Problem 6
Question
Write in slope-intercept form the equation of the line that passes through the given points. $$ (-1,1) \text { and }(2,5) $$
Step-by-Step Solution
Verified Answer
The equation of the line that passes through the points (-1,1) and (2,5) is \(y = \frac{4}{3}x + \frac{7}{3}\).
1Step 1: Find the Slope
The formula for finding the slope between two points \((x_{1},y_{1})\) and \((x_{2},y_{2})\) is given by: \(m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\). Substitute the given points \((-1,1)\) and \((2,5)\) to find the slope. So, \(m = \frac{5-1}{2-(-1)} = \frac{4}{3}\).
2Step 2: Find the Intercept
To find the y-intercept, substitute the slope and one of the points into the slope-intercept form. Let's use the point \((-1,1)\). Plugging these values into the equation gives: \(1 = \frac{4}{3}* -1 + b\). Solving for \(b\) gives \(b = \frac{7}{3}\).
3Step 3: Write the Equation in Slope-Intercept Form
Finally, substitute the values for \(m\) and \(b\) back into the slope-intercept equation to get the desired equation in slope-intercept form: \(y = \frac{4}{3}x + \frac{7}{3}\).
Key Concepts
Equation of a LineFinding SlopeY-intercept
Equation of a Line
The equation of a line is a fundamental concept in algebra that helps us describe how two variables are related on a coordinate plane. The most common form of a linear equation is the slope-intercept form, written as:
\[ y = mx + b \] Here, \(y\) represents the dependent variable, \(x\) is the independent variable, \(m\) is the slope of the line, and \(b\) is the y-intercept.
\[ y = mx + b \] Here, \(y\) represents the dependent variable, \(x\) is the independent variable, \(m\) is the slope of the line, and \(b\) is the y-intercept.
- The slope \(m\) shows the steepness or incline of the line.
- The y-intercept \(b\) indicates where the line crosses the y-axis.
Finding Slope
Finding the slope of a line is a crucial step in creating its equation. The slope tells us how much \(y\) changes for a given change in \(x\). To find the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\), use the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]This formula calculates the 'rise' (change in \(y\)) over the 'run' (change in \(x\)).
In the problem, using points \((-1,1)\) and \((2,5)\), we compute:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]This formula calculates the 'rise' (change in \(y\)) over the 'run' (change in \(x\)).
In the problem, using points \((-1,1)\) and \((2,5)\), we compute:
- \(y_2 - y_1 = 5 - 1 = 4\)
- \(x_2 - x_1 = 2 - (-1) = 3\)
- Therefore, \(m = \frac{4}{3}\)
Y-intercept
The y-intercept is where the line crosses the y-axis, and it plays a key role in defining the line's equation. To find the y-intercept \(b\), use the slope-intercept formula after finding the slope:
Start with:\[ y = mx + b \]Substitute the slope and one point's coordinates into the equation.
For example, with point \((-1, 1)\) and slope \(\frac{4}{3}\):
Start with:\[ y = mx + b \]Substitute the slope and one point's coordinates into the equation.
For example, with point \((-1, 1)\) and slope \(\frac{4}{3}\):
- Set \(1 = \frac{4}{3}(-1) + b\)
- This simplifies to \(1 = -\frac{4}{3} + b\)
- Solving gives \(b = \frac{7}{3}\)
Other exercises in this chapter
Problem 6
Write in standard form an equation of the line that passes through the given point and has the given slope. Use integer coefficients. \((3,4), m=-4\)
View solution Problem 6
Determine whether the equation is in slope-intercept form. $$ x+23 y=-15 $$
View solution Problem 7
In Exercises \(7-11\), a mountain climber is scaling a 400 -foot cliff. The climber starts at the bottom at \(t=0\) and climbs at a constant rate of 124 feet pe
View solution Problem 7
Write the equation of the line passing through the two points. Show that this line is perpendicular to the given line. $$ (-3,0),(3,6) ; y=-x-2 $$
View solution