Problem 14
Question
Solve each equation. \(0.07 x=152-0.08(2000-x)\)
Step-by-Step Solution
Verified Answer
The solution is \( x = 800 \).
1Step 1: Distribute the negative sign
We need to distribute the \( -0.08 \) across the terms inside the parentheses on the right side of the equation: \( 0.07x = 152 - 0.08 imes 2000 + 0.08x \)
2Step 2: Compute the multiplication
Calculate \( -0.08 imes 2000 = -160 \). The equation now becomes:\( 0.07x = 152 - 160 + 0.08x \)
3Step 3: Combine like terms on the right
Combine the constants on the right side: \( 0.07x = -8 + 0.08x \)
4Step 4: Move the variable to one side
Subtract \( 0.08x \) from both sides to get all terms involving \( x \) on one side of the equation:\( 0.07x - 0.08x = -8 \)
5Step 5: Simplify the equation
Combine the \( x \) terms: \( -0.01x = -8 \)
6Step 6: Solve for x
Divide both sides by \( -0.01 \) to solve for \( x \):\( x = \frac{-8}{-0.01} = 800 \)
Key Concepts
Distributive PropertyCombining Like TermsIsolation of Variables
Distributive Property
The distributive property is a crucial algebraic principle used to simplify expressions and solve equations. It involves distributing, or multiplying, a single term across terms within parentheses. The generic form of the distributive property is:
\( a(b + c) = ab + ac \). This means if you have a term outside the parenthesis, you multiply it with each term inside the parentheses.
In our example, we used this property to distribute the \( -0.08 \) across the terms in the expression
\( a(b + c) = ab + ac \). This means if you have a term outside the parenthesis, you multiply it with each term inside the parentheses.
In our example, we used this property to distribute the \( -0.08 \) across the terms in the expression
- \( -0.08 \times 2000 = -160 \)
- \( -0.08 \times (-x) = 0.08x \)
Combining Like Terms
Combining like terms simplifies mathematical expressions and equations. Like terms are terms that contain the same variable raised to the same power. For example, in the expression \( 3x + 5 + 2x -4 \), the like terms \( 3x \) and \( 2x \) can be combined to become \( 5x \), while the constants \( 5 \) and \( -4 \) become 1.
In the provided exercise, after applying the distributive property, we had the equation
In the provided exercise, after applying the distributive property, we had the equation
- \( 0.07x = 152 - 160 + 0.08x \).
This was further simplified by combining the constant terms \( 152 \) and \( -160 \), which resulted in \( -8 \).
This gives us the simplified equation of: - \( 0.07x = -8 + 0.08x \).
Isolation of Variables
Isolation of variables is a fundamental step when solving linear equations. The goal is to get the variable, typically denoted as \( x \), by itself on one side of the equation. This means rearranging the equation so that \( x \) is isolated, and all the other numbers are on the opposite side.
In the original problem, we started with
\( 0.07x = -8 + 0.08x \).
To isolate \( x \), we moved terms by subtracting \( 0.08x \) from both sides. This results in:
\( 0.07x - 0.08x = -8 \).
This simplifies to:
In the original problem, we started with
\( 0.07x = -8 + 0.08x \).
To isolate \( x \), we moved terms by subtracting \( 0.08x \) from both sides. This results in:
\( 0.07x - 0.08x = -8 \).
This simplifies to:
- \( -0.01x = -8 \)
- \( x = \frac{-8}{-0.01} = 800 \)
Other exercises in this chapter
Problem 14
Solve each of the inequalities and express the solution sets in interval notation. \(0.08 x+0.09(2 x) \geq 130\)
View solution Problem 14
Express each interval as an inequalit using the variable \(x\). For example, we can express the inter val \([5, \infty)\) as \(x \geq 5\). \((-5, \infty)\)
View solution Problem 14
Solve each equation. \(\frac{3 h}{4}+\frac{2 h}{5}=1\)
View solution Problem 14
Solve each equation. \(-8 y-2=18\)
View solution