Problem 84
Question
\(\int \sqrt[3]{x} \sqrt[7]{1+\sqrt[3]{x^{4}}} d x\) is equal to (A) \(\frac{21}{32}\left(1+\sqrt[3]{x^{4}}\right)^{8 / 7}+C\) (B) \(\frac{32}{21}\left(1+\sqrt[3]{x^{4}}\right)^{8 / 7}+C\) (C) \(\frac{7}{32}\left(1+\sqrt[3]{x^{4}}\right)^{8 / 7}+C\) (D) none of these
Step-by-Step Solution
Verified Answer
Option (A): \( \frac{21}{32}(1+\sqrt[3]{x^{4}})^{8/7} + C \) is correct.
1Step 1: Substitution Setup
To simplify the integral, start by making a substitution. Let's set \( u = 1 + \sqrt[3]{x^4} \). Differentiate both sides to find an expression for \( du \). This gives us \( du = \frac{4}{3} x^{1/3} \, dx \). Thus, \( x^{1/3} \, dx = \frac{3}{4} \, du \).
2Step 2: Rewrite the Integral
Substitute \( u \) and \( du \) into the integral. The original integral becomes \( \int x^{1/3} \sqrt[7]{1 + x^{4/3}} \, dx = \int \frac{3}{4} u^{1/7} \, du \) after substitution.
3Step 3: Integration
Now integrate \( \int \frac{3}{4} u^{1/7} \, du \). This can be integrated using the power rule: \( \frac{3}{4} \cdot \frac{u^{1/7 + 1}}{1/7 + 1} \). Simplify the exponent: \( 1/7 + 1 = 8/7 \), and thus the integral becomes \( \frac{3}{4} \cdot \frac{7}{8} u^{8/7} + C \).
4Step 4: Simplify the Expression
The expression simplifies to \( \frac{21}{32} u^{8/7} + C \), where \( u = 1 + \sqrt[3]{x^4} \). Thus, substituting back for \( u \), the solution is \( \frac{21}{32} (1 + \sqrt[3]{x^4})^{8/7} + C \).
5Step 5: Select the Correct Option
Compare the simplified integral solution to the options provided. The solution \( \frac{21}{32}(1+\sqrt[3]{x^{4}})^{8/7} + C \) matches option (A).
Key Concepts
Substitution MethodIntegration by PartsPower Rule in Integration
Substitution Method
The Substitution Method in integration is a powerful tool to simplify complex integrals, especially those involving composite functions. This approach works by substituting a part of the integral with a new variable to transform it into a simpler form.
In our exercise, the substitution is key to simplifying the integral \(\int \sqrt[3]{x} \sqrt[7]{1+\sqrt[3]{x^{4}}} \, dx\). Here, we set \(u = 1 + \sqrt[3]{x^{4}}\). This clever substitution targets the composite part \(\sqrt[7]{1+\sqrt[3]{x^{4}}}\), making the integration more straightforward.
To proceed, differentiate \(u\) with respect to \(x\) to find an expression for \(du\). This gives \(du = \frac{4}{3} x^{1/3} \, dx\), which implies \(x^{1/3} \, dx = \frac{3}{4} \, du\). With this substitution, the original integral becomes significantly simpler.
In our exercise, the substitution is key to simplifying the integral \(\int \sqrt[3]{x} \sqrt[7]{1+\sqrt[3]{x^{4}}} \, dx\). Here, we set \(u = 1 + \sqrt[3]{x^{4}}\). This clever substitution targets the composite part \(\sqrt[7]{1+\sqrt[3]{x^{4}}}\), making the integration more straightforward.
To proceed, differentiate \(u\) with respect to \(x\) to find an expression for \(du\). This gives \(du = \frac{4}{3} x^{1/3} \, dx\), which implies \(x^{1/3} \, dx = \frac{3}{4} \, du\). With this substitution, the original integral becomes significantly simpler.
- Identify the composite part of the function.
- Choose a substitution that simplifies this part.
- Convert the entire integral in terms of the new variable.
- Solve the transformed integral using standard methods.
Integration by Parts
Integration by Parts is a technique based on the product rule of differentiation, used when integrating products of functions. However, it's not directly applicable in our exercise. Still, understanding this method provides deeper insights into integration techniques.
The identity for Integration by Parts is:\[\int u \, dv = uv - \int v \, du\] To use Integration by Parts:
The identity for Integration by Parts is:\[\int u \, dv = uv - \int v \, du\] To use Integration by Parts:
- Select functions \(u\) and \(dv\) from your integral.
- Differentiate \(u\) to get \(du\), and integrate \(dv\) to find \(v\).
- Substitute into the formula to solve the integral.
Power Rule in Integration
The Power Rule in Integration is a fundamental technique used for integrating functions of the form \(x^n\). This rule transforms the function into a more straightforward expression by raising the power by one and dividing by the new power.
The rule states:\[\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\] This is applied to functions where \(n eq -1\). In the exercise, after substitution leads to \(\int \frac{3}{4} u^{1/7} \, du\), we apply the Power Rule to find the integral.
For \(u^{1/7}\), increase the exponent by 1 to get \(u^{8/7}\) and divide by this new exponent:\[\frac{3}{4} \cdot \frac{u^{8/7}}{8/7} + C = \frac{3}{4} \cdot \frac{7}{8} u^{8/7} + C\]Simplifying gives \(\frac{21}{32} u^{8/7} + C\).
The rule states:\[\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\] This is applied to functions where \(n eq -1\). In the exercise, after substitution leads to \(\int \frac{3}{4} u^{1/7} \, du\), we apply the Power Rule to find the integral.
For \(u^{1/7}\), increase the exponent by 1 to get \(u^{8/7}\) and divide by this new exponent:\[\frac{3}{4} \cdot \frac{u^{8/7}}{8/7} + C = \frac{3}{4} \cdot \frac{7}{8} u^{8/7} + C\]Simplifying gives \(\frac{21}{32} u^{8/7} + C\).
- Identify the power of \(x\) or \(u\) in your integral.
- Apply the Power Rule to integrate.
- Simplify the result.
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