Problem 27
Question
In Exercises \(21-28,\) divide and express the result in standard form. $$ \frac{2+3 i}{2+i} $$
Step-by-Step Solution
Verified Answer
The result is \( \frac{7}{5} + \frac{4}{5}i \) in standard form.
1Step 1: Identify the Conjugate
The conjugate of a complex number \(a+bi\) is \(a-bi\). Thus the conjugate of \(2+i\) is \(2-i\).
2Step 2: Multiply by Conjugate
Multiply the numerator and the denominator by the conjugate of the denominator. Hence, \(\frac{2+3i}{2+i}\) becomes \(\frac{2+3i}{2+i} * \frac{2-i}{2-i}\).
3Step 3: Simplify the Numerator
For the numerator, follow the FOIL method (First, Outer, Inner, Last) to get \((2+3i) * (2-i) = 4 - 2i + 6i - 3i^2\). Here, \(i^2 = -1\), so the expression becomes \(4 + 4i + 3 = 7 + 4i\).
4Step 4: Simplify the Denominator
In the denominator also follow the FOIL method. The denominator is \((2+i)* (2-i) = 4 - 2i + 2i - i^2\). Here again, \(i^2 = -1\), thus the expression becomes \(4 + 1 = 5\).
5Step 5: Express the Result in Standard Form
The result is then \(\frac{7 + 4i}{5}\). This can be written in standard form as \( \frac{7}{5} + \frac{4}{5}i\).
Key Concepts
Understanding Conjugates in Complex NumbersThe Standard Form of Complex NumbersHow to Use the FOIL Method with Complex NumbersUnderstanding the Imaginary Unit
Understanding Conjugates in Complex Numbers
Conjugates are an important concept when working with complex numbers, especially in division. A complex number is usually expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit. The conjugate of this complex number is \(a - bi\).
To form the conjugate, you simply change the sign of the imaginary part. This is crucial for simplifying division involving complex numbers.
To form the conjugate, you simply change the sign of the imaginary part. This is crucial for simplifying division involving complex numbers.
- For example, the conjugate of \(2+i\) is \(2-i\).
- Using the conjugate allows us to eliminate the imaginary part in the denominator.
The Standard Form of Complex Numbers
The standard form for complex numbers is important for clearly expressing results. This form consists of a real part and an imaginary part separated by a plus sign, written as \(a + bi\).
For instance, after dividing two complex numbers and simplifying, the result might be \(\frac{7 + 4i}{5}\). This can be further expressed in standard form as \(\frac{7}{5} + \frac{4}{5}i\), where both parts are separated clearly. Using standard form helps in comparing, plotting on the complex plane, and further calculations.
- Here, \(a\) is the real component.
- \(b\) is the coefficient of the imaginary part.
For instance, after dividing two complex numbers and simplifying, the result might be \(\frac{7 + 4i}{5}\). This can be further expressed in standard form as \(\frac{7}{5} + \frac{4}{5}i\), where both parts are separated clearly. Using standard form helps in comparing, plotting on the complex plane, and further calculations.
How to Use the FOIL Method with Complex Numbers
The FOIL method is a handy mnemonic for remembering how to multiply binomials and it, surprisingly, works well with complex numbers too. FOIL stands for First, Outer, Inner, and Last. When you multiply two complex numbers in the form \((a+bi)(c+di)\), you apply the FOIL method like this:
- First: Multiply the first terms of each binomial, \(a \cdot c\).
- Outer: Multiply the outer terms, \(a \cdot di\).
- Inner: Multiply the inner terms, \(bi \cdot c\).
- Last: Multiply the last terms, \(bi \cdot di\).
- First: \(2 \cdot 2 = 4\)
- Outer: \(2 \cdot (-i) = -2i\)
- Inner: \(3i \cdot 2 = 6i\)
- Last: \(3i \cdot (-i) = -3i^2\)
Understanding the Imaginary Unit
The imaginary unit \(i\) is a fundamental component of complex numbers. By definition, \(i\) is the square root of \(-1\), which is not possible within the real number system.
- This imaginary unit is denoted as \(i\), where \(i^2 = -1\).
- Complex numbers are constructed using \(i\), combining both real and variable parts.
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Problem 26
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