the first circle:
- Radius = 5, Area = \(\pi \times 5^2 = 25\pi\)
- Radius = 6, Area = \(\pi \times 6^2 = 36\pi\)
This is found by subtracting the area of the smaller circle from the larger one:
- \(36\pi - 25\pi = 11\pi\)
Other exercises in this chapter
Problem 95
Begin by graphing the standard cubic function, \(f(x)=x^{3} .\) Then use transformations of this graph to graph the given function. $$g(x)=x^{3}-3$$
View solution Problem 95
Explain how to derive the slope-intercept form of a line's equation, \(y=m x+b,\) from the point-slope form $$y-y_{1}=m\left(x-x_{1}\right)$$
View solution Problem 96
let \(f\) and \(g\) be defined by the following table: $$ \begin{array}{ccc} \hline x & f(x) & g(x) \\ \hline-2 & 6 & 0 \\ -1 & 3 & 4 \\ 0 & -1 & 1 \\ 1 & -4 &
View solution Problem 96
Show that $$f(x)=\frac{3 x-2}{5 x-3}$$
View solution