Problem 31
Question
Find the solution set to each equation. $$\frac{10}{x}=\frac{20}{x+20}$$
Step-by-Step Solution
Verified Answer
The solution set is {20}.
1Step 1: Set the problem
The given equation is \( \frac{10}{x} = \frac{20}{x+20} \)
2Step 2: Cross-multiply
To solve the equation, cross-multiply to get rid of the fractions: \(10(x + 20) = 20x \)
3Step 3: Distribute and simplify
Distribute the 10 on the left side: \[ 10x + 200 = 20x \]
4Step 4: Isolate the variable
Subtract 10x from both sides to isolate the variable: \[ 10x + 200 - 10x = 20x - 10x \] \[ 200 = 10x \]
5Step 5: Solve for x
Divide both sides by 10 to find the value of x: \[ x = \frac{200}{10} \] \[ x = 20 \]
6Step 6: Verify the solution
Substitute \( x = 20 \) back into the original equation to check: \[ \frac{10}{20} = \frac{20}{20 + 20} \] \[ \frac{10}{20} = \frac{20}{40} \] \[ \frac{1}{2} = \frac{1}{2} \] Since both sides are equal, the solution is verified.
Key Concepts
cross-multiplicationisolating the variablefraction operations
cross-multiplication
Cross-multiplication is a technique used to solve rational equations. It involves multiplying the numerator of one fraction by the denominator of the other fraction. This helps to eliminate the fractions and makes the equation easier to solve. In the equation \( \frac{10}{x} = \frac{20}{x+20} \), cross-multiplying gives us: \( 10(x + 20) = 20x \). This step simplifies the process and helps in getting rid of the fractions on both sides. By using cross-multiplication:
- We convert a rational equation into a linear equation.
- The fractions disappear, leaving an equation with no denominators.
isolating the variable
Isolating the variable means getting the variable (in this case, \( x \)) by itself on one side of the equation. It's an important step when solving any equation. After cross-multiplying in our example, we get: \[ 10(x + 20) = 20x \]. Distributing on the left side, we get: \[ 10x + 200 = 20x \]. To isolate \( x \), we need to move all terms containing \( x \) to one side and constant terms to the other:
- Subtract \( 10x \) from both sides: \[ 10x + 200 - 10x = 20x - 10x \]
- This simplifies to: \[ 200 = 10x \]
- Finally, divide both sides by 10: \( x = \frac{200}{10} \), which gives \( x = 20 \)
fraction operations
When solving rational equations, understanding how to work with fractions is essential. Here are key points to remember:
In fractions, the numerator (top number) and the denominator (bottom number) must be handled carefully. For instance, in \( \frac{10}{x} \) and \( \frac{20}{x+20} \), the numerators are 10 and 20, while the denominators are \( x \) and \( x+20 \).
Operations with fractions include:
In fractions, the numerator (top number) and the denominator (bottom number) must be handled carefully. For instance, in \( \frac{10}{x} \) and \( \frac{20}{x+20} \), the numerators are 10 and 20, while the denominators are \( x \) and \( x+20 \).
Operations with fractions include:
- Addition/Subtraction: Find a common denominator before adding or subtracting the numerators.
- Multiplication: Multiply the numerators together and the denominators together.
- Division: Multiply by the reciprocal of the fraction you're dividing by.
Other exercises in this chapter
Problem 30
Solve each problem. Beverly can drive 600 miles in the same time as it takes Susan to drive 500 miles. If Beverly drives 10 mph faster than Susan, then how fast
View solution Problem 30
Reduce each rational expression to its lowest terms. $$\frac{6 a^{3} b^{12} c^{5}}{-8 a b^{4} c^{9}}$$
View solution Problem 31
Simplify each complex fraction. $$\frac{\frac{1}{a-b}-\frac{3}{a+b}}{\frac{2}{b-a}+\frac{4}{b+a}}$$
View solution Problem 32
Find the solution set to each equation. $$\frac{x}{5}=\frac{x+2}{3}$$
View solution