Problem 14
Question
Solve each of the inequalities and express the solution sets in interval notation. \(0.08 x+0.09(2 x) \geq 130\)
Step-by-Step Solution
Verified Answer
The solution in interval notation is \([500, \infty)\).
1Step 1: Distribute and Combine Like Terms
First, simplify the inequality by distributing the 0.09 across the terms inside the parentheses. This gives us:\[0.08x + 0.18x \geq 130\]Next, combine the like terms on the left side:\[0.26x \geq 130\].
2Step 2: Solve for x
To isolate \(x\), divide both sides of the inequality by 0.26:\[x \geq \frac{130}{0.26}\].Performing the division gives:\[x \geq 500\].
3Step 3: Express the Solution Set in Interval Notation
Since the inequality sign is \(\geq\), the solution includes 500 and all numbers greater than 500. Thus, the solution set in interval notation is:\[[500, \infty)\].
Key Concepts
Interval NotationDistributive PropertyCombining Like TermsSolving Linear Inequalities
Interval Notation
Interval notation is a very efficient way to represent a range of numbers along the number line. It's compact and easy to understand. In interval notation, we use brackets and parentheses:
Learning to express solution sets in interval notation helps to succinctly communicate which numbers satisfy an inequality.
- A square bracket "[" or "]" indicates that an endpoint is included in the interval. We call this "inclusive" notation.
- A parenthesis "(" or ")" shows that an endpoint is not included, known as "exclusive" notation.
Learning to express solution sets in interval notation helps to succinctly communicate which numbers satisfy an inequality.
Distributive Property
The distributive property is key to simplifying expressions involving parentheses. It allows you to multiply a single term by each term inside a parenthesis. In mathematical terms, for any numbers \( a \), \( b \), and \( c \), the property states:\[a(b+c) = ab + ac\]In the inequality \(0.08 x+0.09(2 x) \geq 130\), the distributive property helps us simplify:\(0.09(2x)\).
By distributing, we get \[0.09 \times 2x = 0.18x\].
Using the distributive property allows us to break down complex problems into simpler parts, making it a powerful tool in algebra.
By distributing, we get \[0.09 \times 2x = 0.18x\].
Using the distributive property allows us to break down complex problems into simpler parts, making it a powerful tool in algebra.
Combining Like Terms
Combining like terms is the process of adding or subtracting terms with the same variable part to simplify an expression. Like terms in an algebraic expression have exactly the same variables and exponents, though their coefficients can differ.
In our example:\(0.08x + 0.18x\), both terms feature the variable \(x\).
To combine them, we simply add their coefficients:\(0.08 + 0.18 = 0.26\). The simplified expression becomes:\(0.26x\).
By combining like terms, we effectively streamline the expression, making it easier to solve.
In our example:\(0.08x + 0.18x\), both terms feature the variable \(x\).
To combine them, we simply add their coefficients:\(0.08 + 0.18 = 0.26\). The simplified expression becomes:\(0.26x\).
By combining like terms, we effectively streamline the expression, making it easier to solve.
Solving Linear Inequalities
Solving linear inequalities involves finding which values of the variable satisfy the inequality condition. When solving the inequality:\(0.26x \geq 130\), we aim to isolate \(x\) on one side.
However, in this problem, multiplication and division are positive, so the inequality sign stays \(\geq\). Solving inequalities like this is similar to solving equations but requires careful attention to the inequality sign.
- The first step is to divide both sides by 0.26, yielding the expression: \(x \geq \frac{130}{0.26}\).
- Perform the division to get a numerical result: \(x \geq 500\).
However, in this problem, multiplication and division are positive, so the inequality sign stays \(\geq\). Solving inequalities like this is similar to solving equations but requires careful attention to the inequality sign.
Other exercises in this chapter
Problem 13
Solve each equation. \(-6 y-4=16\)
View solution Problem 14
Solve each inequality and graph the solutions. \(|x-2| \geq 1\)
View solution Problem 14
Express each interval as an inequalit using the variable \(x\). For example, we can express the inter val \([5, \infty)\) as \(x \geq 5\). \((-5, \infty)\)
View solution Problem 14
Solve each equation. \(0.07 x=152-0.08(2000-x)\)
View solution