StudyQuestionHubStudyQuestionHub
TextbooksPhysicsUniversity Physics with Modern PhysicsChapter 27

Chapter 27

University Physics with Modern Physics · 51 exercises

Problem 90

The Electromagnetic Pump. Magnetic forces acting on conducting fluids provide a convenient means of pumping these fluids. For example, this method can be used to pump blood without the damage to the cells that can be caused by a mechanical pump. A horizontal tube with rectangular cross section (height \(h ,\) width \(w )\) is placed at right angles to a uniform magnetic field with magnitude \(B\) so that a length \(l\) is in the field (Fig. P27.90). The tube is filled with a conducting liquid, and an electric current of density \(J\) is maintained in the third mutually perpendicular direction. (a) Show that the difference of pressure between a point in the liquid on a vertical plane through \(a b\) and a point in the liquid on another vertical plane through \(c d ,\) under conditions in which the liquid is prevented from flowing, is \(\Delta p = J / B\) . (b) What current density is needed to provide a pressure difference of 1.00 atm between these two points if \(B = 2.20 \mathrm { T }\) and \(l = 35.0 \mathrm { mm } ?\)

4 step solution

Show/ page(51 total)
Previous
12
Next

Practice

  • SAT Questions
  • Practice Tests
  • Popular Questions

Resources

  • Textbook Solutions
  • Leaderboard

Company

  • About
  • Privacy
  • Terms

100.000+ bài giải textbook & 3.000+ câu SAT

Tất cả miễn phí! Lời giải chi tiết, hệ thống XP, huy hiệu và bảng xếp hạng giúp bạn luyện tập mỗi ngày.

Luyện SAT ngay →

© 2026 StudyQuestionHub. All rights reserved.

HomeSearchTextbooksBookmarksProfile
  • Home
  • Popular
  • Recent
  • Top Voted
  • Textbooks
  • Leaderboard
Filters