Problem 18
Question
Eind the dot product of \(\mathbf{x}=[2,-3,1]^{\prime}\) and \(\mathbf{v}=[3,1,-2]^{\prime}\)
Step-by-Step Solution
Verified Answer
The dot product of \( \mathbf{x} \) and \( \mathbf{v} \) is 1.
1Step 1: Understand the Dot Product
The dot product of two vectors \( \mathbf{a} = [a_1, a_2, a_3]^{\prime} \) and \( \mathbf{b} = [b_1, b_2, b_3]^{\prime} \) is given by the formula \( a_1b_1 + a_2b_2 + a_3b_3 \). It produces a scalar (a single number).
2Step 2: Identify Components of Vectors
Identify the components of vectors \( \mathbf{x} \) and \( \mathbf{v} \). For \( \mathbf{x} = [2, -3, 1]^{\prime} \), we have components \( x_1 = 2 \), \( x_2 = -3 \), and \( x_3 = 1 \). For \( \mathbf{v} = [3, 1, -2]^{\prime} \), we have components \( v_1 = 3 \), \( v_2 = 1 \), and \( v_3 = -2 \).
3Step 3: Calculate Each Product of Components
Multiply the corresponding components of the vectors: \( 2 \times 3 = 6 \), \( -3 \times 1 = -3 \), and \( 1 \times -2 = -2 \).
4Step 4: Sum the Results
Add the results of the products from Step 3: \( 6 + (-3) + (-2) = 6 - 3 - 2 \).
5Step 5: Final Calculation
Compute \( 6 - 3 - 2 \) to find the dot product. This results in \( 1 \).
Key Concepts
Vector CalculusScalar MultiplicationVector Components
Vector Calculus
Vector calculus is a branch of mathematics that deals with vector-related concepts and operations. In this context, vectors are mathematical entities that have both magnitude and direction. They are incredibly useful for representing physical quantities like force, velocity, and acceleration. In vector calculus, operations like addition, subtraction, and dot product are integral.
The dot product is one such operation and is fundamental to vector calculus. It results in a scalar, simplifying complex multidimensional calculations. It helps in finding angles between vectors, determining vector projections, and calculating work done by force fields. Understanding these concepts enriches your problem-solving toolkit in physics and engineering.
The dot product is one such operation and is fundamental to vector calculus. It results in a scalar, simplifying complex multidimensional calculations. It helps in finding angles between vectors, determining vector projections, and calculating work done by force fields. Understanding these concepts enriches your problem-solving toolkit in physics and engineering.
Scalar Multiplication
Scalar multiplication is a basic operation in vector calculus that involves multiplying a vector by a scalar, or a single number. This operation scales the vector, changing its magnitude without affecting its direction.
Imagine you have a vector representing a force, and you scale this vector by multiplying it with a scalar. It changes the force's magnitude, making it stronger or weaker, without altering its initial direction.
Imagine you have a vector representing a force, and you scale this vector by multiplying it with a scalar. It changes the force's magnitude, making it stronger or weaker, without altering its initial direction.
- Scalar multiplication retains the direction of the vector.
- It modifies the magnitude by the scalar's absolute value.
- Negative scalar flips the vector's direction.
Vector Components
Vector components are individual parts that make up the whole vector. Each component represents the vector's projection along an axis in Cartesian coordinates. For example, a three-dimensional vector \( \mathbf{x} = [x_1, x_2, x_3]^{\prime}\) has three components: \( x_1, x_2, \) and \( x_3\). These are important because they allow us to perform vector operations like the dot product.
Identifying vector components was a key step in solving the original exercise. For vectors \( \mathbf{x} = [2, -3, 1]^{\prime} \) and \( \mathbf{v} = [3, 1, -2]^{\prime}\), their components guided the scalar multiplications and highlighted the importance of individual axis contributions in vector calculations.
By mastering vector components, you enhance your comprehension of vector behavior in different dimensions, laying a solid foundation for more advanced studies and applications.
Identifying vector components was a key step in solving the original exercise. For vectors \( \mathbf{x} = [2, -3, 1]^{\prime} \) and \( \mathbf{v} = [3, 1, -2]^{\prime}\), their components guided the scalar multiplications and highlighted the importance of individual axis contributions in vector calculations.
By mastering vector components, you enhance your comprehension of vector behavior in different dimensions, laying a solid foundation for more advanced studies and applications.
Other exercises in this chapter
Problem 17
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Suppose that \(A\) is an \(m \times n\) matrix. Show that $$ \left(A^{\prime}\right)^{\prime}=A $$
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In Problems , find \(\mathbf{x}+\mathbf{y}\) for the given vectors \(\mathbf{x}\) and \(\mathbf{y}\). Represent \(\mathbf{x}, \mathbf{y}\), and \(\mathbf{x}+\ma
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Suppose that \(A\) is an \(m \times n\) matrix and \(k\) is a real number. Show that $$ (k A)^{\prime}=k A^{\prime} $$
View solution