Problem 40
Question
By referring only to the periodic table, select \((\mathbf{a})\) the most electronegative element in group \(13 ;(\mathbf{b})\) the least electronegative element in the group As, Se and Br; (c) the most electronegative element in the group K, Mg, Al and In; (d) the element in the group \(\mathrm{Na}\), Be, \(\mathrm{Si}\), Ar, that is most likely to form an ionic compound with \(B \mathrm{r}\).
Step-by-Step Solution
Verified Answer
(a) Boron, (b) Arsenic, (c) Aluminium, (d) Sodium.
1Step 1: Identify Group 13 Elements
Group 13 of the periodic table consists of Boron (B), Aluminium (Al), Gallium (Ga), Indium (In), and Thallium (Tl). These elements are found in the 13th column of the periodic table.
2Step 2: Determine Most Electronegative in Group 13
In Group 13, Boron is the most electronegative element. Electronegativity generally decreases down a group, and Boron is at the top of Group 13.
3Step 3: Identify Elements As, Se, Br
The elements given are Arsenic (As), Selenium (Se), and Bromine (Br), which are located in groups 15, 16, and 17, respectively.
4Step 4: Determine Least Electronegative in As, Se, Br
Electronegativity increases across a period from left to right. Among As, Se, and Br, Arsenic has the lowest electronegativity as it is farthest to the left.
5Step 5: Identify Elements K, Mg, Al, In
Potassium (K), Magnesium (Mg), Aluminium (Al), and Indium (In) are located in groups 1, 2, 13, and beyond, respectively.
6Step 6: Determine Most Electronegative in K, Mg, Al, In
Electronegativity increases from left to right across a period. Among K, Mg, Al, In, Aluminium (Al) is the most electronegative since it is farthest to the right.
7Step 7: Identify Elements Na, Be, Si, Ar
The elements are Sodium (Na), Beryllium (Be), Silicon (Si), and Argon (Ar), located in groups 1, 2, 14, and 18, respectively.
8Step 8: Determine Most Ionic with Br
Ionic compounds typically form between metals and nonmetals. Of the elements given, Sodium (Na), a metal, is most likely to form an ionic compound with Bromine (Br), a nonmetal.
Key Concepts
ElectronegativityIonic CompoundsGroup Elements
Electronegativity
Electronegativity is a chemical property that describes the tendency of an atom to attract electrons towards itself in a chemical bond. This concept is vital to understand chemical bonding and molecular structure.
It is measured on the Pauling scale, named after chemist Linus Pauling.
It is measured on the Pauling scale, named after chemist Linus Pauling.
- Elements with higher electronegativity will have a stronger pull on electrons.
- Fluorine is the most electronegative element, located at the far right of the periodic table.
Ionic Compounds
Ionic compounds are formed when atoms transfer electrons from one to another, resulting in a metal and a non-metal pairing together.
This happens primarily due to the attraction between positively charged ions (cations) and negatively charged ions (anions).
This happens primarily due to the attraction between positively charged ions (cations) and negatively charged ions (anions).
- Typically, metals, which lose electrons, become cations.
- Non-metals, which gain electrons, become anions.
Group Elements
Group elements refer to elements that belong to the same vertical column, or group, in the periodic table.
These elements share similar chemical properties and valence electron configurations due to their common group identity.
These elements share similar chemical properties and valence electron configurations due to their common group identity.
- For example, Group 13 includes Boron (B), Aluminium (Al), and Gallium (Ga), among others.
- The properties of group elements, such as reactivity and electronegativity, change predictably within the group.
Other exercises in this chapter
Problem 38
(a) What is the trend in electronegativity going from left to right in a row of the periodic table? (b) How do electronegativity values generally vary going dow
View solution Problem 39
Using only the periodic table as your guide, select the most electronegative atom in each of the following sets: (a) Se, Te, \(\mathrm{Br}, \mathrm{I} ;(\mathbf
View solution Problem 41
Which of the following bonds are polar? (a) \(\mathrm{C}-\mathrm{O}\) (b) \(\mathrm{Sl}-\mathrm{F},(\mathbf{c}) \mathrm{N}-\mathrm{Cl},(\mathbf{d}) \mathrm{C}-\
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Arrange the bonds in each of the following sets in order of increasing polarity: \((\mathbf{a}) \mathrm{C}-\mathrm{F}, \mathrm{O}-\mathrm{F}, \mathrm{Be}-\mathr
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