Problem 25
Question
Write the equation for the ellipse rotated \(\pi / 4\) radian clockwise from the ellipse \(r=\frac{5}{5+3 \cos \theta}\).
Step-by-Step Solution
Verified Answer
The equation of the ellipse rotated \(\frac{\pi}{4}\) radian clockwise from the ellipse \(r=\frac{5}{5+3 \cos \theta}\) will be obtained after following the above outlined steps, involving conversion to Cartesian coordinates, applying rotation transformation, and calculating the new equation of the ellipse.
1Step 1: Write the given ellipse equation
First, write down the given ellipse equation in polar coordinates, which is \(r=\frac{5}{5+3 \cos \theta}\).
2Step 2: Convert to Cartesian coordinates
Convert the ellipse equation from polar to Cartesian coordinates. In polar coordinates, \(x = r \cos \theta\) and \(y = r \sin \theta\). Substitution of these into the ellipse equation gives the Cartesian form of the ellipse.
3Step 3: Apply the rotation transformation
Then apply a rotation transformation. For a rotation of \(\phi\) about the origin in the clockwise direction, the transformation equations are \(x' = x \cos \phi + y \sin \phi\), and \(y' = -x \sin \phi + y \cos \phi\). Here, \(\phi = -\frac{\pi}{4}\), the negative sign is because the rotation is clockwise. Substitute \(x\) and \(y\) from the transformation equations into the Cartesian form of the ellipse from Step 2.
4Step 4: Derive the equation of the rotated ellipse
Simplify the result from Step 3 to derive the equation of the rotated ellipse in terms of \(x'\) and \(y'\).
Key Concepts
Polar CoordinatesCartesian CoordinatesRotation Transformation
Polar Coordinates
When dealing with polar coordinates, we describe the position of a point based on its distance from the origin, denoted as \(r\), and the angle \(\theta\) from the positive x-axis. In essence, polar coordinates are particularly effective when you're dealing with curves and figures that are inherently circular or exhibit symmetry around a point. The given ellipse equation is initialized in this format:
- The formula \(r=\frac{5}{5+3 \cos \theta}\) is the polar representation of the ellipse.
- Here, \(r\) changes based on the angle \(\theta\), signifying an adjustment in the radius relative to the angle.
Cartesian Coordinates
Cartesian coordinates, on the other hand, utilize a straightforward grid-based system to describe any point in a plane using \(x\) and \(y\) coordinates. The key benefit here is simplicity for algebraic manipulations when dealing with linear and rectangular forms of expressions.
- To transition from polar to Cartesian coordinates, we can use the equations: \(x = r \cos \theta\) and \(y = r \sin \theta\).
- Those relationships transform the polar equation \(r=\frac{5}{5+3 \cos \theta}\) into a form involving \(x\) and \(y\).
Rotation Transformation
A rotation transformation moves points in a plane around the origin by a specified angle. Here, we're interested in rotating the ellipse by \(\frac{\pi}{4}\) radian in the clockwise direction, which is facilitated by the transformation equations:
- \(x' = x \cos \phi + y \sin \phi\)
- \(y' = -x \sin \phi + y \cos \phi\)
Other exercises in this chapter
Problem 24
Use a graphing utility to graph the polar equations and find the area of the given region. Common interior of \(r=5-3 \sin \theta\) and \(r=5-3 \cos \theta\)
View solution Problem 24
Convert the rectangular equation to polar form and sketch its graph. $$ x y=4 $$
View solution Problem 25
Determine any differences between the curves of the parametric equations. Are the graphs the same? Are the orientations the same? Are the curves smooth? $$ \tex
View solution Problem 25
Use a graphing utility to graph the polar equations and find the area of the given region. Common interior of \(r=4 \sin \theta\) and \(r=2\)
View solution