Problem 7
Question
If \(\lim _{x \rightarrow a+} f(x)=l=\lim _{x \rightarrow a-} g(x)\) and \(\lim _{x \rightarrow a-} f(x)=m=\) \(g(x)\), then the function \(f(x) \cdot g(x)\) (A) is not continuous at \(x=a\) (B) has a limit when \(x \rightarrow a\) and it is equal to \(l \mathrm{~m}\) (C) is continuous at \(x=a\) (D) has a limit when \(x \rightarrow a\) but it is not equal to \(l \mathrm{~m}\)
Step-by-Step Solution
Verified Answer
The function \( f(x) \cdot g(x) \) is not continuous at \( x=a \).
1Step 1: Analyze One-Sided Limits
We are given that \( \lim_{x \to a^+} f(x) = l \) and \( \lim_{x \to a^-} g(x) = l \). Both these limits converge to the same value \( l \) from opposite sides of \( a \). Similarly, \( \lim_{x \to a^-} f(x) = m \) and \( \lim_{x \to a^-} g(x) = m \) also converge to \( m \).
2Step 2: Determine Limits at a
Since \( \lim_{x \to a^+} f(x) = l \) and \( \lim_{x \to a^+} g(x) = m \) converge to different values, \( f(x) \cdot g(x) \) cannot approach a single limit as \( x \) approaches \( a \).
3Step 3: Test Continuity
To check the continuity, the limit of \( f(x) \cdot g(x) \) must exist and equal the function value at \( x = a \). Given the limits found essentially differ from each sided convergence, \( f(x) \cdot g(x) \) is not continuous at \( x = a \).
4Step 4: Conclusion on Limit Existence
Since the behaviors of \( f(x) \) and \( g(x) \) at \( x=a \) converge to different limits from each direction, the product \( f(x) \cdot g(x) \) doesn't result in a definitive limit product, thus option (A) "is not continuous at \( x=a \)" is confirmed.
Key Concepts
One-Sided LimitsLimit ExistenceFunction Behavior at Points
One-Sided Limits
When we talk about one-sided limits, we are discussing how a function behaves as it approaches a specific point from one side only. These are crucial in understanding if a full limit exists and, subsequently, if the function is continuous. One-sided limits are essential in determining how the function approaches from either the positive or negative direction.
- Right-Hand Limit: Denoted as \( \lim_{x \to a^+} f(x) \), it considers how the function behaves as it approaches from values greater than \( a \).
- Left-Hand Limit: Denoted as \( \lim_{x \to a^-} f(x) \), it examines the approach from values less than \( a \).
Limit Existence
The existence of a limit at a point depends on one-sided limits agreeing with each other. For a function \( f(x) \) to have a limit at a point \( x = a \), the left-hand limit \( \lim_{x \to a^-} f(x) \) and the right-hand limit \( \lim_{x \to a^+} f(x) \) must both exist and be equal.
This means:
This means:
- If \( \lim_{x \to a^-} f(x) eq \lim_{x \to a^+} f(x) \), the limit does not exist at \( x=a \).
- If \( \lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x) = L \), then we say the limit exists and is \( L \).
Function Behavior at Points
The behavior of a function at a specific point tells us about continuity. For a function to be continuous at a point, three conditions must be satisfied:
- \( f(a) \) is defined.
- The limit \( \lim_{x \to a} f(x) \) exists.
- The limit equals the function's value at that point, \( \lim_{x \to a} f(x) = f(a) \).
Other exercises in this chapter
Problem 5
The function \(f(x)=[x] \cos \left(\frac{2 x-1}{2}\right) \pi\), where \([.]\) denotes the greatest integer function, is discontinuous at (A) all \(x\) (B) all
View solution Problem 6
The left-hand derivative of \(f(x)=[x] \sin (\pi x)\) at \(x=k\), \(k\) an integer and \([x]=\) greatest integer \(\leq x\), is (A) \((-1)^{k}(k-1) \pi\) (B) \(
View solution Problem 8
Let \([x]\) denotes the greatest integer less than or equal to \(x\). If \(f(x)=[x \sin \pi x]\), then \(f(x)\) is (A) continuous at \(x=0\) (B) continuous in \
View solution Problem 9
The function \(f(x)=[x]^{2}-\left[x^{2}\right]\) (where \([x]\) is the greatest integer less than or equal to \(x\) ), is discontinuous at (A) all integers (B)
View solution