Problem 24
Question
Use a graphing utility to graph the polar equations and find the area of the given region. Common interior of \(r=5-3 \sin \theta\) and \(r=5-3 \cos \theta\)
Step-by-Step Solution
Verified Answer
The short answer will be the numerical value of the area obtained after performing the above steps. The exact value will depend on the results of the integration in Step 3 and Step 4.
1Step 1: Graph the Polar Equations
Use a graphing utility to plot the two polar equations \(r=5-3 \sin \theta\) and \(r=5-3 \cos \theta\). This will help to visually understand the area to be calculated.
2Step 2: Find the Points of Intersection
Set the two functions equal to each other to determine the θ values where the two curves intersect: \(5-3 \sin \theta = 5-3 \cos \theta\). Solve this equation to get the values of θ.
3Step 3: Evaluate the Integral
The area of the region in polar coordinates is given by integrating the square of the difference between the two polar functions over the common θ range: \[ Area = \frac{1}{2} \int_{\theta_1}^{\theta_2} ((5 - 3\sin\theta)^2 - (5 - 3\cos\theta)^2) d\theta \]
4Step 4: Calculate the Area
Substitute the θ values obtained in Step 2 into the integral and calculate to get the area of the common interior.
Key Concepts
Polar EquationsArea CalculationGraphing Utility
Polar Equations
Polar equations are used to express curves in the polar coordinate system, where each point is determined by a distance from a reference point and an angle from a reference direction. This can be different from the regular Cartesian coordinates most students are familiar with. A point in polar coordinates is written as \((r, \theta)\), where \(r\) is the radius or the distance from the origin, and \(\theta\) is the angle from the positive x-axis.
In our exercise, two specific polar equations are provided:
Understanding these equations requires familiarity with how sine and cosine values fluctuate between -1 and 1, affecting the radius ranges and resulting curve shapes.
In our exercise, two specific polar equations are provided:
- \(r = 5 - 3 \sin \theta\)
- \(r = 5 - 3 \cos \theta\)
Understanding these equations requires familiarity with how sine and cosine values fluctuate between -1 and 1, affecting the radius ranges and resulting curve shapes.
Area Calculation
Finding the area of a region described by polar equations involves integration, which is a core concept in calculus. In polar coordinates, the formula to find the area enclosed by a curve \(r(\theta)\) from an initial angle \(\theta_1\) to a final angle \(\theta_2\) is given by: \[Area = \frac{1}{2} \int_{\theta_1}^{\theta_2} r^2 d\theta\]This integral takes into account how the radius changes as the angle \(\theta\) sweeps through its range.
In this specific exercise, we deal with the common interior of two polar curves. This means we are interested in the area where the curves overlap. To find this, we calculate the intersection points of the two equations, \(5 - 3 \sin \theta = 5 - 3 \cos \theta\). Solving such equations gives the values of \(\theta\) where the curves intersect, determining the limits for our integral.
Finally, we substitute these limits into the following area calculation: \[Area = \frac{1}{2} \int_{\theta_1}^{\theta_2} \left((5 - 3\sin\theta)^2 - (5 - 3\cos\theta)^2\right) d\theta\]This formulation helps us find the exact area enclosed by the curves within the overlapping region.
In this specific exercise, we deal with the common interior of two polar curves. This means we are interested in the area where the curves overlap. To find this, we calculate the intersection points of the two equations, \(5 - 3 \sin \theta = 5 - 3 \cos \theta\). Solving such equations gives the values of \(\theta\) where the curves intersect, determining the limits for our integral.
Finally, we substitute these limits into the following area calculation: \[Area = \frac{1}{2} \int_{\theta_1}^{\theta_2} \left((5 - 3\sin\theta)^2 - (5 - 3\cos\theta)^2\right) d\theta\]This formulation helps us find the exact area enclosed by the curves within the overlapping region.
Graphing Utility
A graphing utility is an essential tool for working with polar equations, especially when visualizing complex curves that are not straightforward. In the context of our exercise, it assists in plotting the equations \(r=5-3\sin\theta\) and \(r=5-3\cos\theta\) to see how they interact. This visual representation can highlight symmetries and intersections, providing insight before performing any calculations.
Using a graphing utility allows:
Using a graphing utility allows:
- Checking the behavior of each polar curve as \(\theta\) varies from \(0\) to \(2\pi\)
- Identifying intersection points more easily and accurately
- Estimating areas visually to support integral calculations
Other exercises in this chapter
Problem 23
Convert the rectangular equation to polar form and sketch its graph. $$ 3 x-y+2=0 $$
View solution Problem 24
Use a graphing utility to graph the curve represented by the parametric equations (indicate the orientation of the curve). Eliminate the parameter and write the
View solution Problem 24
Convert the rectangular equation to polar form and sketch its graph. $$ x y=4 $$
View solution Problem 25
Write the equation for the ellipse rotated \(\pi / 4\) radian clockwise from the ellipse \(r=\frac{5}{5+3 \cos \theta}\).
View solution