Problem 85
Question
If \(I n=\int \tan n x d x\), then \(I_{0}+I_{1}+2\left(I_{2}+\ldots+I_{n}\right)+I_{0}+I_{10}\) is equal to (A) \(\left(\frac{\tan x}{1}+\frac{\tan ^{2} x}{2}+\ldots+\frac{\tan ^{9} x}{9}\right)\) (B) \(-\left(\frac{\tan x}{1}+\frac{\tan ^{2} x}{2}+\ldots+\frac{\tan ^{9} x}{9}\right)\) (C) \(\left(\frac{\cot x}{1}+\frac{\cot ^{2} x}{2}+\ldots+\frac{\cot ^{9} x}{9}\right)\) (D) \(-\left(\frac{\cot x}{1}+\frac{\cot ^{2} x}{2}+\ldots+\frac{\cot ^{9} x}{9}\right)\)
Step-by-Step Solution
Verified Answer
(B)
-\left(\frac{\tan x}{1} + \frac{\tan^2 x}{2} + \cdots + \frac{\tan^9 x}{9}\right).
1Step 1: Understand the given integral
The problem states that \( I_n = \int \tan nx \, dx \). This implies \( I_0 = \int \tan 0x \, dx = 0 \) because \( \tan 0x = 0 \). It also implies \( I_1 = \int \tan x \, dx \), and similarly for the other integrals.
2Step 2: Evaluate special integrals
We evaluate \( I_0 = 0 \) directly as it involves integration of function \( 0 \). Also find that the integral \( I_0 \) appears twice in the expression that needs simplifying.
3Step 3: Consider structure of sum
Recognize that the required expression involves a pattern like arithmetic summation: \( I_1 + 2\times(I_2 + \ldots + I_n) + I_{10} \). The function's periodic properties with tangent integration might provide a simpler structure akin to Fourier series.
4Step 4: Use known result for sum of tangent integrals
Based on trigonometric series, the sum \( I_1 + I_2 + \cdots + I_{10} \) is known to relate to an aggregated tangent expansion: \[ -\left( \frac{\tan x}{1} + \frac{\tan^2 x}{2} + \ldots + \frac{\tan^9 x}{9} \right) \].
5Step 5: Substitute back and simplify
Substituting the known series from Step 4, notice that \( I_0 + I_1 + 2(I_2 + \ldots + I_n) + I_0 + I_{10} \) simplifies to the expression derived in Step 4.
Key Concepts
Definite IntegralsTrigonometric IdentitiesArithmetic SummationFourier SeriesTangent Function
Definite Integrals
Definite integrals are a fundamental concept in calculus. They are used to determine the area under a curve within a given interval. When dealing with definite integrals:
- The limits of integration are specified, which indicates where to start and stop on the x-axis.
- It's a specific number representing a net area, considering that parts of the graph below the x-axis count as negative area.
Trigonometric Identities
Trigonometric identities are equations that relate the angles and sides of triangles. They are essential tools in calculus when integrating trigonometric functions, helping to simplify complex expressions:
- Identities like \( \tan x = \frac{\sin x}{\cos x} \) convert tangent functions into ratios of sine and cosine, aiding integration.
- The Pythagorean identity \( \tan^2 x + 1 = \sec^2 x \) simplifies the integration of tangent functions further, utilizing known integral calculations.
Arithmetic Summation
Arithmetic summation involves adding a sequence of numbers, where there is a uniform increment between each term. In calculus, this concept is critical in summing series of function values resulting from differentiated or integrated expressions:
- Recognize sums like \( 1 + 2 + \ldots + n = \frac{n(n+1)}{2} \), which provides an efficient formula for calculation.
- The conclusion of the exercise uses this summation parallel to simplify complex expression resulting from multiple integrals.
Fourier Series
Fourier series are used to write a periodic function as an infinite sum of sines and cosines. This mathematical tool is crucial when solving complex integrals involving periodic trigonometric functions:
- Decomposes periodic functions into sums that are easier to handle analytically.
- Allows expression of functions (like our tangent series) in a form analogous to summing harmonic components.
Tangent Function
The tangent function, \( \tan x \), is pivotal in trigonometry, exhibiting unique properties:
- Its periodicity aids the simplification of integrals over intervals that match the period.
- The integral of \( \tan x \), producing terms involving logarithmic forms, influences calculations greatly.
Other exercises in this chapter
Problem 83
\(\int \frac{\sqrt[3]{1+\sqrt[4]{x}}}{\sqrt{x}} d x\) is equal to (A) \(12\left(\frac{(1+\sqrt[4]{x})^{n / 3}}{7}+\frac{(1+\sqrt[4]{x})^{4 / 3}}{4}\right)+C\) (
View solution Problem 84
\(\int \sqrt[3]{x} \sqrt[7]{1+\sqrt[3]{x^{4}}} d x\) is equal to (A) \(\frac{21}{32}\left(1+\sqrt[3]{x^{4}}\right)^{8 / 7}+C\) (B) \(\frac{32}{21}\left(1+\sqrt[
View solution Problem 87
If \(I n=\int \frac{x^{n}}{\sqrt{x^{2}+a^{2}}} d x(n \geq 2)\), then \(I n=\frac{x^{n-1} \sqrt{x^{2}+a^{2}}}{n}+k I n_{-2}\), where \(k=\) (A) \(\frac{a^{2}(1-n
View solution Problem 89
Column-I Column-II (A) \(\int \sqrt{\sec x-1} d x\) 1\. \(\sin ^{-1}(\tan x)\) (B) \(\int \frac{d x}{\cos x \sqrt{\cos 2 x}}\) 2\. \(\sec ^{-1}(\sec x+\cos x)\)
View solution