Problem 23
Question
Convert the rectangular equation to polar form and sketch its graph. $$ 3 x-y+2=0 $$
Step-by-Step Solution
Verified Answer
The polar form of the given rectangle equation is \(r = -2/(3\cos\theta - \sin\theta)\). The sketch involves a curve, with its maximum in the \(3\pi/4\) direction, extends indefinitely in the \(\pi/4\) and \(-3\pi/4\) directions. Where points are negative, reflect them across the origin.
1Step 1: Convert Rectangular Equations into Polar form
In the given equation \(3x - y + 2 = 0\), replace \(x\) with \(r \cos \theta\) and \(y\) with \(r \sin \theta\). The equation becomes \(3r \cos \theta - r \sin \theta + 2 = 0\). To simplify further, factor out the \(r\) which yields \(r(3 \cos \theta - \sin \theta )+2=0\).
2Step 2: Solve for r
For the graph, it is easier to have \(r\) on one side of the equation. Subtract 2 from both side to get \(r(3 \cos \theta - \sin\theta) = -2\). Then divide both sides by \((3 \cos \theta - \sin \theta)\) to isolate \(r\), producing \(r = -2/(3 \cos \theta - \sin \theta)\).
3Step 3: Sketch the Graph
The graph sketching involves plotting the points of \(r\) and \(\theta\) on a polar grid. As \(\theta\) varies from \(0\) to \(360^{\circ}\) or \(0\) to \(2\pi\), mark the corresponding \(r\) values. Remember, \(r<0\) means the point is in the opposite direction. Properly interpret points where \(r\) is negative by reflecting over the origin and acquire smooth curve by joining these points.
Other exercises in this chapter
Problem 23
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