Problem 20
Question
Evaluate the function when \(x=2, x=0,\) and \(x=-3\). $$ f(x)=10 x+1 $$
Step-by-Step Solution
Verified Answer
The values of the function are 21 when \(x=2\), 1 when \(x=0\), and -29 when \(x=-3\).
1Step 1: Substitute x=2
Substitute \(x=2\) in the function: \[f(2)=10(2) + 1=21\]
2Step 2: Substitute x=0
Substitute \(x=0\) in the function: \[f(0)=10(0) + 1=1\]
3Step 3: Substitute x=-3
Substitute \(x=-3\) in the function: \[f(-3)=10(-3) + 1=-29\]
Key Concepts
Understanding Function NotationThe Art of Substitution in FunctionsExploring Linear Functions
Understanding Function Notation
When we talk about function notation, it might sound a bit complex at first, but it really just gives us a neat way to describe relationships between numbers. Function notation, typically written as \(f(x)\), allows us to express a function without ambiguity. Here, \(f\) is the name of the function, and \(x\) is the input variable, or the number you put into the function. Think of \(x\) as the ingredient and \(f\) as the recipe. For example, if the function is \(f(x) = 10x + 1\), then you input \(x\) to calculate an output value. This standard notation helps us easily understand which function we are evaluating and what input we're using. It's like having a personal name tag for each function, ensuring we handle them correctly.
The Art of Substitution in Functions
Substitution is a fancy word for plugging in numbers where letters usually go. It’s one of the most fundamental concepts in evaluating functions. To evaluate a function like \(f(x) = 10x + 1\) at specific values of \(x\), say \(x = 2\), you substitute 2 in place of \(x\) in the equation. Like this: \(f(2) = 10 \cdot 2 + 1 = 21\). The key steps are straightforward:
- Identify the value to substitute for \(x\).
- Replace each \(x\) in the expression with the chosen number.
- Calculate the result using standard arithmetic operations.
Exploring Linear Functions
Linear functions are one of the simplest and most fundamental types of functions in mathematics. They represent relationships that produce straight lines on a graph. The general formula for a linear function is \(f(x) = mx + b\), where \(m\) is the slope of the line and \(b\) is the y-intercept. In our example, \(f(x) = 10x + 1\), 10 is the slope and 1 is the y-intercept.Linear functions have a constant rate of change, meaning the slope remains the same no matter where you are on the line. They are easy to identify because for every increase or decrease in \(x\), \(y\) will increase or decrease by the same amount, specifically by \(m\). This property makes linear functions predictable and useful for many real-world applications, like predicting expenses or distance over time. They are a stepping stone to understanding more complex functions as they lay the groundwork for concepts like rates of change and growth.
Other exercises in this chapter
Problem 20
Solve the equation algebraically. Check your solution graphically. $$5 x+3=-2$$
View solution Problem 20
Without plotting the point, tell whether it is in Quadrant I, Quadrant II, Quadrant III, or Quadrant IV. $$(-2,7)$$
View solution Problem 20
Graph the equation. Find the constant of variation and the slope of the direct variation model. $$y=-\frac{1}{5} x$$
View solution Problem 20
Plot the points and find the slope of the line passing through the points. $$(4,5),(2,3)$$
View solution