Problem 42
Question
Arrange the bonds in each of the following sets in order of increasing polarity: \((\mathbf{a}) \mathrm{C}-\mathrm{F}, \mathrm{O}-\mathrm{F}, \mathrm{Be}-\mathrm{F} ;\) (b) \(\mathrm{O}-\mathrm{Cl}, \mathrm{S}-\mathrm{Br}, \mathrm{C}-\mathrm{P} ;(\mathbf{c}) \mathrm{C}-\mathrm{S}, \mathrm{B}-\mathrm{F}, \mathrm{N}-\mathrm{O}\).
Step-by-Step Solution
Verified Answer
(a) O-F, C-F, Be-F; (b) S-Br, C-P, O-Cl; (c) C-S, N-O, B-F.
1Step 1: Understand Bond Polarity
Bond polarity depends on the difference in electronegativity between the two atoms involved in a bond. The greater the difference, the more polar the bond is. To solve the problem, we need to know the electronegativity values for each atom involved.
2Step 2: Electronegativity Values
Find the electronegativity values for the relevant elements:
- Fluorine (F) = 4.0
- Oxygen (O) = 3.5
- Carbon (C) = 2.5
- Beryllium (Be) = 1.5
- Chlorine (Cl) = 3.0
- Sulfur (S) = 2.5
- Bromine (Br) = 2.8
- Phosphorous (P) = 2.1
- Nitrogen (N) = 3.0
3Step 3: Calculate Electronegativity Differences
For each bond, calculate the difference in electronegativity:
(a)
- C-F: |2.5 - 4.0| = 1.5
- O-F: |3.5 - 4.0| = 0.5
- Be-F: |1.5 - 4.0| = 2.5
(b)
- O-Cl: |3.5 - 3.0| = 0.5
- S-Br: |2.5 - 2.8| = 0.3
- C-P: |2.5 - 2.1| = 0.4
(c)
- C-S: |2.5 - 2.5| = 0.0
- B-F: |2.0 - 4.0| = 2.0
- N-O: |3.0 - 3.5| = 0.5
4Step 4: Order Bonds by Increasing Polarity
Arrange the bonds by their electronegativity difference from lowest to highest:
(a) O-F (0.5), C-F (1.5), Be-F (2.5)
(b) S-Br (0.3), C-P (0.4), O-Cl (0.5)
(c) C-S (0.0), N-O (0.5), B-F (2.0)
Key Concepts
ElectronegativityCovalent BondsChemical Bonding
Electronegativity
Electronegativity is a key concept in understanding bond polarity. It is the tendency of an atom to attract electrons towards itself when forming a chemical bond. Different elements have varying degrees of electronegativity, which influences the type of bond they form.
- Fluorine is the most electronegative element with a value of 4.0, making it particularly effective at pulling electrons.
- Oxygen, with a value of 3.5, is also highly electronegative.
- Elements like Be (Beryllium, 1.5) and P (Phosphorus, 2.1) have lower electronegativities.
Covalent Bonds
Covalent bonds form when atoms share electrons, allowing them to fill their outer electron shells and achieve stability. Unlike ionic bonds, which result from the transfer of electrons, covalent bonds involve a sharing mechanism.
- Homogeneous covalent bonds, such as \( \text{O}_2 \), involve atoms with similar electronegativities, leading to equal sharing of electrons.
- Heterogeneous covalent bonds, like \( \text{H}_2\text{O} \), involve atoms with different electronegativities, causing unequal sharing.
Chemical Bonding
Chemical bonding is the force that holds atoms together in compounds. Understanding the types of bonds - ionic, covalent, and metallic - is essential for grasping how substances are formed.
- Ionic bonds occur when electrons are transferred from one atom to another, often between metals and non-metals, leading to full positive and negative charges.
- In contrast, covalent bonds involve the sharing of electrons between non-metal atoms.
- Metallic bonds, however, involve a pooling of electrons among metal atoms, contributing to properties like conductivity and malleability.
Other exercises in this chapter
Problem 40
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