Problem 20
Question
Solve the equation algebraically. Check your solution graphically. $$5 x+3=-2$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(5x + 3 = -2\) is \(x = -1\), checked graphically by confirming the line \(y = 5x+3\) intersects the x-axis at x=-1.
1Step 1: Isolating 'x' Algebraically
We start with the equation \(5x + 3 = -2\). The goal is to isolate 'x'. To do so, first, we subtract 3 from both sides of the equation to remove the +3 on the left. This gets us: \(5x = -2-3\), which simplifies to \(5x = -5\).
2Step 2: Solving for 'x'
Next, we need to solve for 'x'. The current term with 'x' (\(5x\)) indicates 5 times 'x', so we need to undo that by doing the opposite - in this case, division. We divide both sides of the equation by 5. This gives us: \(x = -5/5\), which further simplifies to \(x = -1\).
3Step 3: Checking the solution graphically
To check the solution graphically, create a graph with the equation \(y = 5x + 3\). The solution to the initial equation is the x-coordinate at which the line crosses the x-axis. If we did Q1 and Q2 correctly, the line should intersect the x-axis at x=-1.
Key Concepts
Algebraic Methods for Solving Linear EquationsGraphical Solutions to Linear EquationsIsolation of Variables in Linear Equations
Algebraic Methods for Solving Linear Equations
When students encounter a linear equation such as 5x + 3 = -2, algebraic methods provide a structured approach to finding the solution. The key principle in algebra is to perform the same operation on both sides of the equation to keep it balanced.
Let's break down how this works:
Let's break down how this works:
- Identify the variable you're solving for – in this case, it's 'x'.
- Apply the inverse operation to isolate the term with the variable. If the variable is being added to or subtracted from a number, do the opposite (subtract or add) that number from both sides.
- If the variable is multiplied by a number, divide both sides by that number; if divided, multiply.
Graphical Solutions to Linear Equations
Graphical solutions are a visual representation of algebraic equations and can serve as a great tool for checking the work you've done using algebraic methods. To graph the equation 5x + 3 = -2, or in graphing format, y = 5x + 3, follow these steps:
- Start by plotting the y-intercept, which is the constant term in the equation (in this case, +3) on the y-axis.
- Use the slope (the coefficient of x, which is 5) to determine the rise over run, helping you plot another point.
- Draw a line through these points, which represents the equation.
Isolation of Variables in Linear Equations
Isolation of the variable is one of the fundamental techniques in solving linear equations. The main goal is to have the variable you're looking for by itself on one side of the equal sign. To isolate the variable ’x’ in an equation like 5x + 3 = -2:
- Subtract or add constants to both sides to remove them from the side with the variable.
- Once you have only terms with the variable on one side, use multiplication or division to get the variable by itself.
Other exercises in this chapter
Problem 19
Find the \(x\) -intercept of the graph of the equation. $$ 2 x+2 y=-10 $$
View solution Problem 19
Decide whether the given ordered pair is a solution of the equation. \(6 y-3 x=-9,(2,-1)\)
View solution Problem 20
Without plotting the point, tell whether it is in Quadrant I, Quadrant II, Quadrant III, or Quadrant IV. $$(-2,7)$$
View solution Problem 20
Evaluate the function when \(x=2, x=0,\) and \(x=-3\). $$ f(x)=10 x+1 $$
View solution