Problem 35
Question
Graph each quadratic function. Label the vertex and sketch and label the axis of symmetry. $$ f(x)=-(x-1)^{2} $$
Step-by-Step Solution
Verified Answer
Vertex: (1, 0); Axis of symmetry: x = 1; Opens downwards.
1Step 1: Identify the Form of the Quadratic
The given quadratic function is \( f(x) = -(x-1)^2 \). This is in the vertex form of a quadratic equation, \( y = a(x-h)^2 + k \), where \( a = -1 \), \( h = 1 \), and \( k = 0 \).
2Step 2: Determine the Vertex
Using the vertex form of the quadratic \( f(x) = -(x-1)^2 \), the vertex is at the point \( (h, k) \). Here, \( h = 1 \) and \( k = 0 \), thus the vertex is \( (1, 0) \).
3Step 3: Identify the Axis of Symmetry
The axis of symmetry for a quadratic in vertex form \( y = a(x-h)^2 + k \) is the vertical line \( x = h \). Here, \( x = 1 \) is the axis of symmetry.
4Step 4: Graph the Function
Sketch the quadratic by plotting the vertex at \( (1, 0) \). Since the coefficient \( a = -1 \) (which is negative), the parabola opens downwards. Draw the axis of symmetry as a dashed line through \( x = 1 \).
Key Concepts
Vertex of a Quadratic FunctionAxis of SymmetryVertex Form of a Quadratic Equation
Vertex of a Quadratic Function
The vertex of a quadratic function is a crucial point that represents either the maximum or minimum value of the quadratic equation. For the quadratic function in the exercise, which is given by \[ f(x) = -(x-1)^2 \], the vertex plays a key role.In vertex form, the vertex is at the point \( (h, k) \).
This occurs because the coefficient \( a = -1 \) is negative. The vertex gives the turning point of the parabola and is a useful point for sketching the graph.
- Here, we see \( h = 1 \) and \( k = 0 \).
- This means the vertex of this function is at the point \( (1, 0) \).
This occurs because the coefficient \( a = -1 \) is negative. The vertex gives the turning point of the parabola and is a useful point for sketching the graph.
Axis of Symmetry
The axis of symmetry is a vertical line that runs through the vertex of the parabola, dividing it into two mirror-image halves. It is a significant part of graphing quadratic functions because it helps in understanding the symmetry and shape of the parabola.
For the function \( f(x) = -(x-1)^2 \), we can identify the axis of symmetry directly from the equation.
It helps visually in plotting the mirror image of points on one side of the parabola to the other.
For the function \( f(x) = -(x-1)^2 \), we can identify the axis of symmetry directly from the equation.
- The formula tells us that the axis of symmetry is given by \( x = h \).
- In this case, \( h = 1 \), so our axis of symmetry is \( x = 1 \).
It helps visually in plotting the mirror image of points on one side of the parabola to the other.
Vertex Form of a Quadratic Equation
Understanding the vertex form of a quadratic equation gives us insight into the essential aspects of graphing these functions.
A quadratic function is expressed in vertex form as: \[ y = a(x-h)^2 + k \].
A quadratic function is expressed in vertex form as: \[ y = a(x-h)^2 + k \].
- Here, \( a \) determines the direction of the parabola (upward if positive, downward if negative).
- \( h \) and \( k \) are constants that allow us to locate the vertex \((h, k)\).
- The negative \( a \) tells us the parabola opens downwards.
- The vertex at \( (1, 0) \) makes this the highest point on the graph.
Other exercises in this chapter
Problem 35
Solve. Find two numbers whose difference is 10 and whose product is as small as possible.
View solution Problem 35
Solve each equation by completing the square. See Examples 7 through 9 $$ x^{2}+8 x=-15 $$
View solution Problem 36
Use the quadratic formula to solve each equation. These equations have real solutions and complex, but not real, solutions. $$ \frac{1}{8} x^{2}+x+\frac{5}{2}=0
View solution Problem 36
Solve each inequality. Write the solution set in interval notation. $$ 12 x^{2}+11 x \leq 15 $$
View solution