Chapter 13
43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Chemistry · 72 exercises
Problem 29
Draw the stereochemical structures of the products in the following reactions: [1994-4 Marks] \(\mathrm{R}-\mathrm{C} \equiv \mathrm{C}-\mathrm{R} \frac{\mathrm{H}_{2}}{\text { Lindlar catalyst }}\)
3 step solution
Problem 30
How would you distinguish between 2 -butyne and 1-butyne.
5 step solution
Problem 31
Which of the following compounds will exhibit geometrical isomerism ? [2000S] (a) 1-Phenyl-2-butene (b) 3-Phenyl-1-butene (c) 2-Phenyl-1-butene (d) 1,1-Diphenyl-1-propene
4 step solution
Problem 31
A certain hydrocarbon \(A\) was found to contain \(85.7\) percent carbon and \(14.3\) per cent hydrogen. This compound consumes 1 molar equivalent of hydrogen to give a saturated hydrocarbon \(B .1 .00 \mathrm{~g}\) of hydrocarbon \(A\) just decolourized \(38.05 \mathrm{~g}\) of a 5 per cent solution (by weight) of \(\mathrm{Br}_{2}\) in \(\mathrm{CCl}_{4}\). Compound \(A\), on oxidation with concentrated \(\mathrm{KMnO}_{4}\), gave compound \(C\) (molecular formula \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}\) ) and acetic acid. Compound \(C\) could easily be prepared by the action of acidic aqueous mercuric sulphate on 2 - butyne. Determine the molecular formula of \(A\) and deduce the structure of \(A, B\) and \(C\).
6 step solution
Problem 32
anti-Markovnikoff addition of HBr is not observed in : [1985-1 Mark] (a) propene (b) 1-butene (c) but-2-ene (d) pent-2-ene
5 step solution
Problem 33
Baeyer's reagent is : (a) alkaline permanganate solution (b) acidified permanganate solution (c) neutral permanganate solution (d) aqueous bromine solution
4 step solution
Problem 34
Which of the following compounds will exhibit cis-trans (geometrical) isomerism? [1983] (a) 2-butene (b) 2 -butyne (c) 2-butanol (d) butanal
6 step solution
Problem 34
Write the structural formula of the major product in each of the following cases: (i) the compound obtained by the hydration of ethyne is treated with dilute alkali
5 step solution
Problem 35
Which of the following decolourises alkaline \(\mathrm{KMnO}_{4}\) solution (a) \(\mathrm{C}_{3} \mathrm{H}_{8}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{4}\) (c) \(\mathrm{CH}_{4}\) (d) \(\mathrm{CCl}_{4}\)
4 step solution
Problem 37
1 , 3-Butadiene with bromine in molar ratio of \(1: 1\) generates predominantly ...............
4 step solution
Problem 43
Which one of the following has the smallest heat of hydrogenation per mole? [1993 - 1 Mark] (a) 1-butene (b) trans-2-butene (c) cis -2-butene (d) 1,3 -butadiene
4 step solution
Problem 46
Assertion : Addition of \(\mathrm{Br}_{2}\) to 1 -butene gives two optical isomers. Reason : The product contains one asymmetric carbon.
6 step solution
Problem 47
An alkene (A) \(\mathrm{C}_{16} \mathrm{H}_{16}\) on ozonolysis gives only one product (B) \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}\). Compund (B) on reaction with \(\mathrm{NaOH} / \mathrm{I}_{2}\) yields sodium benzoate. Compound (B) reacts with \(\mathrm{KOH} / \mathrm{NH}_{2} \mathrm{NH}_{2}\) yielding a hydrocarbon (C) \(\mathrm{C}_{8} \mathrm{H}_{10}\). Write the structures of compounds (B) and (C). Based on this information, two isomeric structures can be proposed for alkene (A). Write their structures and identify the isomer which on catalytic hydrogenation \(\left(\mathrm{H}_{2} / \mathrm{Pd}-\mathrm{C}\right)\) gives a racemic mixture.
4 step solution
Problem 48
Complete the following reactions with appropriate structures of products/reagents. \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}=\mathrm{CH}_{2} \stackrel{\mathrm{Br}_{2}}{\longrightarrow}[\mathrm{A}]\) $$ \frac{\text { (i) } \mathrm{NaNH}_{2}(3.0 \text { equiv.) }}{\text { (ii) } \mathrm{CH}_{3} \mathrm{I}}[\mathrm{B}] $$
3 step solution
Problem 49
The hydrocarbon \(A\), adds one mole of hydrogen in the presence of a platinum catalyst to form \(n\)-hexane. When \(A\) is oxidized vigorously with \(\mathrm{KMnO}_{4}\), a single carboxylic acid, containing three carbon atoms, is isolated. Give the structure of \(A\) and explain.
4 step solution
Problem 50
Give the structures of the major organic products from3-ethyl-2pentene under each of the following reaction conditions. [1996 - 3 Marks] (a) HBr in the presence of peroxide (b) \(\mathrm{Br}_{2} / \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{Hg}(\mathrm{OAc})_{2} / \mathrm{H}_{2} \mathrm{O} ; \mathrm{NaBH}_{4}\)
4 step solution
Problem 51
An organic compound \(\mathbf{E}\left(\mathrm{C}_{5} \mathrm{H}_{8}\right)\) on hydrogenation gives compound \(\mathbf{F}\left(\mathrm{C}_{5} \mathrm{H}_{12}\right)\). Compound \(\mathbf{E}\) on ozonolysis gives formaldehyde and 2 ketopropanal. Deduce the structure of compound \(\mathbf{E}\).
4 step solution
Problem 52
1,4 -Pentadiene reacts with excess of \(\mathrm{HCl}\) in the presence of benzoyl peroxide to give compound \(X\) which upon reaction with excess of \(\mathrm{Mg}\) in dry ether forms \(Y\). Compound \(Y\) on treatment with ethyl acetate followed by dilute acid yields \(Z\). Identify the structures of compounds \(X, Y\) and \(Z\)
4 step solution
Problem 53
When gas \(A\) is passed through dry \(\mathrm{KOH}\) at low temperature, a deep red coloured compound \(B\) and a gas \(C\) are obtained. The gas \(A\), on reaction with but-2-ene, followed by treatment with \(\mathrm{Zn} / \mathrm{H}_{2} \mathrm{O}\) yields acetaldehyde. Identify A. B and C. [1994 - 3 Marksl
4 step solution
Problem 54
Identify, \(\mathbf{D}\left(\mathrm{C}_{6} \mathrm{H}_{12}\right)\), an optically active hydrocarbon which on catalytic hydrogenation gives an optically inactive compound, \(\mathrm{C}_{6} \mathrm{H}_{14}\)
5 step solution
Problem 55
Identify, \(\mathbf{B}\left(\mathrm{C}_{4} \mathrm{H}_{8}\right)\) which adds on HBr in the presence and in the absence of peroxide to give the same product, \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{Br}\).
1 step solution
Problem 58
Give reasons for the following : (i) Propene reacts with HBr to give isopropyl bromide but does not give \(n\) propyl bromide. [1983-1 Mark] (ii) The central carbon-carbon bond in 1,3 - butadiene is shorter than that in \(n\)-butane.
5 step solution