Problem 19
Question
Suppose that \(A\) is an \(m \times n\) matrix and \(k\) is a real number. Show that $$ (k A)^{\prime}=k A^{\prime} $$
Step-by-Step Solution
Verified Answer
\((kA)^{\prime} = kA^{\prime}\) because transposing and then scaling yields the same matrix as scaling then transposing.
1Step 1: Understand the problem
We are asked to show that taking the transpose of a scaled matrix equals scaling the transpose of that matrix. Specifically, if we have a matrix \(A\) and multiply it by a scalar \(k\), then transpose it, we need to demonstrate that this results in the same matrix as transposing \(A\) first and then multiplying the result by \(k\).
2Step 2: Know the definition of matrix transpose
Recall that the transpose of a matrix \(A\), denoted \(A^{\prime}\) or \(A^T\), involves flipping the rows and columns of \(A\). If \(A\) is an \(m \times n\) matrix, then \(A^{\prime}\) is an \(n \times m\) matrix.
3Step 3: Consider the scalar multiplication
Scalar multiplication \(kA\) involves multiplying each element of the matrix \(A\) by the scalar \(k\). If \(a_{ij}\) represents the element in the \(i^{th}\) row and \(j^{th}\) column of \(A\), then the corresponding element in \(kA\) is \(ka_{ij}\).
4Step 4: Perform the transposition on scaled matrix
When transposing the matrix \(kA\), which has elements \(ka_{ij}\), the resulting element in \((kA)^{\prime}\) at position \(j,i\) is also \(ka_{ij}\).
5Step 5: Transpose first and then scale
Consider the transpose of \(A\), denoted \(A^{\prime}\). The elements of \(A^{\prime}\) are \(a_{ji}\). When we multiply these elements by \(k\), the resulting elements in \(kA^{\prime}\) are \(k a_{ji}\), which are the same as those in \((kA)^{\prime}\).
6Step 6: Apply equivalence
Since both processes, transposing after scaling and scaling after transposing, give the same resulting matrix with elements \(k a_{ji}\), we conclude that \((kA)^{\prime} = kA^{\prime}\).
Key Concepts
Scalar MultiplicationMatrix AlgebraLinear AlgebraMatrix Properties
Scalar Multiplication
Scalar multiplication in the context of matrices is a fundamental operation in linear algebra. It involves taking each element of a matrix and multiplying it by a scalar (a real number). This is a straightforward process but an essential component in matrix operations.
- If you have a matrix \(A\) with elements \(a_{ij}\), multiplying by a scalar \(k\) involves changing each element to \(ka_{ij}\).
- This operation results in a new matrix that maintains the same dimensions as the original matrix.
Matrix Algebra
Matrix algebra is a branch of mathematics that deals with matrices and the operations that can be performed on them. The operations include addition, subtraction, scalar multiplication, and matrix multiplication. Each operation follows a set of rules and properties that can simplify solving matrix-related problems.
- Matrix addition involves adding corresponding elements of matrices with the same dimensions.
- Matrix multiplication is more complex and requires the multiplication of rows by columns, resulting in a new matrix.
Linear Algebra
Linear algebra is the study of vectors, vector spaces, and linear transformations. It uses matrices to understand these concepts, making it one of the cornerstones of modern mathematics. Linear algebra has applications in various fields, from computer science to economics.
- It introduces the concept of vector spaces, where matrices enable operations like transformations and projections.
- Linearity is key, ensuring that scaling and addition of vectors behave predictably.
Matrix Properties
Matrix properties are intrinsic characteristics that define how matrices behave under various operations. These properties help streamline calculations and ensure the consistency of results.
- One such property is transpose, which involves flipping a matrix over its diagonal, turning rows into columns and columns into rows.
- Another important property is the associative property of matrix multiplication, which states \((AB)C = A(BC)\).
- Furthermore, the distributive property \(A(B + C) = AB + AC\) applies, simplifying complex expressions.
Other exercises in this chapter
Problem 18
Eind the dot product of \(\mathbf{x}=[2,-3,1]^{\prime}\) and \(\mathbf{v}=[3,1,-2]^{\prime}\)
View solution Problem 18
In Problems , find \(\mathbf{x}+\mathbf{y}\) for the given vectors \(\mathbf{x}\) and \(\mathbf{y}\). Represent \(\mathbf{x}, \mathbf{y}\), and \(\mathbf{x}+\ma
View solution Problem 19
Show that if $$ a_{11} a_{22}-a_{21} a_{12} \neq 0 $$ then the system $$ \begin{array}{l} a_{11} x_{1}+a_{12} x_{2}=0 \\ a_{21} x_{1}+a_{22} x_{2}=0 \end{array}
View solution Problem 19
Use the dot product to compute the length of \([0,-1,2]^{\prime}\).
View solution