Problem 32
Question
Find the solution set to each equation. $$\frac{x}{5}=\frac{x+2}{3}$$
Step-by-Step Solution
Verified Answer
x = -5
1Step 1: Set Up the Equation
First, write down the given equation: \[ \frac{x}{5} = \frac{x+2}{3} \]
2Step 2: Cross-Multiply
To get rid of the fractions, cross-multiply so that each side of the equation becomes a whole number: \[ 3x = 5(x + 2) \]
3Step 3: Distribute the 5 on the Right Side
Distribute the 5 to both terms inside the parentheses: \[ 3x = 5x + 10 \]
4Step 4: Move All x Terms to One Side
Subtract 5x from both sides to bring all x terms to one side of the equation: \[ 3x - 5x = 10 \] Simplifying this, you get: \[ -2x = 10 \]
5Step 5: Solve for x
Divide both sides by -2 to isolate x: \[ x = \frac{10}{-2} \] So, \[ x = -5 \]
Key Concepts
Cross-MultiplicationDistributive Property
Cross-Multiplication
When solving rational equations, one of the most important techniques is cross-multiplication. This method helps eliminate fractions by converting them into a simpler, non-fractional form. In the exercise, we started with the equation \(\frac{x}{5} = \frac{x+2}{3}\). To cross-multiply, imagine swapping the denominators and numerators in a diagonal manner: multiply the numerator of the first fraction by the denominator of the second fraction and vice versa.\
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So, you end up with: \[ 3x = 5(x + 2) \] This transformation simplifies the solving process by dealing with whole numbers rather than fractions.
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So, you end up with: \[ 3x = 5(x + 2) \] This transformation simplifies the solving process by dealing with whole numbers rather than fractions.
Distributive Property
The next step involves using the distributive property to eliminate parentheses. The initial equation after cross-multiplication was \[ 3x = 5(x + 2) \] Applying the distributive property means multiplying 5 by both terms inside the parentheses (x and 2).\
So:\
So:\
Other exercises in this chapter
Problem 31
Find the solution set to each equation. $$\frac{10}{x}=\frac{20}{x+20}$$
View solution Problem 31
Simplify each complex fraction. $$\frac{\frac{1}{a-b}-\frac{3}{a+b}}{\frac{2}{b-a}+\frac{4}{b+a}}$$
View solution Problem 32
Simplify each complex fraction. $$\frac{\frac{3}{2+x}-\frac{4}{2-x}}{\frac{1}{x+2}-\frac{3}{x-2}}$$
View solution Problem 32
Reduce each rational expression to its lowest terms. $$\frac{b^{8}-a b^{5}}{a b^{5}}$$
View solution