Problem 9
Question
The function \(f(x)=[x]^{2}-\left[x^{2}\right]\) (where \([x]\) is the greatest integer less than or equal to \(x\) ), is discontinuous at (A) all integers (B) all integers except 0 and 1 (C) all integers except 0 (D) all integers except 1
Step-by-Step Solution
Verified Answer
The function is discontinuous at all integers except 0 (Option C).
1Step 1: Understand the Function Components
The given function is \( f(x) = [x]^2 - [x^2] \). Here, \([x]\) is the greatest integer function, which returns the largest integer less than or equal to \(x\). We need to determine where \(f(x)\) is discontinuous.
2Step 2: Analyze Discontinuity at Integers
A function \( f(x) \) using the greatest integer function is usually discontinuous at integers. We consider the behavior of \([x]^2\) and \([x^2]\) separately for integers.
3Step 3: Evaluate at Specific Points
Let’s analyze the function at integer points, particularly checking at 0 and 1 separately, as suggested by options: - When \( x \) is an integer, \([x] = x\), and \([x]^2 = x^2\). - If \(x = n\) where \(n\) an integer, \([n^2] = n^2\). Thus, \( f(n) = n^2 - n^2 = 0\).- For integers other than 0, expressions may differ when approaching from positive or negative sides.
4Step 4: Check Behavior around Nonzero Integers
Consider one-sided limits around nonzero integers: - For \( x = 1^+ \), \([x] = 1\) and \([x^2] = 1\). As \(x \rightarrow 1^- \), \([x] = 0\) and \([x^2] = 0\). - There is no discontinuity at 0 because approaching from both sides does not result in differing expressions as integers around 0 are negative (i.e., \([-1]\) who squares still result in 0).
5Step 5: Determine Discontinuity
The function is discontinuous at all integers except 0, confirming that it behaves continuously around nonzero integer inputs when approached from both sides near any integer except where |\(x > 1\) or \(x < 1\).
Key Concepts
Greatest Integer FunctionInteger Points AnalysisOne-Sided Limits
Greatest Integer Function
The greatest integer function, denoted as \([x]\), plays a crucial role in understanding the behavior of functions that involve rounding numbers down to the nearest integer. This function returns the largest integer less or equal to a given number \(x\). For example:
- \([2.7] = 2\)
- \([-1.3] = -2\)
- \([5] = 5\)
Integer Points Analysis
Integer points play a significant role when analyzing functions that contain the greatest integer function. At each integer point, the behavior of the function can dramatically shift due to the nature of the step function.To analyze such functions, consider the behavior of the individual components at integer points:
- For \([x]^2\), if \(x\) is an integer, the function remains consistent, as it evaluates to \(x^2\).
- For \([x^2]\), when \(x\) is an integer, it directly evaluates to \(x^2\), providing a consistent output.
- Therefore, at any integer \(n\), \(f(n) = [n]^2 - [n^2] = n^2 - n^2 = 0\).
One-Sided Limits
One-sided limits assist in revealing where a function like \(f(x) = [x]^2 - [x^2]\) may be discontinuous around integer points. These limits involve approaching an integer from the left or right, offering insight into the precise behavior of the function in these regions.Consider integer values such as 0 and 1:
- For \(x = 1^+\) (approaching from the right), \([x] = 1\) and \([x^2] = 1\), leading to no change.
- As \(x ightarrow 1^-\) (approaching from the left), \([x] = 0\) and \([x^2] = 0\), meaning possible differences manifest between these one-sided values.
- The consistency at \(x=0\) arises as negative values near zero (such as -0.1 becoming -1) maintain consistent expression values, unlike positive integer transitions.
Other exercises in this chapter
Problem 7
If \(\lim _{x \rightarrow a+} f(x)=l=\lim _{x \rightarrow a-} g(x)\) and \(\lim _{x \rightarrow a-} f(x)=m=\) \(g(x)\), then the function \(f(x) \cdot g(x)\) (A
View solution Problem 8
Let \([x]\) denotes the greatest integer less than or equal to \(x\). If \(f(x)=[x \sin \pi x]\), then \(f(x)\) is (A) continuous at \(x=0\) (B) continuous in \
View solution Problem 10
The function \(f(x)=[x]^{2}-\left[x^{2}\right]\) (where \([x]\) is the greatest integer less than or equal to \(x\) ), is discontinuous at (A) all integers (B)
View solution Problem 11
Let \(f(x)\) be a function satisfying the condition \(f(-x)=f(x)\), for all real \(x\). If \(f^{\prime}(0)\) exists, then its value is (A) 0 (B) 1 (C) \(-1\) (D
View solution