Problem 7
Question
In Exercises \(7-11\), a mountain climber is scaling a 400 -foot cliff. The climber starts at the bottom at \(t=0\) and climbs at a constant rate of 124 feet per hour. What is the slope in the linear model for the situation?
Step-by-Step Solution
Verified Answer
The slope in the linear model for this situation is 124 feet per hour.
1Step 1: Understand the concept of slope
In a linear model, the slope of the line represents the rate of change. In the context of this problem, the mountain climber is climbing at a constant rate. This rate of climb is the slope of the linear model.
2Step 2: Identify the rate of change
The problem states that the mountain climber is climbing the cliff at a constant rate of 124 feet per hour. This will be used as the slope in the linear model.
3Step 3: Formulate the slope
In a linear model, the slope is formulated as the ratio of 'rise over run' which represents the rate of change. In this situation, the 'rise' represents the change in height (in feet), and the 'run' is the change in time (in hours). Using the constant rate of climbing, the slope will be \(124 feet/hour\).
Key Concepts
Rate of ChangeSlopeConstant Rate
Rate of Change
The rate of change is a fundamental concept in mathematics, especially when discussing linear equations. It essentially tells us how one quantity changes in relation to another. In the context of our mountain climber scenario, the rate of change signifies how fast or slow the climber is ascending the cliff. It is calculated using the linear relationship between the distance climbed and the time taken.
The formula for determining the rate of change is straightforward. It is the change in one variable divided by the change in another, typically written as \( \frac{\Delta y}{\Delta x} \). Here, \( \Delta y \) represents the change in height (the vertical distance climbed), and \( \Delta x \) represents the change in time (how long it's been since the climbing started).
In most real-world problems, including our climbing example, the rate of change is usually constant, such as climbing at a dependable pace of 124 feet per hour.
The formula for determining the rate of change is straightforward. It is the change in one variable divided by the change in another, typically written as \( \frac{\Delta y}{\Delta x} \). Here, \( \Delta y \) represents the change in height (the vertical distance climbed), and \( \Delta x \) represents the change in time (how long it's been since the climbing started).
In most real-world problems, including our climbing example, the rate of change is usually constant, such as climbing at a dependable pace of 124 feet per hour.
Slope
In most linear models, the slope is what gives the line its steepness and direction. It's an essential part of any linear equation, often symbolized as \( m \) in the slope-intercept formula \( y = mx + b \).
For the mountain climber, the slope is a reflection of the climbing rate, which in this case is a constant 124 feet per hour. This slope tells us that for every hour the climber ascends, they will have climbed 124 feet. The slope is then calculated as a ratio of the 'rise'—the vertical movement in feet—and the 'run'—the horizontal change in time in hours.
Understanding slope allows us to interpret the rate at which changes occur in linear relationships. So, in our climbing scenario, it is both a rate and a slope given that they are the same in this linear context, 124 feet per hour is both the constant climb rate and the slope. This understanding is crucial when solving linear problems and developing models that predict future behavior.
For the mountain climber, the slope is a reflection of the climbing rate, which in this case is a constant 124 feet per hour. This slope tells us that for every hour the climber ascends, they will have climbed 124 feet. The slope is then calculated as a ratio of the 'rise'—the vertical movement in feet—and the 'run'—the horizontal change in time in hours.
Understanding slope allows us to interpret the rate at which changes occur in linear relationships. So, in our climbing scenario, it is both a rate and a slope given that they are the same in this linear context, 124 feet per hour is both the constant climb rate and the slope. This understanding is crucial when solving linear problems and developing models that predict future behavior.
Constant Rate
The term constant rate is exactly as it sounds—a rate that doesn't change over time. In the case of our mountain climber, a constant rate of 124 feet per hour means that every hour, the climber climbs exactly 124 feet, consistently, without variation.
This concept is fundamental in linear equations since it ensures that the graph of the equation forms a straight line—a direct characteristic of constant rates. If the rate changes, the line becomes curved, no longer linear. Linear equations come into play extensively in analyses where prediction, consistency, and reliability of pattern behaviors are necessary.
Having a constant rate is like having cruise control on your climbing pace. It ensures predictability and stability, making it easier to calculate progress. For students learning about linear equations, mastering the idea of constant rate can significantly ease understanding of more complex mathematical concepts related to functional relationships.
This concept is fundamental in linear equations since it ensures that the graph of the equation forms a straight line—a direct characteristic of constant rates. If the rate changes, the line becomes curved, no longer linear. Linear equations come into play extensively in analyses where prediction, consistency, and reliability of pattern behaviors are necessary.
Having a constant rate is like having cruise control on your climbing pace. It ensures predictability and stability, making it easier to calculate progress. For students learning about linear equations, mastering the idea of constant rate can significantly ease understanding of more complex mathematical concepts related to functional relationships.
Other exercises in this chapter
Problem 6
Determine whether the equation is in slope-intercept form. $$ x+23 y=-15 $$
View solution Problem 6
Write in slope-intercept form the equation of the line that passes through the given points. $$ (-1,1) \text { and }(2,5) $$
View solution Problem 7
Write the equation of the line passing through the two points. Show that this line is perpendicular to the given line. $$ (-3,0),(3,6) ; y=-x-2 $$
View solution Problem 7
Write in standard form an equation of the line that passes through the given point and has the given slope. Use integer coefficients. \((1,-2), m=5\)
View solution