Problem 5
Question
The function \(f(x)=[x] \cos \left(\frac{2 x-1}{2}\right) \pi\), where \([.]\) denotes the greatest integer function, is discontinuous at (A) all \(x\) (B) all integer points (C) no \(x\) (D) \(x\) which is not an integer
Step-by-Step Solution
Verified Answer
The function is discontinuous at all integer points, choice (B).
1Step 1: Understanding the Greatest Integer Function
The greatest integer function, denoted as \([x]\), represents the largest integer less than or equal to \(x\). This means \([x]=n\) if \(n \leq x < n+1\), where \(n\) is an integer.
2Step 2: Analyzing Discontinuity in Terms of Integers
To determine if \(f(x)=[x]\cos\left(\frac{2x-1}{2}\right)\pi\) is discontinuous at integer points, consider that \([x]\) changes its value at every integer. Therefore, \(f(x)\) could be potentially discontinuous at integers due to the change in \([x]\).
3Step 3: Evaluating the Cosine Component
The term \( \cos\left(\frac{2x-1}{2}\right)\pi \) remains continuous as it's a trigonometric function. However, discontinuity in \(f(x)\) can occur due to the presence of the greatest integer function, especially at points where \(x\) is an integer.
4Step 4: Testing for Discontinuity at Integer Points
At integer points, \(x=n\), \([x]=n\). As we approach from the left, \(x=n^-\), \([n^-]=n-1\) and \(x=n^+\), \([n^+]=n\), indicating that there's a jump in the function value, showing discontinuity.
5Step 5: Concluding Discontinuity Condition
The function \(f(x)\) is discontinuous where \([x]\) changes, which occurs at all integer points. The correct choice is (B) all integer points, as this is where the discontinuity due to the greatest integer function occurs.
Key Concepts
Greatest Integer FunctionTrigonometric FunctionsContinuity and Limits
Greatest Integer Function
The greatest integer function, often denoted as \([x]\), is a fascinating mathematical concept. It represents the largest integer that is less than or equal to a given number \(x\). Essentially, it rounds down a real number to the nearest whole number lower than or equal to it.
- For example, if \(x = 2.3\), then \([x] = 2\).
- If \(x = -2.3\), then \([x] = -3\). This is because \(-3\) is the greatest integer less than or equal to \(-2.3\).
Trigonometric Functions
Trigonometric functions, such as sine, cosine, and tangent, play a crucial role in mathematics. For the function \(f(x)=[x] \cos\left(\frac{2x-1}{2}\right)\pi\), the cosine component is a key player. The cosine function represents a periodic wave, continuously oscillating between 1 and -1.
- The cosine function is continuous and smooth along the entire real line.
- It maintains continuity because it does not have jumps or interruptions in its values.
Continuity and Limits
Continuity and limits are fundamental concepts in calculus used to analyze the behavior of functions at certain points. A function is continuous at a point if it does not have any abrupt changes or jumps there, meaning you can draw its graph without lifting your pen at that point.
- A limit describes the value that a function approaches as the input approaches some value.
- For continuity at a point \(c\), the limit of \(f(x)\) as \(x\) approaches \(c\) from both directions should equal \(f(c)\).
Other exercises in this chapter
Problem 2
Let \(f(x)=\cos x\) and \(g(x)=[x+2]\), where \([.]\) denotes the greatest integer function. Then, \((\text { gof })^{\prime}\left(\frac{\pi}{2}\right)\) is (A)
View solution Problem 3
Let \(f(x)=\left\\{\begin{array}{cl}\frac{1}{|x|} & |x| \geq 1 \\ a x^{2}+b & |x|
View solution Problem 6
The left-hand derivative of \(f(x)=[x] \sin (\pi x)\) at \(x=k\), \(k\) an integer and \([x]=\) greatest integer \(\leq x\), is (A) \((-1)^{k}(k-1) \pi\) (B) \(
View solution Problem 7
If \(\lim _{x \rightarrow a+} f(x)=l=\lim _{x \rightarrow a-} g(x)\) and \(\lim _{x \rightarrow a-} f(x)=m=\) \(g(x)\), then the function \(f(x) \cdot g(x)\) (A
View solution