Problem 26
Question
Contain linear equations with constants in denominators. Solve equation. \(\frac{x+1}{4}=\frac{1}{6}+\frac{2-x}{3}\)
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 1\)
1Step 1: Identify the least common multiple (LCM)
Firstly, identify the LCM of the denominators 4, 6, and 3. Here, the LCM is 12.
2Step 2: Multiply each term with the LCM
Multiply both sides of the equation by the LCM to eliminate the denominators. It will result in \(12*(\frac{x+1}{4})=12*(\frac{1}{6}+\frac{2-x}{3})\) that simplifies to \(3(x+1)=2+4*(2-x)\).
3Step 3: Simplify the equation
Now simplify the equation at both sides. The equation after simplifying will be \(3x+3=2+8-4x\). Further, simplify it to \(3x+3=10-4x\).
4Step 4: Regroup like terms
Bring the terms involving 'x' to one side of the equation and constant terms to the other side of the equation. This leads to \(3x+4x=10-3\), which simplifies to \(7x=7\).
5Step 5: Solve for x
Finally, solve for 'x' by dividing by 7 on both sides of the equation. It gives the solution as \(x=1\).
Key Concepts
Least Common Multiple (LCM)DenominatorsSolving Equations Step-by-Step
Least Common Multiple (LCM)
When working with linear equations that have fractions, finding the least common multiple (LCM) is a crucial step. The LCM of a set of numbers is the smallest multiple that they all share. For the denominators in the exercise \(\frac{x+1}{4}=\frac{1}{6}+\frac{2-x}{3}\), we need to find the LCM of 4, 6, and 3.
Here’s how you can find the LCM:
Here’s how you can find the LCM:
- List the multiples of each number until you find the smallest common one. For 4, 6, and 3, the LCM is 12.
- This step is vital because multiplying each term by the LCM will eliminate the fractions and simplify the equation into a form that's easier to solve.
Denominators
Denominators are the bottom parts of fractions. In the context of equations, denominators tell us how to divide numbers evenly. For example, in our exercise, 4, 6, and 3 are the denominators.
Understanding denominators is key:
Understanding denominators is key:
- They indicate into how many parts a whole is divided.
- When solving an equation, the goal is often to "clear" these denominators to simplify the process.
Solving Equations Step-by-Step
Solving equations step-by-step is like peeling back the layers of an onion, revealing the solution at the core. Let's break down the process for our equation:
1. **Multiply by the LCM:** Begin by multiplying each term by the LCM (12), which clears the fractions and simplifies the equation.
2. **Simplify:** After eliminating fractions, simplify by expanding and combining like terms on both sides.
3. **Regroup Terms:** Move terms containing the variable \(x\) to one side and constants to the other to form an equation like \(7x=7\).
4. **Solve for \(x\):** Finally, solve for \(x\) by dividing both sides by the coefficient of \(x\).
This systematic approach ensures clarity and structure, making it easier to arrive at an accurate solution.
1. **Multiply by the LCM:** Begin by multiplying each term by the LCM (12), which clears the fractions and simplifies the equation.
2. **Simplify:** After eliminating fractions, simplify by expanding and combining like terms on both sides.
3. **Regroup Terms:** Move terms containing the variable \(x\) to one side and constants to the other to form an equation like \(7x=7\).
4. **Solve for \(x\):** Finally, solve for \(x\) by dividing both sides by the coefficient of \(x\).
This systematic approach ensures clarity and structure, making it easier to arrive at an accurate solution.
Other exercises in this chapter
Problem 26
Solve each equation in Exercises \(15-34\) by the square root property. $$ (x-1)^{2}=-9 $$
View solution Problem 26
Check all proposed solutions. $$ \sqrt{2 x-3}-\sqrt{x-2}=1 $$
View solution Problem 27
You are choosing between two health clubs. Club A offers membership for a fee of \(\$ 40\) plus a monthly fee of \(\$ 25 .\) Club \(B\) offers membership for a
View solution Problem 27
In Exercises \(21-28,\) divide and express the result in standard form. $$ \frac{2+3 i}{2+i} $$
View solution