Problem 27
Question
Use interval notation to express solution sets and graph each solution set on a number line. Solve each linear inequality. $$5 x+11<26$$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(5x+11<26\) is \( x < 3 \), which in interval notation is expressed as \((-\infty, 3)\).
1Step 1: Simplify inequality
Start by isolating the term with \( x \) on one side of the inequality. This is done by subtracting 11 from both sides of the inequality: \(5x + 11 - 11 < 26 - 11\), which simplifies to \(5x < 15\)
2Step 2: Solve for x
To solve for \( x \), divide both sides of the inequality by 5. \( \frac{5x}{5} < \frac{15}{5} \), simplifies to \( x < 3 \)
3Step 3: Express in Interval Notation
Our solution \( x < 3 \) denotes that \( x \) can be any number less than 3 but not 3 itself. In interval notation, it's expressed as \((-\infty, 3)\)
4Step 4: Graph the solution on a Number Line
Draw a number line, and mark the number 3. Then draw an open circle at 3 (Because 3 is not part of the solution set), and shade all the values to the left of 3, extending the line to indicate that it continues towards negative infinity.
Other exercises in this chapter
Problem 27
In Exercises \(21-28,\) divide and express the result in standard form. $$ \frac{2+3 i}{2+i} $$
View solution Problem 27
Solve each equation in Exercises \(15-34\) by the square root property. $$ (x-3)^{2}=-5 $$
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Check all proposed solutions. $$ \sqrt{2 x+3}+\sqrt{x-2}=2 $$
View solution Problem 27
Contain linear equations with constants in denominators. Solve equation. \(\frac{x}{4}=2+\frac{x-3}{3}\)
View solution